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    (Original post by Tizzydag)
    any predictions on possible questions/topics
    Tbh theres no point looking for predictions but Binomial theorem, Factor/remainder theorem, Logarithms, Differentiation/Integration and Trig identities has come up in all the papers since 2009 and that's pretty much majority of C2 revise everything!
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    (Original post by Olon)
    https://c4a3f001dcd45afe69d0ceec8300...%20Edexcel.pdf

    Q5
    and q7b If you can help me

    and q9.a
    Q5

    the normal of the gradient of PQ = gradient of QR

    7b the angles lies on a full turn and the two sides are symmetrical so 2pi -2.2/2

    q9 a - geometric sequences you divide the previous term so 2k-15/k = k/(k+4)
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    Btw. If you are one of those people like me who gets work done quickly but makes mistakes, do the entire thing again. Like, start each question from scratch and make sure that the answers are the same. Do the question as if you haven't seen it before.

    If you don't have time to do it again, go over part a to a question or something, if you lose that mark then you may lose more marks if you've used that answer again.

    But please don't do it again unless you've finished the first go-over.
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    Name:  Screen Shot 2015-05-19 at 18.40.09.png
Views: 188
Size:  23.4 KBPLEASE SOMEONE HELP ME WITH THE FOLLOWING QUESTION::
    (ALSO i need explanation as to why)

    JANUARY 2013 QUESTION 4 ii)
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    (Original post by El-Presidente)
    Most Universities don't care about your AS grades, unless they are astonished by a BBC suddenly becoming predicted A*A*A* they will only act on your predicted grades. They don't care about resists or anything, they will just assume.
    no, but your AS grades determine your predicted grades dont they
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    Could we be asked to prove the Sn formula, it's in the textbook
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    (Original post by physicsmaths)
    unis don't care about AS grades? Lol OK.


    Posted from TSR Mobile
    Yes, that's the case. Then again - you missed out the most bit. They look at your predications, not your AS.
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    (Original post by El-Presidente)
    Wait what?

    a(1-r^n)? What is this? Isn't that the top half of the sum formula?

    It is always ar^n-1 isn't it? What's this greater than less than 1 stuff.
    Lool yes that's the top half of the sum formula but what I was saying was that if the common ratio is less than one then you would use the formula provided however if the common ratio is greater than 1 then you would use a(r^n-1)/r-1

    Hope this cleared the confusion!
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    (Original post by LikeASomebody)
    Could we be asked to prove the Sn formula, it's in the textbook
    Yes we can, I saw it on a paper I did the other day. It's not likely though!

    Write out

    Sn = a
    rSn = ar

    Sn - rSn = a - ar
    Sn(1- r) = a(1 - r^n)

    Therefore,

    Sn = (a(1-r^n))/(1-r)

    ^ Something like that
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    (Original post by LikeASomebody)
    Could we be asked to prove the Sn formula, it's in the textbook
    Yes its worth 4 marks
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    (Original post by El-Presidente)
    Yes, that's the case. Then again - you missed out the most bit. They look at your predications, not your AS.
    Lol
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    (Original post by physicsmaths)
    Lol
    Hmmm... you were the one who called a poor soul a retard earlier, no doubt with that attitude you'll be aiming for Cambridge or Oxford. Am I right?
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    (Original post by Haych97)
    Yes its worth 4 marks
    Oh bloody hell! I have a feeling that this may be asked tomorrow!
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    Anyone done IYGB S and T?

    Posted from TSR Mobile
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    (Original post by starkers1997)
    Oh bloody hell! I have a feeling that this may be asked tomorrow!
    Its really simple! Just practice writing it out now and it'll stick in your head :yes:

    Posted from TSR Mobile
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    (Original post by studentwiz)
    Q5

    the normal of the gradient of PQ = gradient of QR

    7b the angles lies on a full turn and the two sides are symmetrical so 2pi -2.2/2

    q9 a - geometric sequences you divide the previous term so 2k-15/k = k/(k+4)
    Thanks. I'm struggling to understand what you mean for q7b, maybe if you could say it in a simpler way
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    (Original post by falloutboyyy)
    Name:  Screen Shot 2015-05-19 at 18.40.09.png
Views: 188
Size:  23.4 KBPLEASE SOMEONE HELP ME WITH THE FOLLOWING QUESTION::
    (ALSO i need explanation as to why)

    JANUARY 2013 QUESTION 4 ii)
    never seen a question like this before but i think you have to factorise it and then it becomes the same as part 1) but just using y instead of x, leading to expanding the brackets and gathering like terms
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    (Original post by Olon)
    Thanks. I'm struggling to understand what you mean for q7b, maybe if you could say it in a simpler way
    a full circle is 2pi so you take away 2.2 from what is already on the diagram, then whats left of the circle is 2 lots of DAC which you need so to find DAC its essentially 0.5(2pi-2.2)
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    You need to know how to proove Fermat's Last Theorem also
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    (Original post by starkers1997)
    Oh bloody hell! I have a feeling that this may be asked tomorrow!
    It's pretty simple..i haven't seen it since a 2005/06 paper not sure which one so I would watch out for it...the link below explains it clearly

    https://www.youtube.com/watch?v=xfzcUkcLXXA
 
 
 
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