Mr M's OCR (not OCR MEI) Core 2 Answers May 2016 Watch

bluegirl64
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Can someone pls go through q 6(iii)?
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Mr M
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#82
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(Original post by 2807)
I somehow managed to add 5 instead of 4 onto the end of 5bi, so therefore wrote the sum to infinity as 5, how many marks will I drop?
You'll drop 1 mark. You won't be penalised twice.
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Mr M
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#83
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(Original post by Devkj)
And would i get any marks for saying stretch by scale factor 9 parallel to the y axis, i accidentally did the stretch the opposite way round.
1 mark
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RomeoSantos
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#84
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How many marks would i lose marks for 9i) 360/a and 9iii) 60/a and 240/a ??
Silly mistakes
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Mr M
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#85
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(Original post by Saching99)
If a = 5/3 as said before, ive done all the same working, surely id get 2 or 3 out of 4? i solved the trig equation exactly right
If your working is right you'll get some credit.
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Mr M
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(Original post by RomeoSantos)
How many marks would i lose marks for 9i) 360/a and 9iii) 60/a and 240/a ??
Silly mistakes
You might only lose 1 in total if they are kind.
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Saching99
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if for 3ii , we used 3 from (3+kx) as the constant instead of 27 and got +-1/rt3 do we drop both or jsut one
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GcseLad-_-
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Hi sir, for 3ii, I equted the coeffeicent to k the constant and not the constant term, how many marks would i get if any? My solutions were 0 and 1/9 by the way.
Also for 9ii I got root 3/2 for k which is correct but got a is equal to 10/3?
Finally for 9iii i said that the period of tan was pi/a and also wrote "pi/a -x1=x2" and said xq and xw were the solutions. After that o did tan -1 root3 and got pi/3 and 4pi/3 but did not relate them to ax at all, how many dropped?
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Nikita_2313
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(Original post by Mr M)
Mr M's OCR (not OCR MEI) Core 2 Answers May 2016


1. (i) 10 cm (2 marks)

(ii) 5.04 cm (2 marks)


2. (i) \displaystyle \frac{3 \pi}{10} (2 marks)

(ii) r=20.4 (3 marks)


3. (i) \displaystyle 27 +27kx+9k^2x^2 +k^3x^3 (4 marks)

(ii) k=\pm \sqrt{3} (2 marks)


4. (i) \displaystyle \log_3 \frac{x^2}{x+4} (2 marks)

(ii) x = 12 (4 marks)


5. (a) \displaystyle \frac{x^4}{2} -x^3 +2x^2-6x+k (3 marks)

(b) (i) \displaystyle \frac{2}{a^2} - \frac{6}{a} + 4 (4 marks)

(ii) 4 (1 mark)


6. (i) k=91 (3 marks)

(ii) \displaystyle S_{16} = 978 (2 marks)

(iii) N=38 (6 marks)


7. (i) Quotient x^2-4x+3 and remainder 0 (3 marks)

(ii) x=1 or x=-1 or x=3 (3 marks)

(iii) Show (2 marks)

(iv) \displaystyle \frac{512}{15} (4 marks)


8. (i) Translation by 2 units in the positive x direction (2 marks)

(ii) Stretch parallel to the y axis scale factor \displaystyle \frac{1}{9} (2 marks)

(iii) Sketch showing (0, \frac{1}{9}) as the only point of intersection (2 marks)

(iv) x=6.73 (3 marks)

(v) 9.60 (3 marks)


9. (i) \displaystyle \frac{2 \pi}{a} (1 mark)

(ii) \displaystyle a=\frac{5}{3} and \displaystyle k=\frac{\sqrt{3}}{2} (3 marks)

(iii) \displaystyle x=\frac{\pi}{3a} and \displaystyle x=\frac{4 \pi}{3a} (4 marks)


Sorry guys I made a mess of 9(ii) at the start - I didn't notice k had to be positive. It's right now.

If in question 7iv i got the right answer 512/15, but then proceeded to make it into a mixed number, but did it incorrectly, would I lose a mark? I did not cross out 512/15
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Mia122333
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(Original post by Mr M)
Mr M's OCR (not OCR MEI) Core 2 Answers May 2016


1. (i) 10 cm (2 marks)

(ii) 5.04 cm (2 marks)


2. (i) \displaystyle \frac{3 \pi}{10} (2 marks)

(ii) r=20.4 (3 marks)


3. (i) \displaystyle 27 +27kx+9k^2x^2 +k^3x^3 (4 marks)

(ii) k=\pm \sqrt{3} (2 marks)


4. (i) \displaystyle \log_3 \frac{x^2}{x+4} (2 marks)

(ii) x = 12 (4 marks)


5. (a) \displaystyle \frac{x^4}{2} -x^3 +2x^2-6x+k (3 marks)

(b) (i) \displaystyle \frac{2}{a^2} - \frac{6}{a} + 4 (4 marks)

(ii) 4 (1 mark)


6. (i) k=91 (3 marks)

(ii) \displaystyle S_{16} = 978 (2 marks)

(iii) N=38 (6 marks)


7. (i) Quotient x^2-4x+3 and remainder 0 (3 marks)

(ii) x=1 or x=-1 or x=3 (3 marks)

(iii) Show (2 marks)

(iv) \displaystyle \frac{512}{15} (4 marks)


8. (i) Translation by 2 units in the positive x direction (2 marks)

(ii) Stretch parallel to the y axis scale factor \displaystyle \frac{1}{9} (2 marks)

(iii) Sketch showing (0, \frac{1}{9}) as the only point of intersection (2 marks)

