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    (Original post by 13 1 20 8 42)
    To be honest the hardest C4 paper I know of is probably last year's which wasn't exactly mind-blowing
    You could go on TeeEm's IYGB thread; the papers are certainly more suitable than Solomon and they are hard
    Thank you


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    (Original post by raypalmer)
    Cheers pal


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    no worries

    read instructions and all about difficulty rating in
    http://madasmaths.com/archive_iygb_p...ce_papers.html
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    (Original post by kaya_lioness)
    Danke.I tried that But in the mark scheme they use the value of x=0.1 and placed that into the expansion.
    I get it now - we cant just solve for x as x is greater than 8/9 which means the expansion would not be valid. Hence we go for x=0.1 as this means we can manipulate the expansion to get a cubed root of 7100. Sneaky Q imo

    EDIT: just realised someone above has pointed this out.
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    (Original post by Gilo98)
    :rofl: it is my life goal to find a flaw in your wealth of resources Just a quick check though, would it simply be

    



\pi\displaystyle\int x^2\frac{dy}{dt}\ dt
    Where limits are in terms of t and found using the values of y given in Q. apologies for poor formatting above, first time using LaTex

    Be sure to quote me with the Q!!
    This can't come up, right?
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    (Original post by Gilo98)
    I get it now - we cant just solve for x as x is greater than 8/9 which means the expansion would not be valid. Hence we go for x=0.1 as this means we can manipulate the expansion to get a cubed root of 7100. Sneaky Q imo

    EDIT: just realised someone above has pointed this out.
    This question is very strange, in the mark scheme it says cubed root 7100 = 10 x cubed root 71, but i tried this in my calculator and they are not the same
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    (Original post by 13 1 20 8 42)
    |x| < 8/9 so don't do 8 - 9x = 7100
    Instead see if there's a nice clean cube factor you can take out and then multiply by at the end
    Thank you
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    (Original post by Gilo98)
    I get it now - we cant just solve for x as x is greater than 8/9 which means the expansion would not be valid. Hence we go for x=0.1 as this means we can manipulate the expansion to get a cubed root of 7100. Sneaky Q imo

    EDIT: just realised someone above has pointed this out.
    Danke
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    (Original post by kaya_lioness)
    Danke
    Why is it that when I put cubed root 7100 and 10 x cubed root 71 into my calculator I get different answers??
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    (Original post by anonwinner)
    Why is it that when I put cubed root 7100 and 10 x cubed root 71 into my calculator I get different answers??
    100 cube rooted is...

    I think you're mixing it up with squared.
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    (Original post by anonwinner)
    Why is it that when I put cubed root 7100 and 10 x cubed root 71 into my calculator I get different answers??
    You cube root 1000 which is 10. when you are left with 10 ( cube root) 7.1 which is the same the cube root 7100 and this is equal to (cube root) 8-9x.

    then you make 8-9x = 7.1
    x=0.1

    then you sub that into the expansion. Your answer will be ten smaller than cube root 7100 but thats it.
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    (Original post by SeanFM)
    100 cube rooted is...

    I think you're mixing it up with squared.
    Wow I'm dumb, thanks
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    (Original post by kaya_lioness)
    You cube root 1000 which is 10. when you are left with 10 ( cube root) 7.1 which is the same the cube root 7100 and this is equal to (cube root) 8-9x.

    then you make 8-9x = 7.1
    x=0.1

    then you sub that into the expansion. Your answer will be ten smaller than cube root 7100 but thats it.
    Thanks for explaining!
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    (Original post by anonwinner)
    Why is it that when I put cubed root 7100 and 10 x cubed root 71 into my calculator I get different answers??
    You're correct, although people are saying you're wrong. The mark scheme says 10 x cube root 71 - it is 10 cube root 7.1.. Hence you get different answers Mistake by the mark scheme really not you
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    (Original post by Jimmy_M)
    You're correct, although people are saying you're wrong. The mark scheme says 10 x cube root 71 - it is 10 cube root 7.1.. Hence you get different answers Mistake by the mark scheme really not you
    I knew something was wrong! Thanks
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    urgh ffs im ****ting myself for this exam
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    (Original post by yelllowribbon)
    urgh ffs im ****ting myself for this exam
    It's definitely the hardest A-level Maths exam, and you're not the only one. :console:

    There's still a few days left so just keep at it
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    (Original post by SeanFM)
    It's definitely the hardest A-level Maths exam, and you're not the only one. :console:

    There's still a few days left so just keep at it
    Cheers man Yeah it's just I would have liked C3 to have gone slightly better to try and take the pressure of C4, but yeah I guess just got to keep on going...
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    (Original post by JamieF95)
    This can't come up, right?
    Could do. Doubt they would give curve parametrically though. Thus, all you would need to do is

    



\pi\displaystyle\int^y_y x^2\ dy\
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    how is c4 constantly 75/75 for full ums....is the date normally later than our date for c4, I feel like with the way my exams a scheduled I cant revise effectively for c4 as I have biol5 and chem5 aswell day after day. Only done like 3 papers for c4 aswell and that was before easter


    EDIT:

    If you want to change the limits on an integral eg you have a 1 at the top and 2 at the bottom and you have a negative inside the integral can you bring this out removing it and change the limits?
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    (Original post by TeeEm)
    I hope so too, for the sake of my students
    Dd they not do aswell as the June 13 event?


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