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    (Original post by nholliday95)
    For Core 1, for question 2)a)ii) the question asked x√12 = 7√3 - √48

    Did anybody else get 3/√4 as the value for X, or have I messed up? Thanks
    x√12= 7√3-√48
    x√12=7√3- 4√3
    x√12=3√3
    √12 = √4 x √3 = 2√3
    x(2√3) = 3√3
    x= 3/2. (1.5)
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    (Original post by Alifff)
    for x i got 3/2
    Oh yeah I just thought, 3/2 is exactly the same. Hopefully I won't get penalised for not turning the root 4 into 2.
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    A) Show p=3/2

    72=p96+q
    24=p24+q

    48=p72

    48/72= 2/3

    B) find u3

    72= 2/3*96 +q
    72=64 + q
    Q=8

    u3= 2/3*72 +q
    U3= 48 +q

    u3= 48 + 8
    = 56


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    For the second translation did anyone get Root((x-2)^3)+0.7)

    I thought the -2 had to be cubed with the x, and the -0.3 taken off the 1? But still in the root because its not actually with the x?

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    (Original post by nholliday95)
    Oh yeah I just thought, 3/2 is exactly the same. Hopefully I won't get penalised for not turning the root 4 into 2.
    haha its only one mark if that does happen and i think the grade boundaries would be lower as the paper was semi hard according to c1 standards
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    What was the proof for trig question at the end? I couldnt for the life of me do the last 2 parts on Q9
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    Did a resit of C1, paper wasn't too bad
    Can't remember the questions though.
    -Area question i got 27 for the final part.
    -x was 3/2 for the second question
    -the circle translation question. i put translation 6 to the right and 7 down, so (6,-7) in the square brackets (not too sure about this being correct)
    there was a question, express AB as 1/4√10
    Overall fairly confident i got over 95%, hoping for 100.
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    For Q1, p was -3, k = 10, D = (-7, -4).
    For the surds question, x = 1.5 and for part b the answer they were looking for was 8 - (15)^0.5.
    The complete the square question was 2(x+1.5)^2 + 0.5 and the length of AB was 0.5(10)^0.5.
    Dividing the polynomial by x+3 gave x^2 - 3x + 5.
    The integral was 31.5 or 63/2 and the area of the shaded region was 27.
    The point furthest away from the x-axis was (5, -14) and the translation was by vector (6, -7).
    The last question was 20/7 ( < or =) k (< or =) 4.
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    (Original post by nholliday95)
    For Core 1, for question 2)a)ii) the question asked x√12 = 7√3 - √48

    Did anybody else get 3/√4 as the value for X, or have I messed up? Thanks
    Nah, I got (√33)/2
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    (Original post by Equality4all)
    The last question was 20/7 ( < or =) k (< or =) 4.
    You only had to find the value of k not solve the inequality.

    The answer was k = (-20)/7 and k= 4
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    Also, for question 5)b)ii), it asked you to use the coordinates that we got from part a)ii) (-3,-13) or something I think,
    and find a minimum value putting it into 1/2√n

    any done that one? And did you get 1/2√100?
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    (Original post by Notorious544d)
    Same here, I was getting scared hearing 116 everywhere!

    Can anybody remember the question and the u1 and u2 values?

    Edit: I derived the u1 and u2 values by using u3 as 56 and I think u1 was 96 and u2 was 72.
    I put in 3/2 instead of 2/3 . Such a stupid mistake to make! How many marks will I lose? The question was just a two marker right?

    *sigh*
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    (Original post by Science211)
    You only had to find the value of k not solve the inequality.

    The answer was k = (-20)/7 and k= 4
    No it was not. It was a real roots question, so it asked you to solve the inequality to find the possible values for k. In addition, it was 20/7, not -20/7.
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    For the 2 to the power of k question, I actually got k = 2? Did anyone else get that?
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    (Original post by MajesticHippo)
    For the 2 to the power of k question, I actually got k = 2? Did anyone else get that?
    I think it was 6/5
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    (Original post by Alifff)
    I got those too
    I think people didnt realise that it was a trapezium.
    Area of that was (6+33)*3/2 ?


    Fairly sure that trapezium's aren't covered for Core 1. Pretty sure that they're introduced at Core 2.
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    (Original post by PatrickM)
    Fairly sure that trapezium's aren't covered for Core 1. Pretty sure that they're introduced at Core 2.
    Nah I thought that too until I did a past paper this morning before the exam and it came up, yet I still used the area of a triangle like on this paper annoyingly
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    In C1:

    was it

    (X-5)^2 + (Y+7)^2 = 49 >>>>>>>> (X+1)^2 + Y^2 = 49?

    or other way round?

    i got (-6 , 7)
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    (Original post by MajesticHippo)
    For the 2 to the power of k question, I actually got k = 2? Did anyone else get that?
    Ye I got that too K=2
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    (Original post by PatrickM)
    Fairly sure that trapezium's aren't covered for Core 1. Pretty sure that they're introduced at Core 2.
    The question in Core 1 involved using the area of a trapezium in the integration, but it wasn't a "trapezium rule" integration question(which is in Core 2, if I remember right) .
 
 
 
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