Hey there! Sign in to join this conversationNew here? Join for free
    Offline

    3
    ReputationRep:
    Geometric:b) 256c) 1.201Binomial:A = 16k = 7/2B = 936Integration = 24.3Trapezium:a) 7b) 20.75c) R = 5.75Factor theorem:a) 5c) (x + 2)(3x + 2)(2x - 1)Differentiation(Q10):a) 2/3PIx^2d) Minimum = 120mc) x = 16.63... => f''(x) = 0.437 > 0 Trig identities:a) Theta = 8/15Pi , -2/15Pi b) x = 194.5, 345.5Circle:a) root(34)c) 3x + 5x - 95 = 0Log:i) (a - 5)/9ii) -2.19
    Offline

    0
    ReputationRep:
    (Original post by Leeteuk)
    it was absolutely nightmare
    *an absolute nightmare
    Offline

    0
    ReputationRep:
    (Original post by Hangk13)
    What did everyone get when substituting their x value into the 2nd differential to show it was a minimum point? (very last question part e)

    I got a really small decimal??
    i also got a decimal after defferentiating again , but as long as it was greater than 0 (which it was) this proves the value is a minimum
    Offline

    14
    ReputationRep:
    can someone put up a link to arseys solution
    Offline

    3
    ReputationRep:
    Any mark scheme up?
    Offline

    1
    ReputationRep:
    (Original post by marshmellow:))
    2^(2x+5) laws of indices allow you to rewrite this as (2^5)(2^2x). Then as 2^2x= (2^x)^2 so this bit equals y^2. So you get 2^5 lots of y which is 32y^2.
    awesome thanks,

    so you get 32y^2 -7y=0, and then solve like a regular old equation.

    y(32y-7)=0

    y=0
    y=7/32
    so then 2^x=0
    and also 2^x=7/32

    log(base2) (0) cant be done
    so log(base2)(7/32)=x
    Offline

    0
    ReputationRep:
    (Original post by Shqipron)
    When does BTEC maths start?
    haha you're dumb
    Offline

    2
    ReputationRep:
    (Original post by adso222)
    Any mark scheme up?
    http://www.thestudentroom.co.uk/show...3#post65151283 Mine
    Offline

    14
    ReputationRep:
    (Original post by TheBillPN)
    awesome thanks,

    so you get 32y^2 -7y=0, and then solve like a regular old equation.

    y(32y-7)=0

    y=0
    y=7/32
    so then 2^x=0
    and also 2^x=7/32

    log(base2) (0) cant be done
    so log(base2)(7/32)=x
    yes that's what I did
    Offline

    1
    ReputationRep:
    Awesome, i've been looking through the mark schemes people are talking about and i'm pretty sure ive got everything else right, so 71/74 for me!
    Offline

    2
    ReputationRep:
    (Original post by TheBillPN)
    Awesome, i've been looking through the mark schemes people are talking about and i'm pretty sure ive got everything else right, so 71/74 for me!
    link
    Offline

    0
    ReputationRep:
    (Original post by marshmellow:))
    can someone put up a link to arseys solution
    He isn't putting solutions up, here is the link for his reasons
    http://www.thestudentroom.co.uk/show...rimary_content
    Offline

    2
    ReputationRep:
    [QUOTE=Lairyfliquid;65149165]that was rough. Couldn't do any of 9 and parts of 6- does anyone know if a mark scheme is coming up soon?
    question 6 a. was not easy it was by far the hardest question on the paper but to be expected as most of the other questions were fairly simple the last question could definitely make those who lack knowledge of the properties of geometric shapes slip up as it requires prior knowledge of area formulas and the fact that all 3 angles of an equilateral triangle are 60 whoever managed to do the last question clearly has solid understanding of certain topics and was able to interpret the question fully.
    Offline

    0
    ReputationRep:
    (Original post by mcfatty)
    how did we find it all?

    like the differentiation question?

    It was absolutely horrible. Didn't get that question at all. I ended up getting a negative number for the minimum!!! What do u need for a C ??
    Offline

    0
    ReputationRep:
    (Original post by hi x)
    haha you're dumb
    No he's not. He's a legend.
    #banter
    #friendsforlife
    Offline

    1
    ReputationRep:
    aww there's not gonna be an arsey mark scheme

    http://www.thestudentroom.co.uk/show...ighlight=arsey
    Offline

    0
    ReputationRep:
    does anyone remember what question "1c)" was asking?
    Offline

    1
    ReputationRep:
    Listen Jumana, it was the easiest C2 paper in recent years so do not insult Edexcel in this inappropriate manner. Your revision was a disaster darling.
    Offline

    0
    ReputationRep:
    (Original post by X_IDE_sidf)
    My answers:

    1 b) (2 marks) 256
    c) (2 marks) 1.602

    2 a) (1 mark) 7
    b) (3 marks) 20.75
    c) (2 marks) 5.75

    3 a) (2 marks) \sqrt{34}
    c) (4 marks) 3x+5y-95=0

    4 a) (2 marks) 5
    b) (2 marks) f(-2)=0
    c) (4 marks) f(x)=(x+2)(3x+2)(2x-1)

    5 a) (4 marks) 16-288x+1944x^2
    b) (1 mark) 16
    c) (2 marks) \frac{7}{2}

    d) (2 marks) 936

    6 i) (3 marks) \frac{8\pi}{15}or \frac{-2\pi}{15}

    ii) (6 marks) 345.5$^{\circ}$ or 194.5$^{\circ}$

    7 b) (3 marks) 24.3

    8 ii) (4 marks) -2.19

    9 a) (2 marks) \frac{\pi x^2}{3}
    d) (5 marks) x=16.63 P= 120m
    c) (2 marks)  f''x = 0.437

    my unofficial mark scheme
    Note that question 6) ii) , had 3 values, original value for x was -14.4 but you also get 14.4. You may want to check that.
    Offline

    2
    ReputationRep:
    (Original post by daria99)
    Note that question 6) ii) , had 3 values, original value for x was -14.4 but you also get 14.4. You may want to check that.
    it was 0 -360 range
 
 
 
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • Poll
    Would you like to hibernate through the winter months?
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

    Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

    Quick reply
    Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.