Turn on thread page Beta
    Offline

    11
    ReputationRep:
    (Original post by a123a)
    Guys for the gradient questions I just want to clear something up.

    Say if the gradient is h+3 and as h tends to zero the gradient of the line PQ tends to the gradient of the curve at point P. Do we then have to say the gradient of the curve at point P is EQUAL to 3, or that gradient of curve at point P tends to 3?

    If someone could write a general answer for this I would much appreciate it.
    You say that the gradient equals the limit as h tends to 0, and that the limit as h tends to 0 = 3. e.g. m = Limh->0 (h + 3) = 3
    Offline

    5
    ReputationRep:
    (Original post by Lau14)
    You say that the gradient equals the limit as h tends to 0, and that the limit as h tends to 0 = 3. e.g. m = Limh->0 (h + 3) = 3
    Thank you!
    Oh ok so you can use that way of writing it?(writing 'Lim' with h tending to zero)?
    I've seen them write it as sentences in the mark schemes so I wasn't sure if I could write it like that.
    Offline

    11
    ReputationRep:
    (Original post by a123a)
    Thank you!
    Oh ok so you can use that way of writing it?(writing 'Lim' with h tending to zero)?
    I've seen them write it as sentences in the mark schemes so I wasn't sure if I could write it like that.
    Yeah, it's okay to use the shorthand and write Lim with h (arrow) 0 underneath it I think? At least, I've always used this method and my teachers mark it correct on mocks etc so I'd think it's okay, and I'm pretty sure I've seen it in markschemes before
    Offline

    5
    ReputationRep:
    (Original post by Lau14)
    Yeah, it's okay to use the shorthand and write Lim with h (arrow) 0 underneath it I think? At least, I've always used this method and my teachers mark it correct on mocks etc so I'd think it's okay, and I'm pretty sure I've seen it in markschemes before
    Ok thank you!
    Offline

    3
    ReputationRep:
    Could somebody help with this q? The sum of (r+17) from 1 to 25 is equal to the sum of r from P to Q.Find R and Q.So I worked out the the sum of r+17 is 1500, then I did:1500= 0.5p(p+1) - (0.5q^2 - 0.5q)But because there are 2 variables I am unable to solve..!I checked the answer and it matches my quadratic, but I don't know what the next step is... thanks
    Offline

    0
    ReputationRep:
    can anyone help me to answer a series question - jan 08 4b thanks!
    Offline

    0
    ReputationRep:
    also how do you draw the newton raphson diagram? The older mark schemes are so vague :/
    Offline

    11
    ReputationRep:
    (Original post by qpqpqpqpqp)
    also how do you draw the newton raphson diagram? The older mark schemes are so vague :/
    I agree. I think you draw a tangent at x1 and when the tangent crosses the x axis (x2) you go veritcally upwards/downwards to the curve and draw another tangent, and where that crosses the x axis will be x3. Youll notice you're getting closer to the root each time.
    Offline

    0
    ReputationRep:
    (Original post by Rabadon)
    I agree. I think you draw a tangent at x1 and when the tangent crosses the x axis (x2) you go veritcally upwards/downwards to the curve and draw another tangent, and where that crosses the x axis will be x3. Youll notice you're getting closer to the root each time.
    thanks! would you mind drawing an example so that i could see it?
    Offline

    11
    ReputationRep:
    (Original post by qpqpqpqpqp)
    thanks! would you mind drawing an example so that i could see it?
    http://imgur.com/bE97Qxi

    heres my paint effort lol
    Offline

    0
    ReputationRep:
    (Original post by Rabadon)
    http://imgur.com/bE97Qxi

    heres my paint effort lol
    thankyou that makes sense now!
    Offline

    11
    ReputationRep:
    (Original post by qpqpqpqpqp)
    thankyou that makes sense now!
    no problem, best of luck tomorrow
    Offline

    3
    ReputationRep:
    (Original post by azo)
    Could somebody help with this q? The sum of (r+17) from 1 to 25 is equal to the sum of r from P to Q.Find R and Q.So I worked out the the sum of r+17 is 1500, then I did:1500= 0.5p(p+1) - (0.5q^2 - 0.5q)But because there are 2 variables I am unable to solve..!I checked the answer and it matches my quadratic, but I don't know what the next step is... thanks
    Anybody ?
    Offline

    3
    ReputationRep:
    (Original post by azo)
    Anybody ?
    Could you screenshot the question instead? Not quite understanding what you are asking.
    Offline

    2
    ReputationRep:
    (Original post by qpqpqpqpqp)
    can anyone help me to answer a series question - jan 08 4b thanks!
    It's because from the form of part a) it the summation can be represented as 1/4*n(n+1)(n+4)(n-3), as n=1000, n+4=1004. Now to make sure that 2008 is a factor, just one other term needs to be even to make sure it is. And as 1000/4 is even then it shows that 2008 is a factor.
    Offline

    1
    ReputationRep:
    Which do you reckon is the hardest FP1 paper?


    Posted from TSR Mobile
    Offline

    11
    ReputationRep:
    (Original post by Fluffehadam)
    Which do you reckon is the hardest FP1 paper?


    Posted from TSR Mobile
    June 2013&2014 are tricky
    Offline

    0
    ReputationRep:
    can someone explain 7ciii for june 2014 - i got y=tan75x which is wrong but i don't understand the mark scheme?
    i did cos^-1(-root3/2) = 150 = 2 theta, so theta = 75?
    Offline

    3
    ReputationRep:
    (Original post by qpqpqpqpqp)
    can someone explain 7ciii for june 2014 - i got y=tan75x which is wrong but i don't understand the mark scheme?
    i did cos^-1(-root3/2) = 150 = 2 theta, so theta = 75?
    I've just done the same question and got the same thing
    Offline

    14
    ReputationRep:
    How are you guys revising? I finished all the papers from 2006 so kinda not knowing what to do atm


    Posted from TSR Mobile
 
 
 
Reply
Submit reply
Turn on thread page Beta
Updated: June 6, 2015

1,368

students online now

800,000+

Exam discussions

Find your exam discussion here

Poll
Should universities take a stronger line on drugs?

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reply
Hide
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.