Turn on thread page Beta
    Offline

    12
    ReputationRep:
    (Original post by TeeEm)
    Xtreme?

    never heard of them..
    where did you get them?
    https://www.dropbox.com/sh/oz0s4m3nf...a/Core/C3?dl=0

    Just in the link from PhysicsMathstutor... perhaps they go by a different name?
    Offline

    14
    ReputationRep:
    (Original post by Artfanatic)
    https://www.dropbox.com/sh/oz0s4m3nf...a/Core/C3?dl=0

    Just in the link from PhysicsMathstutor... perhaps they go by a different name?
    LOL!

    Posted from TSR Mobile
    Offline

    2
    ReputationRep:
    Hahaha they are the IYGB ones


    Posted from TSR Mobile
    Offline

    3
    ReputationRep:
    Guys iv never really understood CAST diagrams. I've always only used the formulae. Should I try learn them now?
    Offline

    2
    ReputationRep:
    (Original post by MissC123)
    Guys iv never really understood CAST diagrams. I've always only used the formulae. Should I try learn them now?
    I would recommend carrying on with what your using now. What might be beneficial is familiarising yourself with the graphs


    Posted from TSR Mobile
    Offline

    2
    ReputationRep:
    (Original post by MissC123)
    Guys iv never really understood CAST diagrams. I've always only used the formulae. Should I try learn them now?
    Well if you've been fine without out them, then there's no reason to learn them. However if you are having trouble then make sure to learn it, there's nothing complicated about them and you should be able to get the hang of them instantly. Check out the videos about them on examsolutions.
    Offline

    19
    ReputationRep:
    (Original post by Artfanatic)
    https://www.dropbox.com/sh/oz0s4m3nf...a/Core/C3?dl=0

    Just in the link from PhysicsMathstutor... perhaps they go by a different name?
    yes, they are my papers ...
    they are called IYGB
    extreme, my Name:  5.jpg
Views: 86
Size:  224.7 KB
    Offline

    3
    ReputationRep:
    Just about finished the solomon papers and have a couple of questions before Friday:

    What are the chances of one of these: "Prove, by counter-example, that the statement “ln(3x2 + 5x + 3) ≥ 0 for all real values of x” is false." sort of proof questions coming up?

    Also when you demonstrate change of sign to prove a root lies in a particular interval is it important to mention that the function is continuous as they do in the solomon mark schemes? Thanks!
    Offline

    16
    ReputationRep:
    when talking about the root, how exactly do you word it? do you just write "there's a sign change, therefore root = (insert root here)"
    I'm always unsure on what to write.... can anyone clarify for me? thanks
    Offline

    2
    ReputationRep:
    Teem are you sitting this exam


    Posted from TSR Mobile
    Offline

    2
    ReputationRep:
    (Original post by danlocke)
    Just about finished the solomon papers and have a couple of questions before Friday:

    What are the chances of one of these: "Prove, by counter-example, that the statement “ln(3x2 + 5x + 3) ≥ 0 for all real values of x” is false." sort of proof questions coming up?

    Also when you demonstrate change of sign to prove a root lies in a particular interval is it important to mention that the function is continuous as they do in the solomon mark schemes? Thanks!
    (Original post by Bustamove)
    when talking about the root, how exactly do you word it? do you just write "there's a sign change, therefore root = (insert root here)"I'm always unsure on what to write.... can anyone clarify for me? thanks


    Mark scheme from an Edexcel paper: http://i.imgur.com/Fxnjm75.png

    As you can see they put the continuous function in brackets, all you have to put as conclusion is: change of sign, therefore root at X for the final mark
    Offline

    16
    ReputationRep:
    (Original post by Anon-)
    Mark scheme from an Edexcel paper: http://i.imgur.com/Fxnjm75.png

    As you can see they put the continuous function in brackets, all you have to put as conclusion is: change of sign, therefore root at X for the final mark
    ah i see... would I need to say that root is in between ae(2.3585,2.3595) or do i just go straight and say a=2.359?

