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    help with this question ppl
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    (Original post by docdoc02)
    help with this question ppl
    From the graph they have handily given you, you know that:

    a(x+b)=x
    and:
    

a(x+b)=-x

    Can you do the rest?
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    (Original post by Jai Sandhu)
    From the graph they have handily given you, you know that:

    a(x+b)=x
    and:
    

a(x+b)=-x

    Can you do the rest?
    why cant it be a(-x-b)=-x
    or a(-x-b)=x
    also i dont understand how they got b=0.25
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    (Original post by docdoc02)
    help with this question ppl
    Alternatively notice that it is just a transformation of y=|x|. You should be able to easily find b then, and then a.
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    (Original post by lizard54142)
    Alternatively notice that it is just a transformation of y=|x|. You should be able to easily find b then, and then a.
    Spoil sport stop stalking me. Btw, I was making reference to part 2
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    (Original post by Jai Sandhu)
    Spoil sport stop stalking me.
    I watch your every move.

    :cyber:
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    (Original post by lizard54142)
    Alternatively notice that it is just a transformation of y=|x|. You should be able to easily find b then, and then a.
    why is b=0.25 and not 0.5?
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    (Original post by docdoc02)
    why is b=0.25 and not 0.5?
    I don't get b as either of those... which past paper is this?
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    (Original post by lizard54142)
    I don't get b as either of those... which past paper is this?
    Yeah... I didn't get b=1/2 or 1/4, I thought I might have done something wrong but I am pretty confident in what I got.
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    (Original post by lizard54142)
    I don't get b as either of those... which past paper is this?
    oh sorry i meant a= 0.5 my bad, i got it right just didnt read the mark scheme properly, it was the june 2013 paper
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    (Original post by Jai Sandhu)
    Yeah... I didn't get b=1/2 or 1/4, I thought I might have done something wrong but I am pretty confident in what I got.
    sorry i meant a :/ but i didnt read the mark scheme properly
    why cant it be a(-x-b)=-x
    or a(-x-b)=x
    for the second part
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    Does anyone have june 2014 paper if yes please post
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    (Original post by docdoc02)
    sorry i meant a :/ but i didnt read the mark scheme properly
    why cant it be a(-x-b)=-x
    or a(-x-b)=x
    for the second part
    Look at the graph and the points at which the 2 lines intersect.
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    (Original post by docdoc02)
    help with this question ppl
    as it is a transformation of y=IxI, i think b=1 because f(x+1) is a translation of 1 unit to the left parallel to the x-axis, and A i think will be the degree to which the graph is stretched or squashed parallel to the y-axis in relation to the graph of y=IxI
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    (Original post by docdoc02)
    sorry i meant a :/ but i didnt read the mark scheme properly
    why cant it be a(-x-b)=-x
    or a(-x-b)=x
    for the second part
    It can, you've written the same thing as Jai did, just in a different way.

    (Original post by bapu_01)
    Does anyone have june 2014 paper if yes please post
    http://www.thestudentroom.co.uk/show...7#post56794477
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    [QUOTE=lizard54142;56853983]It can, you've written the same thing as Jai did, just in a different way.

    (Original post by Jai Sandhu)
    Look at the graph and the points at which the 2 lines intersect.
    thank you!
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    I appreciate the help from the previous question and im stuck on question 5. I understand to use the product rule but not the not until i have got the full differential equation and not simplified yet. after that i dont know how to get the result. thanks.
    http://www.mei.org.uk/files/papers/2011_June_c3.pdf
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    (Original post by Velocity_)
    I appreciate the help from the previous question and im stuck on question 5. I understand to use the product rule but not the not until i have got the full differential equation and not simplified yet. after that i dont know how to get the result. thanks.
    http://www.mei.org.uk/files/papers/2011_June_c3.pdf
    I don't understand what you've typed... this question is just an application of the product rule. Post your working?
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    you know when doing proofs you can say even number is 2x, odd number is 2x+1, what others are there e.g. A prime number?
    Because i really struggle on these
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    (Original post by Alevelstudent678)
    you know when doing proofs you can say even number is 2x, odd number is 2x+1, what others are there e.g. A prime number?
    Because i really struggle on these
    You cannot define a prime number like you would an even or odd number. Make sure you know how to prove \sqrt2 is irrational, or \sqrt3 is irrational etc...
 
 
 
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