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    (Original post by NikitaPond)
    For the abba question, what did people do? I think I put the wrong numbers into the calculator, but my method was:
    3/7 * 2/6 * 2/5 * 1/4 (picking the letters AABB).
    There are 6 ways to arrange AABB, so multiply by 1/6. This gets 1/420. I think then multiply by 4! as it does not matter what order we pick the cards from the initial 7.
    I done wjat u done but only multiplied by 4 at the end instead of 4!
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    (Original post by toosie)
    I got 0.0864 because either Marie fails twice and nadia succeeds twice (0.8^2*0.3^2) or Marie scores, nadia scores, Marie fails, nadia scores (0.8*0.2*0.3^2) or Marie fails nadia scores Marie scores nadia scores (same thing) so it's (0.8^2*0.3^2) +2(0.8*0.2*0.3^2).
    This seems correct actually
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    (Original post by Ozil5)
    How were you meant to work out the total output for the year?
    I did an arithmetic progression with a being 17.6 and d being 0.6 comes to like 200 and something
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    (Original post by madberry1)
    I did an arithmetic progression with a being 17.6 and d being 0.6 comes to like 200 and something
    You calculated the mean value of n in the previous question and the mean is given by mean = (sum of n) / n(12) so to find the sum of n you multiply the mean by n
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    (Original post by Ozil5)
    How were you meant to work out the total output for the year?
    I just found the sum of z using the mean of z and n=12
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    (Original post by Ozil5)
    How were you meant to work out the total output for the year?
    I did the mean output times by 12
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    (Original post by Ozil5)
    How were you meant to work out the total output for the year?
    I did the mean for x multiplied by 12. Forgot what i got though
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    (Original post by ukgjyhtrhv)
    i got 0.0864 for the last one
    me too
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    (Original post by rektron)
    You calculated the mean value of n in the previous question and the mean is given by mean = (sum of n) / n(12) so to find the sum of n you multiply the mean by n
    But z was the output
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    (Original post by madberry1)
    But z was the output
    I'm sorry, I meant the mean of z!
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    (Original post by duncant)
    Mean of apples was kike 146.5 and variance was 21.75. Sum on m2 was 1117168.
    how did you work out the sum of m^2?
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    Does anyone else think that was one of the easiest papers out of all the past exams?
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    What did everyone get for the group of 12 question. I got 166320 i think.
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    (Original post by madberry1)
    I did an arithmetic progression with a being 17.6 and d being 0.6 comes to like 200 and something
    yh i got something like 250.8 i think
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    can we make a markscheme?
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    I got 1/70 for the ABBA question??
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    What did people get for the question where it said what is the p of X equaling each other and how did you do it
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    (Original post by catwat99)
    I got 1/70 for the ABBA question??
    same, but my first answer was 12/35 idk
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    (Original post by student199919)
    yh i got something like 250.8 i think
    Same, just did ((1x0.6 + 17)) + ((2x0.6 + 17))...... and i think i got that.
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    (Original post by catwat99)
    I got 1/70 for the ABBA question??
    So did I 🙌🙌
 
 
 
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