2016 May 25th Edexcel Core 2 Questions and answers. [Unofficial mark scheme] 2016 Watch

SLamb
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#81
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#81
(Original post by UKoE Luna)
Awesome Thanks for clearing that up I wasn't quite sure if I was just allowed to remove the logs like that.
Yup! Any like terms on either side can be simply cancelled out, regardless of whether it's powers, logs, trigonometric functions etc etc
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X_IDE_sidf
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#82
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(Original post by maddywalde)
Hi guys

if i put 5y + 3x - 95 = 0, will i still get the mark even though it said put it as 'ax + by + c = 0'?
yes
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maddywalde
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#83
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(Original post by X_IDE_sidf)
yes
nice one thanks friend
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Guèpard
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I don't know how i got higher on C2 its weird because I thought C1 would be easier. :hmmmm:
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X_IDE_sidf
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(Original post by Guèpard)
I don't know how i got higher on C2 its weird because I thought C1 would be easier. :hmmmm:
Having done C1, C2, C3, C4, S1 and S2 I found C1 the hardest. This is because of the scope for mental maths error.
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TheProKi
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(Original post by obeyyy)
any idea what the grade bondaries might be
It was harder than last years so hopefully around 59-62 for an A and 52-55 for B
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Kholmes1
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#87
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Can someone explaon how you got part c for question one? I jist tried it now and I got 4.8 but im sure in the exam I got different.

Also the radius for tje circle. I completely forgot the formula so I tried completing the square for which I got like 10.6/ 113
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X_IDE_sidf
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(Original post by Kholmes1)
Can someone explaon how you got part c for question one? I jist tried it now and I got 4.8 but im sure in the exam I got different.

Also the radius for tje circle. I completely forgot the formula so I tried completing the square for which I got like 10.6/ 113
u_n=ar^{n-1}
\therefore |u_9-u_{10}| = |(64)(\frac{3}{4})^{9-1}-(64)(\frac{3}{4})^{10-1}| = 1.602 (3 d.p.)
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Kholmes1
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(Original post by X_IDE_sidf)
u_n=ar^{n-1}
\therefore |u_9-u_{10}| = |(64)(\frac{3}{4})^{9-1}-(64)(\frac{3}{4})^{10-1}| = 1.602 (3 d.p.)
Oh god, I just realised that I did the sum formula. Idk how, i just did.
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LeFatOaf
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Not sure how everyone else found it, I smashed it, 74/75 according to the unofficial mark scheme. Thankfully got a lot of time to revise S1 now XD
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bulletman54
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(Original post by X_IDE_sidf)
u_n=ar^{n-1}
\therefore |u_9-u_{10}| = |(64)(\frac{3}{4})^{9-1}-(64)(\frac{3}{4})^{10-1}| = 1.602 (3 d.p.)
dont you get negative 1.602 so if you wrote -1.602 as the difference is it wrong
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TheProKi
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(Original post by bulletman54)
dont you get negative 1.602 so if you wrote -1.602 as the difference is it wrong
Lol it doesn't matter, they will most likely ignore the sign, they just told you to find the difference its like saying if i had 5 apples one day and had 10 the next day what would be the difference in the amount of apples i had in those 2 days it wont be -5 but just 5 but the minus i think they will ignore so you will get full marks.
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TheProKi
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#93
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Guys do you think 59-61 will be an A as last year it was 59 for an A and it was pretty easy compared to this.
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bulletman54
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(Original post by TheProKi)
Lol it doesn't matter, they will most likely ignore the sign, they just told you to find the difference its like saying if i had 5 apples one day and had 10 the next day what would be the difference in the amount of apples i had in those 2 days it wont be -5 but just 5 but the minus i think they will ignore so you will get full marks.
Safe G was worried about that
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TheOnlyAngel
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(Original post by Qweudhs56)
1.b. Is wrong. The answer is -1.602. It has to be negative because in geometric sequence, the biggest term is subtract by the smallest.

Therefore 64(3/4)^9 - 64(3/4)^8 = -1.602 (to three decimal places).

P.S. I don't know if the markscheme would say 'ignore' signs.

I've seen a similar past paper question and it does say ignore signs, i also got negative.
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Sam53
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9 d) is wrong, x was a really long decimal. If you used the full decimal you would have got 121.5... Something rounding up to 122. You are not supposed to round x as that is too early.

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Hasib98
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(Original post by dididid)
the answer was b= (3a+5)/9

I swear b= (a-5)/9 ??
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Hasib98
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(Original post by Verdahf)
Do you know how many marks this part was for?
this was deffo b=(a-5)/9

unless im mistaken because i just did it again
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X_IDE_sidf
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Name:  sdafaefa.PNG
Views: 99
Size:  95.9 KBHere is the 1 b equivalent from 2006

(Original post by Sam53)
9 d) is wrong, x was a really long decimal. If you used the full decimal you would have got 121.5... Something rounding up to 122. You are not supposed to round x as that is too early.

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No, you are wrong, please re-check.
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X_IDE_sidf
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#100
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http://www.thestudentroom.co.uk/atta...1&d=1464204940 <-- NEW PDF. This is V2 and has been layed out in a more stylish manner and has Q 9c corrected

Edit: to satisfy my ocd, the real scanned paper will be hitting shelves soon.
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