(iv) x=6.73 (3 marks)

(v) 9.60 (3 marks)


9. (i) \displaystyle \frac{2 \pi}{a} (1 mark)

(ii) \displaystyle a=\frac{5}{3} and \displaystyle k=\frac{\sqrt{3}}{2} (3 marks)

(iii) \displaystyle x=\frac{\pi}{3a} and \displaystyle x=\frac{4 \pi}{3a} (4 marks)


Sorry guys I made a mess of 9(ii) at the start - I didn't notice k had to be positive. It's right now.
Hi 2ii) I got 21. Something I laid it out correctly ie 2r + r3/5 pi then = but then divided by 3/5pi and got wrong answer?
For 9ii) I got a = 5 how many marks if any do you think I will get?
And 7iv) I integrated between 3 and -1 but didn't get the correct answer think I just put in my calculator wrong but showed my method??
9iii) I got tan ax then substituted my a value from previous question which i didn't read the question?
How many marks do you think I got from them if any? And do you think 60 will b a A?

Thanks
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Mr M
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(Original post by Nikita_2313)
If in question 7iv i got the right answer 512/15, but then proceeded to make it into a mixed number, but did it incorrectly, would I lose a mark? I did not cross out 512/15
It's fine to have a mixed number. We tend not to ever use them after GCSE.
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Nikita_2313
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(Original post by Mr M)
It's fine to have a mixed number. We tend not to ever use them after GCSE.
Yes, but if I converted it INCORRECTLY into a mixed number, would I lose a mark, provided that i did not cross out the correct top-heavy fraction answer?
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Mr M
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#93
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(Original post by Mia122333)
For 9ii) I got a = 5 how many marks if any do you think I will get?
And 7iv) I integrated between 3 and -1 but didn't get the correct answer think I just put in my calculator wrong but showed my method??

How many marks do you think I got from them if any? And do you think 60 will b a A?

Thanks
9ii) I made that mistake first time! You might get 1 mark.

7iv) Drop 1 or 2.

I don't guess boundaries.
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Mtjk
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#94
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How many marks would you get if you put k=1/9
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Psraim
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#95
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(Original post by Mr M)
Mr M's OCR (not OCR MEI) Core 2 Answers May 2016


1. (i) 10 cm (2 marks)

(ii) 5.04 cm (2 marks)


2. (i) \displaystyle \frac{3 \pi}{10} (2 marks)

(ii) r=20.4 (3 marks)


3. (i) \displaystyle 27 +27kx+9k^2x^2 +k^3x^3 (4 marks)

(ii) k=\pm \sqrt{3} (2 marks)


4. (i) \displaystyle \log_3 \frac{x^2}{x+4} (2 marks)

(ii) x = 12 (4 marks)


5. (a) \displaystyle \frac{x^4}{2} -x^3 +2x^2-6x+k (3 marks)

(b) (i) \displaystyle \frac{2}{a^2} - \frac{6}{a} + 4 (4 marks)

(ii) 4 (1 mark)


6. (i) k=91 (3 marks)

(ii) \displaystyle S_{16} = 978 (2 marks)

(iii) N=38 (6 marks)


7. (i) Quotient x^2-4x+3 and remainder 0 (3 marks)

(ii) x=1 or x=-1 or x=3 (3 marks)

(iii) Show (2 marks)

(iv) \displaystyle \frac{512}{15} (4 marks)


8. (i) Translation by 2 units in the positive x direction (2 marks)

(ii) Stretch parallel to the y axis scale factor \displaystyle \frac{1}{9} (2 marks)

(iii) Sketch showing (0, \frac{1}{9}) as the only point of intersection (2 marks)

(iv) x=6.73 (3 marks)

(v) 9.60 (3 marks)


9. (i) \displaystyle \frac{2 \pi}{a} (1 mark)

(ii) \displaystyle a=\frac{5}{3} and \displaystyle k=\frac{\sqrt{3}}{2} (3 marks)

(iii) \displaystyle x=\frac{\pi}{3a} and \displaystyle x=\frac{4 \pi}{3a} (4 marks)


Sorry guys I made a mess of 9(ii) at the start - I didn't notice k had to be positive. It's right now.
For question 7iv, how many marks would I lose for doing (153/5) + (53/5) instead of (153/5) + (53/15) ?
And for question 9iii how many marks would I lose for pia/3 and 4pia/3 instead of pi/3a and 4pi/3a?
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Mr M
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#96
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(Original post by bluegirl64)
Can someone pls go through q 6(iii)?
\displaystyle \sum_{n=1}^{\infty} W_n = 1200

\displaystyle \frac{N}{2}(2a+(N-1)d)>1200

Let a = 5 and d = 1.5 and solve.
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Mr M
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#97
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(Original post by Nikita_2313)
Yes, but if I converted it INCORRECTLY into a mixed number, would I lose a mark, provided that i did not cross out the correct top-heavy fraction answer?
Your marker will drop the code ISW onto your script to mean ignore subsequent working.
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Mr M
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#98
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(Original post by Saching99)
if for 3ii , we used 3 from (3+kx) as the constant instead of 27 and got +-1/rt3 do we drop both or jsut one
Drop both.
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Csd1999
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#99
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For the original log question i) I got it down to log3(x^2) -log3(x+4) but I stupidly simplified to log3(x/x+4) so obviously I carried that through to part ii which then gave me a wrong answer.. How many marks would likely I get out of 6?
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Nikita_2313
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(Original post by Mr M)
Your marker will drop the code ISW onto your script to mean ignore subsequent working.
Does that mean I will not lose any marks?
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