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# Edexcel S1 - 15th June, 2016 [Exam Discussion] watch

1. (Original post by gracebromby)
I got 17 lol
I got 17 too because-

The given data tells us that there are 4 babies in the class ( 2w<3) with Width=1 Height=2.
Therefore,
2x1 = 2 cm^2
So
4/2= 2 (babies represented by each cm^2)

We can also tell that Each cm (width) represents 1 kg.

The class we are interested in finding the width and height of ( 3w<3.5)-
Given 17= babies
17/2= 8.5 cm^2

Because Each cm (width) represents 1 kg, and our width is now 0.5 kg, the Width must be 0.5 cm.

Therefore,
8.5/0.5= 17 cm (Height)

Anyone else agrees with this?
2. (Original post by anndz3007)
For the diner question, do people add .405 and .450 and multiply by 77 or you find P( D intersect B interect R) add P( D intersect R intersect B' , i tried the second method and got 30 something but when i check up the diagram, the area of t is not counted, so i crossed it out and do the first method and got 68, im just so confused
There were 77 people, but 40 were B and R, and 37 were B and not R. You do P(D|R intersect B) * 40 and P(D|R intersect not B) * 37. Then add those two values together. You end up with 33.
3. (Original post by Ppatel0)
Omdz I mean the other way round but I can't remember the exact number of people they gave
Yeah, I got 33 too.

Although I believe it was (40 * 0.45) + (37 * 15/37) = 18 + 15 = 33
4. (Original post by tazza ma razza)
well q4 was hard. Otherwise reckon I got 68/69+

boundaries for 100, 90, 80 UMS?

I think
71+ for 100
67+ for 90
56+ for 80
I'm thinking I got 64-68 ish, dunno. First solid A though, which is good news

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5. (Original post by moshe015)
Anyone get 0.65 for sarah and 0.2 for rebecca?

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Yeah i did but i recon i was wrong😂😂😂
6. (Original post by CourtlyCanter)
I got 17 too because-

The given data tells us that there are 4 babies in the class ( 2w<3) with Width=1 Height=2.
Therefore,
2x1 = 2 cm^2
So
4/2= 2 (babies represented by each cm^2)

We can also tell that the Each cm (width) represents 1 kg.

The class we are interested in finding the width and height of ( 3w<3.5)-
Given 17= babies
17/2= 8.5 cm^2

Because Each cm (width) represents 1 kg, and our width is now 0.5 kg, the Width must be 0.5 cm.

Therefore,
8.5/0.5= 17 cm (Height)

Anyone else agrees with this?
I agree, I did the exact same thing
7. I'm confused about how UMS works, if I get around 20 marks, I know that's a U but does that mean 0 UMS?
8. (Original post by X_IDE_sidf)
Disagree with d i) ()
My phone won't let me old half of your reply but here's why it was 0.45 and 15/37

The probability of D given BnR is the proportion of BnRnD in BnR. Since from the diagram we can see BnRnD= 0.27 and BnR = 0.6, the answer is 0.27/0.6 which gives 0.45

For probability of D given RnB' you do the same again. The total of RnB' is 0.15+0.22 = 0.37
The portion of Rn'B which is also D is 0.15, hence the answer is 0.15/0.37 which is 15/37. This is definitely right because in the next question you use the fraction to work out that 15 out of 37 people have dinner at the hotel when they order a room but no breakfast.

EDIT; I've spotted a couple of mistakes in your working. Firstly, P(Dn(RnB)) = 0.27, not 0.42, as it is the area in which all three circles intersect. Secondly, P(RnB) is 0.6, not 0.97. This is because RnB means the area inside B which is also inside R, which happens to be all of it (0.6). You've taken only the probability of R by the looks of it.
9. I got 0.36 for the last one, anyone else?

Easy paper

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10. Imo this paper was harder than last year's, I redid this module and I preferred last year's paper
11. (Original post by Bloom77)
I got 0.36 for the last one, anyone else?

Easy paper

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Yeah I think that's what most people got.

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12. When the extra value was added the pmcc would of moved closer to 0 right?
13. (Original post by hbaig27)
If we got P and Q wrong, is the rest of the question wrong (Error carried forward) or will they give us method marks? This is for the Rebecca and Sara Q
also wondering this.
what did you get for p and q, out of interest?
14. Yeah
15. (Original post by Princepieman)
I'm thinking I got 64-68 ish, dunno. First solid A though, which is good news

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Well in Prince! Excellent stuff - no doubt if we both found it to be harder than expected, than boundaries will reflect and echo that Btw didn't realise you did edexcel - I'll PM you later this afternoon.
I'm confused about how UMS works, if I get around 20 marks, I know that's a U but does that mean 0 UMS?
no, if you got a U your UMS will be somewhere between 0 and 40
17. (Original post by anna096)
only 2, dont stress
18. Did anyone get 0.680 for the standard deviation (where mean = 3.43) and 0.254 for the normal distribution question at the end of question 5? Some people seem to have similar answers but I might have got rounding errors.

Also, what was the effect of the new data on the PMCC for question 3?
19. (Original post by fredhutchings)
no, if you got a U your UMS will be somewhere between 0 and 40
Ok brilliant thanks a lot

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