Hey there! Sign in to join this conversationNew here? Join for free
    Offline

    0
    ReputationRep:
    Is anyone going to make an unofficial mark scheme?
    Offline

    14
    ReputationRep:
    (Original post by student199919)
    depending on what it's out of, maybe like 1/2 marks? what was the actual answer for the stretch one of 3^x-2?
    I put stretch parallel to y axis by factor 1/9 , since multiplying by 1/3^2 gives 3^(x-2)
    Offline

    2
    ReputationRep:
    I am gonna start an unofficial mark scheme - I think this is about correct!

    1i) 10cm (2m)

    1ii) 5.04cm (2m)

    2i) 3/10π (2m)

    2ii) 20.4cm (3m)

    3i) 27+27kx+9k^2x^2+k^3x^3 (4m)

    3ii) +/-√3 (2m)

    4i) log base 3 x^2/x+4 (2m)

    4ii) x=12 (4m)

    5a) x^4/2-x^3+2x^2-6x (3m)

    5bi) -6/a+2/a^2+4 (4m)

    5bii) 4 (1m)

    6i) k=91 (3m)

    6ii) Sum of terms = 978 (2m)

    6iii) N=38 (6m)

    7i) R=0, quotient = x^2-4x+3 (3m)

    7ii) (x+1), (x-1), (x-3) (3m)

    7iii) Prove (2m)

    7iv) 512/15 (4m)

    8i) Translation 2 units in positive x direction (2m)

    8ii) Stretch scale factor 1/9 in y direction (2m)

    8iii) Sketch, crosses y at (0,1/9) (2m)

    8iv) x=6.73 (3m)

    8v) Area =9.60 (3m)

    9i) 2π/a (1m)

    9ii) a=5/3 and k=√3/2 (3m)

    9iii) π/3a and ? (4m)
    Offline

    0
    ReputationRep:
    (Original post by _Orion_)
    What did people get for N with the arithmetic and geometric series?

    Posted from TSR Mobile
    Honestly did that so many times and persistently got that N > 0
    Offline

    1
    ReputationRep:
    (Original post by student199919)
    i think i got something like 38, i'm probably wrong
    I got 38 as well, i spoke to a few people and they got the same
    Offline

    5
    ReputationRep:
    (Original post by AlfieH)
    I am gonna start an unofficial mark scheme - I think this is about correct!

    1i) 10cm

    1ii) 5.04cm

    2i) 3/10π

    2ii) 20.4cm

    3i) 27+27kx+9k^2x^2+k^3x^3

    3ii) +/-√3

    4i) log base 3 x^2/x+4

    4ii) x=12

    5a) x^4/2-x^3+2x^2-6x

    5bi) -6/a+2/a^2+4

    5bii) 4

    6i) k=91

    6ii) Sum of terms = 978

    6iii) N=38

    7i) R=0, quotient = x^2-4x+3

    7ii) (x+1), (x-1), (x-3)

    7iii) Prove

    7iv) 512/15

    8i) Translation 2 units in positive x direction

    8ii) Stretch scale factor 1/9 in y direction

    8iii) Sketch, crosses y at (0,1/9)

    8iv) x=6.73

    8v) Area =9.60

    9i) Not sure - please add

    9ii) a=5/3 and k=√3/2

    9iii) Not sure - please add
    q9i 2pi/a
    9iii i think is pi/3a and 4pi/3a
    Offline

    0
    ReputationRep:
    3ii is wrong shouldn't it be k=0 and k=1/9
    Offline

    2
    ReputationRep:
    for 5bi) -6/a+2/a^2+4
    if i left it as -6a^-1 + 2a^-2 + 4 will any marks be deducted?

    and if i forgot to square and cube k in q3, do i lose a few marks or all?
    Offline

    2
    ReputationRep:
    (Original post by goharis123)
    3ii is wrong shouldn't it be k=0 and k=1/9
    They wanted coefficient of x^2 to equal the constant. The constant was 27 in this case so 9k^2=27 therefore k= +/- root 3.

    I think? Many others seemed to get this and it was only 2 marks. I may be wrong.
    Offline

    2
    ReputationRep:
    (Original post by czj1997)
    for 5bi) -6/a+2/a^2+4
    if i left it as -6a^-1 + 2a^-2 + 4 will any marks be deducted?

    and if i forgot to square and cube k in q3, do i lose a few marks or all?
    Nothing lost on 5bi.

    It was only 2 marks so probably dropped 2.
    Offline

    2
    ReputationRep:
    (Original post by sandpitturtle)
    q9i 2pi
    9iii i think is pi/3a and 4pi/3a
    What about the stretch in a? I think maybe it is 2pi/a?

    I got pi/3a as one solution but for some reason 2pi/3a for the other haha.
    Offline

    1
    ReputationRep:
    I got that k was + or - 1/3
    Offline

    5
    ReputationRep:
    (Original post by AlfieH)
    What about the stretch in a? I think maybe it is 2pi/a?

    I got pi/3a as one solution but for some reason 2pi/3a for the other haha.
    yeah thats right! sorry must've missed typing that but luckily i remember writing it for the exam
    and not sure about the last one really everyone got different things haha
    Offline

    0
    ReputationRep:
    (Original post by AlfieH)
    They wanted coefficient of x^2 to equal the constant. The constant was 27 in this case so 9k^2=27 therefore k= +/- root 3.

    I think? Many others seemed to get this and it was only 2 marks. I may be wrong.
    I think K was the constant and so 9k^2=k so
    9k^2-k =0 so k(9k-1)
    And so k=0 and k=1/9 I may be wrong I dont know
    Offline

    1
    ReputationRep:
    9ii) is 7π/a
    See working out in the attached photo

    Posted from TSR Mobile
    Offline

    5
    ReputationRep:
    (Original post by AlfieH)
    What about the stretch in a? I think maybe it is 2pi/a?

    I got pi/3a as one solution but for some reason 2pi/3a for the other haha.
    yeah 2pi/3a should be right, its amazing how quickly answers are forgotten after exams i have no idea if i put 2 or 4 on the top now
    Offline

    2
    ReputationRep:
    (Original post by sandpitturtle)
    yeah thats right! sorry must've missed typing that but luckily i remember writing it for the exam
    and not sure about the last one really everyone got different things haha
    My logic was first solution is π/3a therefor π-π/3a = 2π/3a...

    Probably wrong - only a mark at least.
    Offline

    2
    ReputationRep:
    Shall we put the mark scheme in Google Docs?

    https://docs.google.com/document/d/1...it?usp=sharing
    Offline

    7
    ReputationRep:
    Overall, i think the paper was fine, maybe apart from 9ii, which I did not manage to solve, but lost some stupid marks here and there. Think the grade boundaries will be around the same as usual, e.g. 58-59 for A
    Offline

    0
    ReputationRep:
    Does anyone know how many marks each question was to add to mark scheme?
 
 
 
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • Poll
    Brexit voters: Do you stand by your vote?
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

    Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

    Write a reply...
    Reply
    Hide
    Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.