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    In that answer we are supposed to identify the oxidising agent in the reaction so we habe to look for the entity that has undergone reduction i.e a decrease in the oxidation state NaIO3 or even IO3^1- is acceptable
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    June 2014 IAL Q1 b please!
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    i have a question if anyone can help me plz

    which of the following has the largest number of lone pairs
    CH2=O
    CH3Cl
    CH3NH2
    CH3OH
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    (Original post by mr.holmes)
    i have a question if anyone can help me plz

    which of the following has the largest number of lone pairs
    CH2=O
    CH3Cl
    CH3NH2
    CH3OH
    First compund has 2
    Second compound has 3
    Third compound has 1
    Last compound has 2
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    can someone explain why it changes to colourless
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    Bromine water test
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    (Original post by AlvlVictim)
    Bromine water test
    Thanks
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    (Original post by mh99)
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    can someone explain why it changes to colourless
    It is cyclopentENE, which means that it has carbon carbon double bond. The pi bond in the double bond breaks and the bromine is added to the organic compound. If all the bromine reacts, there is no bromine solution left so the original colour (brown) turns to colourless.
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    can someone explain it
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    (Original post by mh99)
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    can someone explain it
    The equation of calcium hydroxide is Ca(OH)2 so there is one calcium ion and two Hydroxide ions which add up to 3.

    In OH ion, you have 8 electrons from the oxygen, 1 electron from hydrogen, and 1 electron from calcium which add up to 10.
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    (Original post by omar5478)
    The equation of calcium hydroxide is Ca(OH)2 so there is one calcium ion and two Hydroxide ions which add up to 3.

    In OH ion, you have 8 electrons from the oxygen, 1 electron from hydrogen, and 1 electron from calcium which add up to 10.
    i get the first part b (i)
    but i don't get the second part,
    if you get 8 electrons from oxygen and one electron form hydrogen where does calcium come into this if it OH-? should it be 2 electrons from hydrogen atom??
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    Hey guys how was the exam? I found it ok.. What was the last answer?
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    Hey guys , how did it go? I too found it ok.
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    What did you write for the product of water with Cl2O7 .
    And in the mcq which gave a peak at m/e value 31
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    (Original post by Becka99)
    What did you write for the product of water with Cl2O7 .
    And in the mcq which gave a peak at m/e value 31
    Had no idea about the Cl2O7 thing,
    the m/e was for 31 was the first option(can't remember what is was tho)
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    (Original post by wenogk)
    Had no idea about the Cl2O7 thing,
    the m/e was for 31 was the first option(can't remember what is was tho)
    I think it was propan-01-ol but how did you get it....like which fragment gives that?
    But yaaaaaaaay our exams are over...
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    (Original post by Becka99)
    What did you write for the product of water with Cl2O7 .
    And in the mcq which gave a peak at m/e value 31
    I think it was 2HClO4
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    (Original post by Becka99)
    I think it was propan-01-ol but how did you get it....like which fragment gives that?
    But yaaaaaaaay our exams are over...
    Lucky 10 more days to go.. Oh yeah then the formula would be CH3CH2CH2OH and the last bit CH2OH gives 31, (12+1+1+16+1)=31.
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    (Original post by sumanamalik10)
    I think it was 2HClO4
    Same

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    The paper was tough considering how high the boundary for A has been in recent years

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