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    what did everyone get for the last bit when you had to find the time
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    (Original post by JG1027)
    what did everyone get for the last bit when you had to find the time
    7.67 seconds...
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    (Original post by JG1027)
    what did everyone get for the last bit when you had to find the time
    I defo did that question wrong. I got 12. Something seconds lol...
    If the rope broke does that mean F=0?????
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    (Original post by johnny2spoons)
    7.67 seconds...
    What did you all get for the first question

    I had 9g up, 16g down and a further 7g up
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    the girl couldn't get the 60 degree angle because it required a force greater than her weight so she would be lifted off the floor LOL
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    If I can remember yeah f=0 which gives you the new acceleration so you put in equation to find t, I think it was a quadratic. I got 7.66 or thereabouts
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    (Original post by Axion)
    What did you all get for the first question

    I had 9g up, 16g down and a further 7g up
    yeah same here
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    How did everyone resolve the last question?
    The sleigh weighed 40kg n the rope breaks at 8ms-1 n she is 13.0m up.
    The rope breaks n your suppose to work out the time....
    I used s= ut + 0.5at2
    N used the quadratic formula....but got 12.summat :/
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    What do you think the grade boundaries will be like ?
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    (Original post by Jojo_555)
    How did everyone resolve the last question?
    The sleigh weighed 40kg n the rope breaks at 8ms-1 n she is 13.0m up.
    The rope breaks n your suppose to work out the time....
    I used s= ut + 0.5at2
    N used the quadratic formula....but got 12.summat :/
    F=ma to start where f=-40gsin15 and f=40a so -40gsin15=40a and then a=-2.5 something use xuvat

    x=-13
    u=8
    a=-2.5 summat
    t=t
    then x=ut + 1/2at^2 sub in values and use quadratic formula.... about 7.67s i think...
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    (Original post by johnny2spoons)
    F=ma to start where f=-40gsin15 and f=40a so -40gsin15=40a and then a=-2.5 something use xuvat

    x=-13
    u=8
    a=-2.5 summat
    t=t
    then x=ut + 1/2at^2 sub in values and use quadratic formula.... about 7.67s i think...
    so basically was the only force acting the component of weight down slope ?
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    (Original post by Axion)
    What did you all get for the first question

    I had 9g up, 16g down and a further 7g up
    I got 7g down, 16g up and a further 9g down?


    Posted from TSR Mobile
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    the first question confused me i thought i had to draw extra boxes the wording should have been better
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    (Original post by JG1027)
    so basically was the only force acting the component of weight down slope ?
    yes
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    (Original post by johnny2spoons)
    F=ma to start where f=-40gsin15 and f=40a so -40gsin15=40a and then a=-2.5 something use xuvat

    x=-13
    u=8
    a=-2.5 summat
    t=t
    then x=ut + 1/2at^2 sub in values and use quadratic formula.... about 7.67s i think...
    Like holy sh*t. I did all of that but I stupidly put x=13 :/
    Cuz I was thinking of the equation S= So + ut + 0.5t2
    My S being 0 cuz she goes back to her original position and So being 13
    That's kinda made me sad now
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    (Original post by johnny2spoons)
    yes
    i did that but i used v=u+at to find the time would that be wrong? because v=0 u=8 a=2.5 and t=? so rearrange and i got -3.2s so 3.2 s
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    Wait... i got like 1.44s on the last question

    views on that?
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    Does anyone remember what they got for that vector equation thing?
    Finding out the vector a?
    I remember getting summat like (0.4, 14, -35) or something :/
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    (Original post by stefanocattaneo)
    I got 7g down, 16g up and a further 9g down?


    Posted from TSR Mobile
    0.o wrong way round bro...

    btw I wrote the actual values rather than just writing 7g
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    (Original post by Jojo_555)
    Does anyone remember what they got for that vector equation thing?
    Finding out the vector a?
    I remember getting summat like (0.4, 14, -35) or something :/
    i got 7/0.4= 17.5
 
 
 
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