    (referring to the link you sent me, sorry I can't do the symbols above, so i just used letters which look similiar)
    Offline

    3
    ReputationRep:
    (Original post by Anon-)
    Mark scheme from an Edexcel paper: http://i.imgur.com/Fxnjm75.png

    As you can see they put the continuous function in brackets, all you have to put as conclusion is: change of sign, therefore root at X for the final mark
    Perfect, thanks.
    Offline

    2
    ReputationRep:
    Does anyone know how to derive factor formulae? On page 125 it says:

    sin(A+B) + sin(A-B) = 2sinAcosB
    Let A+B = P and A-B = Q

    Then A=(P+Q)/2 and B = (P-Q)/2
    This is the part i dont get.. How does A and B equal that?

    Shouldnt A = P-B and B = A-Q?
    Posted from TSR Mobile
    Offline

    1
    ReputationRep:
    (Original post by it's a me, mario)
    Does anyone know how to derive factor formulae? On page 125 it says:

    sin(A+B) + sin(A-B) = 2sinAcosB
    Let A+B = P and A-B = Q

    Then A=(P+Q)/2 and B = (P-Q)/2
    This is the part i dont get.. How does A and B equal that?

    Shouldnt A = P-B and B = A-Q?
    Posted from TSR Mobile
    You get simultaneous equations here so when you add them, you get:

    P+Q= (A+B)+(A-B)
    P+Q= 2A
    A= (P+Q)/2

    When you minus them you get:

    P-Q= (A+B)-(A-B)
    P-Q= 2B
    B= (P-Q)/2
    Offline

    2
    ReputationRep:
    (Original post by it's a me, mario)
    Does anyone know how to derive factor formulae? On page 125 it says:

    sin(A+B) + sin(A-B) = 2sinAcosB
    Let A+B = P and A-B = Q

    Then A=(P+Q)/2 and B = (P-Q)/2
    This is the part i dont get.. How does A and B equal that?

    Shouldnt A = P-B and B = A-Q?
    Posted from TSR Mobile
    You shouldn't have to worry about it. It says nothing about factor formulae in our specification.
    Offline

    2
    ReputationRep:
    (Original post by Lochy99)
    You get simultaneous equations here so when you add them, you get:

    P+Q= (A+B)+(A-B)
    P+Q= 2A
    A= (P+Q)/2

    When you minus them you get:

    P-Q= (A+B)-(A-B)
    P-Q= 2B
    B= (P-Q)/2
    Aaah, i get it now. Thanks :yy:

    Posted from TSR Mobile
    Offline

    2
    ReputationRep:
    (Original post by Anon-)
    You shouldn't have to worry about it. It says nothing about factor formulae in our specification.
    Are you sure? No wonder it's never come up on a past paper :dontknow:

    Posted from TSR Mobile
    Offline

    21
    ReputationRep:
    (Original post by it's a me, mario)
    Are you sure? No wonder it's never come up on a past paper :dontknow:

    Posted from TSR Mobile
    I asked that question before couple days ago when I finished recapping C3 theory.

    I did x12 past papers for my C3 mock back in December and never came across it. I'm assuming it's not on our specification. The same with modulus with inequalities.
    Offline

    2
    ReputationRep:
    (Original post by it's a me, mario)
    Are you sure? No wonder it's never come up on a past paper :dontknow:

    Posted from TSR Mobile
    It's worth knowing because this did come up on a past paper I've done recently but I can't remember which one
 
 
 
Turn on thread page Beta
Updated: June 21, 2016

University open days

  • Heriot-Watt University
    School of Textiles and Design Undergraduate
    Fri, 16 Nov '18
  • University of Roehampton
    All departments Undergraduate
    Sat, 17 Nov '18
  • Edge Hill University
    Faculty of Health and Social Care Undergraduate
    Sat, 17 Nov '18
Poll
Have you ever experienced bullying?

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reply
Hide
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.