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# AQA MM1B - Mechanics 1 -Tuesday 21st June 2016 Watch

1. (Original post by PiTheta97)
My answers, no idea how many are right:

Question 1 (Momentum)

0.4m/s
15kg

Question 2 (Particles/Vectors)

P=14
Q=-17

(16i-8j)

Question 3 (Toy Car on Slope)

1.5ms^2
1.8m/s

Question 4 (Airplane)

V = 12m/s
Resultant = 90.8m/s
008°

Question 5 (Connected Particles)

3.92ms^-2
2.50m/s
1.12m

Question 6 (Cleaning Device at 60°)

Tsin60+5g
T=43.8N

Question 7 (Football Projectile)

1.76s
13.6m
13.2m/s
No air resistance

Question 8 (Helicopters)

80.5m

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On Q6 for the tension I got 30.0N and not 43.8N but I'm not sure if I'm right, and on the angle question on Q3 I got 5 degrees or something.
2. (Original post by MLW12345)
Magic that's what I got ended up using that data for the next questions though, probably got bearing wrong around 007deg
I did the same thing, got 007 too
3. (Original post by Chickenslayer69)
On Q6 for the tension I got 30.0N and not 43.8N but I'm not sure if I'm right
I got 30N as well
4. (Original post by RUNSran)
I got the same answers as you apart no 8what do you think think garde boundaries will bw?
Not sure, 55 for an A?

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5. (Original post by gcooney4)
For the modelling assumption [1] I thought it was about air resistance but even a particle would have air resistance so I wrote that the ball cannot stretch and reaches the edges of the box and can't bounce off or tip into the box it can only land exactly on the edge
Its no rotation/spin.
6. What did everyone do to find the angle of the slope in the toy car question.

I used conservation of energy to find the height then used trig to find the angle. I got the same answer as everyone else, but conservation of energy wasnt on the spec. Will i still get the marks
7. I got 106m for the 10 marker, anyone else?
8. For Q 8, I got t= 12. I subbed in and found the s of A and B, then subtracted to find the displacement of B from A, then used pythagoras. I got around 106m. Anyone else?
9. (Original post by fffffg1g1)
anyone get something like 106m for q8?
Yep
10. Anyone else get 119 ish for Q8?
11. (Original post by fffffg1g1)
anyone get something like 106m for q8?
Yes
12. My answers (might have misremembered some, and others are probably wrong):
1) 15 kg
2) p = 14, q = 17
3) 9 degrees
4) V = 12, bearing = 008
5) Max heigh 1.2 m (can't really remember)
6) 43.8 N
7) Velocity around 13, modelling as particle means air resistance can be ignored)
8) I got up to finding t = 5 and t = 25, but then did a load of meaningless BS and got the wrong answer around 28 lol.
13. (Original post by PiTheta97)
Not sure, 55 for an A?

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I would personaly put the grade boundries higher but then again i did mechanics last year too so i dont really know
14. (Original post by matt5822)
Yes
my g
15. (Original post by Chickenslayer69)
On Q6 for the tension I got 30.0N and not 43.8N but I'm not sure if I'm right, and on the angle question on Q3 I got 5 degrees or something.
exactly the same apart from P as 2 root 5 and q as 7i and 67.8 on the last question
16. I got 160 for q8. At t 25 the j components were the same hence parallel then expanded using s=Ut+1/2at^2. Then square the difference
17. (Original post by Examguy123)
What did everyone do to find the angle of the slope in the toy car question.

I used conservation of energy to find the height then used trig to find the angle. I got the same answer as everyone else, but conservation of energy wasnt on the spec. Will i still get the marks
I hope so, because I'm pretty sure at one point I differentiated velocity to find acceleration
18. (Original post by gcooney4)
For the modelling assumption [1] I thought it was about air resistance but even a particle would have air resistance so I wrote that the ball cannot stretch and reaches the edges of the box and can't bounce off or tip into the box it can only land exactly on the edge
Modelling anything as a particle disregards size though, surely there's no air resistance

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19. (Original post by smitherito)
I got 160 for q8. At t 25 the j components were the same hence parallel then expanded using s=Ut+1/2at^2. Then square the difference
But the i components were different
20. I got 106 too. Tan X = j/I then X must be the same for both, as parallel, t= 12, then answer 106.

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