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    Yep. -2-root3 + i

    (Original post by bred123)
    Yeh i thought there was at first, because there was 2 positions of the plus and minus signs,
    but when you did all 4, 2 of them just converted into the opposite ones so it just came out with 2 of the same answers.




    This is what i had for the point of intersection. Did anyone get the same?
    edit: I knew I was right. Definitely only 2 solutions.
    I didn't complete the square I used a different method.
    Took 4 from both sides then took 5+12i to the other side
    then factorised the left (x-2)(x-2) = 5+12i
    so x was the square root of 5+12i + 2 (2 solutions)
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    Okay awesome thanks pal,
    that was the question i was wary about. I didnt originally put -2 until the last minute, i took it from the circles centre haha,

    Hope you and everyone has done great, bring on core 2 haha
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    (Original post by bred123)
    Okay awesome thanks pal,
    that was the question i was wary about. I didnt originally put -2 until the last minute, i took it from the circles centre haha,

    Hope you and everyone has done great, bring on core 2 haha
    Hope you've done well too. Bring on core 2 and D2 on the same day.. ^_^

    edit: remembered the equation
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    hahaha I actually managed to get the hard answers like 29, but for the loci bit I got the right point but I gave it as coordinates 😂😂😂 anyway did anybody get 1.25 for the summations one?
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    Yes

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    (Original post by Yeezus)
    hahaha I actually managed to get the hard answers like 29, but for the loci bit I got the right point but I gave it as coordinates 😂😂😂 anyway did anybody get 1.25 for the summations one?
    Yeah we all did - that was a nice question - I especially liked how there were three terms and the whole thing quite literally lived up to the expectation of it being a "telescope" method
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    (Original post by Wawasan)
    Yeah we all did - that was a nice question - I especially liked how there were three terms and the whole thing quite literally lived up to the expectation of it being a "telescope" method
    yup 1.25 XD
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    Can someone remember how many marks were for each question? We have a user generated mark scheme, but if anyone can remember, that would be really helpful!
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    Any grade boundary predictions?


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    (Original post by GM16)
    Any grade boundary predictions?

    I have a feeling the A boundary might be 60-63 ish. Just guessing though!
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    (Original post by Jamesb17_)
    I have a feeling the A boundary might be 60-63 ish. Just guessing though!
    I agree, I'm thinking about 60 for an A


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    Anyone know if arsey has bought out his solutions yet?
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    I got -(root3) + i
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    (Original post by JPerrin98)
    I got -(root3) + i
    your circle was also 2 negative x units from the origin!
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    (Original post by Parallex)
    your circle was also 2 negative x units from the origin!
    Very true
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    I did this too! Talk about throwing away marks! 😔
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    couldn't do the last one, couldn't do the quadratic one, messed up the matrices, got the wrong loci intercept, I'm gonna enjoy this U
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    (Original post by Parallex)
    29

    you got (a^2 + b^2 + y^2)^2) which was 64
    then took away 2(a^2b^2 + a^2y^2 + b^2y^2) which was 32

    64-32
    then refer to the original equation of x
    aby = -d/a = -3

32-3=29

    you couldn't use your equation in u to find aby because you had no way of deciding whether root 9 was -3 or +3, so refer to the original equation

    -d/a = -3/1 = -3

    32-3=29
    ah I ended up with -32 -3 = -35, shouldn't lose many marks for a sign error? Depends if my method was sound I guess
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    I did it right for 10 ii but had a carry on error from 10 i, and I didn't put much working. Do you need to show working if you get the right answer? Would I get all the marks for working?
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    (Original post by kamiokirby)
    I did it right for 10 ii but had a carry on error from 10 i, and I didn't put much working. Do you need to show working if you get the right answer? Would I get all the marks for working?
    E.c.f means you will get all the marks assuming you made no mistakes in the part of the question where you were going on a follow on error.
 
 
 
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