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    (Original post by Phalange)
    0.4 and like 2.6
    something like that... answers in radians i think
    Ah, I can't actually remember what I got. But thank you anyway
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    (Original post by Jono404)
    Arghhh, you sure it wasn't 0.5 something? cause the 2x values were like 1. something and 5.something then you halve them
    The values are 30 and 150 degrees. Divide by 180 and multiply by pie and ull find out what it is. I haven't got a calculator in front of me
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    (Original post by Zeento)
    How many marks were on that question? Seems like that's the onlt one i got correct at the moment..
    i think it was 1
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    (Original post by Jono404)
    Arghhh, you sure it wasn't 0.5 something? cause the 2x values were like 1. something and 5.something then you halve them
    Uhhhh let me try to work it out

    Cos(2x) = 1/2
    2x = 1.0472
    2pie - 1.0472 = 5.236

    x = 0.52, 2.62
    aye
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    (Original post by lifeadd1ct)
    Guys, I don't understand where you are coming from. In the last 2 log questions, you had to get an answer given in the exam. The very last question, you had to get 1/(4log2) as the answer.
    from (8ei): log 10 = 3 log 2 + log 5 - log 4 so: log 5- log 4 = log 10 - 3 log 2. ==== log (5/4) = log 10 - 3 log 2

    (8eii) 2^(4x-3) = 5/4
    Thus: log (5/4) = (4x-3) log 2.
    Thus: log 10 - 3 log 2 = (4x - 3) log 2
    Thus: log 10 - 3 log 2 = 4x log 2 - 3 log 2
    Thus: log 10 = 4x log 2
    Thus: 1 = 4x log 2
    Thus: x = 1/(4log2)
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    (Original post by *A_S_H*)
    i think it was 1
    Great. 1 mark :woo:
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    (Original post by Phalange)
    Uhhhh let me try to work it out

    Cos(2x) = 1/2
    2x = 1.0472
    2pie - 1.0472 = 5.236

    x = 0.52, 2.62
    aye
    that is correct indeed.
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    (Original post by rob...)
    from (8ei): log 10 = 3 log 2 + log 5 - log 4 so: log 5- log 4 = log 10 - 3 log 2. ==== log (5/4) = log 10 - 3 log 2

    (8eii) 2^(4x-3) = 5/4
    Thus: log (5/4) = (4x-3) log 2.
    Thus: log 10 - 3 log 2 = (4x - 3) log 2
    Thus: log 10 - 3 log 2 = 4x log 2 - 3 log 2
    Thus: log 10 = 4x log 2
    Thus: 1 = 4x log 2
    Thus: x = 1/(4log2)
    OMG I SWEAR THEY DIDN'T SAY HENCE

    I would have looked up if they did
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    (Original post by Zeento)
    Great. 1 mark :woo:
    which i think i didnt get as i substitued the wrong value
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    Does anyone know how quick we can get hold of the paper online?
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    (Original post by rob...)
    from (8ei): log 10 = 3 log 2 + log 5 - log 4 so: log 5- log 4 = log 10 - 3 log 2. ==== log (5/4) = log 10 - 3 log 2

    (8eii) 2^(4x-3) = 5/4
    Thus: log (5/4) = (4x-3) log 2.
    Thus: log 10 - 3 log 2 = (4x - 3) log 2
    Thus: log 10 - 3 log 2 = 4x log 2 - 3 log 2
    Thus: log 10 = 4x log 2
    Thus: 1 = 4x log 2
    Thus: x = 1/(4log2)
    i did it slightly differently but i got the same answer as you.

    Does anyone have access to the paper?
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    They didn't say hence, it was INCREDIBLY CRUEL OF THEM!
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    (Original post by Zeento)
    Does anyone know how quick we can get hold of the paper online?
    the only way to get it right now is for someone to take pictures of the paper and upload them online. Aqa will not upload them for another year.
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    (Original post by *A_S_H*)
    which i think i didnt get as i substitued the wrong value
    At least you got some other marks habibti dyu know this is my third time sitting this exam I swear i feel like it's cursed for me! Im dreading c3 and c4 I haven't even started revising for them..
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    (Original post by rob...)
    They didn't say hence, it was INCREDIBLY CRUEL OF THEM!
    I agree
    did you answer the last one?
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    (Original post by Phalange)
    Uhhhh let me try to work it out

    Cos(2x) = 1/2
    2x = 1.0472
    2pie - 1.0472 = 5.236

    x = 0.52, 2.62
    aye
    :confused: is this answer rounded ? coz i got an answer in terms of pi, it wasnt a decomal
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    (Original post by rob...)
    They didn't say hence, it was INCREDIBLY CRUEL OF THEM!
    do you mean that for question 8 e?
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    (Original post by rob...)
    They didn't say hence, it was INCREDIBLY CRUEL OF THEM!
    I agree! I would have looked up as I got the first part right and completely left the second bit. ******* examiners!!
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    (Original post by Zeento)
    Great. 1 mark :woo:
    Haha
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    Grah, stupid last log question!! I took so long trying to work that out (and failed in the end) that I didn't check through the rest of the paper. Rest was easy enough though. There was some unusual stuff on there though...
 
 
 
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