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    Name:  ImageUploadedByStudent Room1465919833.201290.jpg
Views: 358
Size:  61.4 KB This was the answer to the last question.. (I got it wrong and drew it as a tertiary alcohol:/
    The integration value of 6 with the CH3 included the one on the left..)
    How many marks would I loose for tertiary alcohol? I'd imagine 1 for not mentioning it having to be primary or secondary, 1 for wrong product and 2 probably for an error in my working that showed a segment of R-C(CH3)2OH..
    So most likely -3/4 what do you think?


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    Desperately need to see a copy of the paper, I've blanked out that stitches question and can't remember what i wrote. Were there two questions about medical applications or just one? that paper has wrecked my head hahaha
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    (Original post by Anam)
    Wait so i got a cl* radical in my fragmentation equation is that wrong as i used ch2ocl+ as my fragment ion as it adds up to 65 too
    There may be different answers, but from my notes this should work:

    [ClCH2COCl]+* -> [COCl]+ (37Cl) + [ClCH2]* (35 Cl)
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    I highly doubt for the isomer question you had to put which isotope of Cl you used for that question on the equation for splitting the isotope. Questions like that have come up before - the only reason they specify is to allow you to work out the structure, which is what the question was assessing. Typically the three marks available would be fore 1) the structure of the molecular ion radical (whether you remembered to put the positive and radical signs), 2) For the structure of the fragment ion, and 3) For the structure of the remaining radical
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    (Original post by _newbe)
    I got that!!
    no because then all your peaks would be singlets
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    (Original post by Cadherin)
    I put AgNO3. If acidified, no marks.

    Acidificed AgNO3 would work for the halogenoalkanes. However, if you don't acidify it, the acyl chloride would show a white precipitate and the Cl bonded directly to a methyl group wouldn't.
    you can acidity it because acidifying it gets rid of in wanted ions if you put NaOH with AgNO3 that would of been no marks as they give the same the result
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    Damn That Exam was solid
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    CH3-O-CH2-CH2-C(OH)(CH3)2
    Did anyone else get this
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    (Original post by j5994)
    someone please make an unofficial markscheme or post pictures of the paper coz i need to know how many marks i need in CHEM5 to bring my grade up to an E :'(
    THIS MADE ME LAUGH .....mostly because I am in the same situation :cry2:
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    For the 6 mark Buffer question, did anyone get a pH of 4.56???

    I subtracted moles of OH- added from the salt concentration, not sure if its right
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    surely for the suture one they have to allow both biodegradable so it can dissolve and that permanent dipole dipole means its stronger because both are an advantage and also, how are you to know that a stitch that dissolves is better when I've done a 2 year chem course not the 5 year med course im hoping to do doing after
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    for the acyl chloride you can say h20 cant you?
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    (Original post by clarkey500)
    :beer: So is mine!!!
    At least I've met (well spoken to) another Harry Clarke!
    You're going to tell me your born in May or Bristol next!
    Unfortunately, no hahaha
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    (Original post by cowie)
    Name:  ImageUploadedByStudent Room1465919833.201290.jpg
Views: 358
Size:  61.4 KB This was the answer to the last question.. (I got it wrong and drew it as a tertiary alcohol:/
    The integration value of 6 with the CH3 included the one on the left..)
    How many marks would I loose for tertiary alcohol? I'd imagine 1 for not mentioning it having to be primary or secondary, 1 for wrong product and 2 probably for an error in my working that showed a segment of R-C(CH3)2OH..
    So most likely -3/4 what do you think?


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    I swear it was a tertiary alcohol? If you look at this, this was 7 hydrogen environments, whereas there were only 5 peaks, indicating 5 hydrogen environments, which the tertiary alcohol had. In any case, I have seen questions like this on OCR, so even if you get the structure wrong, you only lose 1 mark - they want to see how you work it out, not whether or not you reach the answer, so so long as you wrote out all your workings you'll still get like 8 marks
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    (Original post by Capsicle102)
    I highly doubt for the isomer question you had to put which isotope of Cl you used for that question on the equation for splitting the isotope. Questions like that have come up before - the only reason they specify is to allow you to work out the structure, which is what the question was assessing. Typically the three marks available would be fore 1) the structure of the molecular ion radical (whether you remembered to put the positive and radical signs), 2) For the structure of the fragment ion, and 3) For the structure of the remaining radical
    But it said in the question to specify which isotope you've used on the structures
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    (Original post by Jojojuice)
    Yeah I got 9 too!! Pretty sure it's right because I checked it like 3 times
    Was 9 the second box?
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    Why is lidocaine hydrochloride rather than lidocaine preferred to be used in medicine? Like wow
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    (Original post by OloMed)
    For the 6 mark Buffer question, did anyone get a pH of 4.56???

    I subtracted moles of OH- added from the salt concentration, not sure if its right
    Good one😂


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    (Original post by Cadherin;[url="tel:65771023")
    65771023[/url]]Lidocaine I seem to remember?
    Yup youre right!! Sh** >;(((((
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    (Original post by Capsicle102)
    I swear it was a tertiary alcohol? If you look at this, this was 7 hydrogen environments, whereas there were only 5 peaks, indicating 5 hydrogen environments, which the tertiary alcohol had. In any case, I have seen questions like this on OCR, so even if you get the structure wrong, you only lose 1 mark - they want to see how you work it out, not whether or not you reach the answer, so so long as you wrote out all your workings you'll still get like 8 marks
    no it was either a secondary or primary alcohol.
 
 
 
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