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# OCR MEI - FP1 - 14th May 2015 watch

1. Good paper I thought! The induction question in particular was great. 5ii caused some problems though.

Took some notes out with me if anyone wants a look at any solutions.
2. For the transformation for matrix M i put a two way strech, sf 4 in the x direction and sf 2 in the y direction is this correct?
3. (Original post by Darcy1)
For the transformation for matrix M i put a two way strech, sf 4 in the x direction and sf 2 in the y direction is this correct?
Think so. That's what I put. Bit generous for 3 marks I thought, unless I've missed something.
4. (Original post by Darcy1)
For the transformation for matrix M i put a two way strech, sf 4 in the x direction and sf 2 in the y direction is this correct?
I did exactly this as well. But, I think we drop a mark for not saying two-way stretch.
5. (Original post by Aph)
k=1/3

area =4*6*8 = 192
wouldn't the area be 48 since the determinants of T and M were 6 and 8 and the original shape had an area of 1?
6. This was the graph. Asymptotes at x = -1, 2 and y = 3
Crosses at x = 3, -2/3 and y = 3
Above at x = -100 Below at x = 100
part 4 was where is y >= 3:
x > -1 and 0 <= x < 2

Attached Images

7. (Original post by frackingmusic)
wouldn't the area be 48 since the determinants of T and M were 6 and 8 and the original shape had an area of 1?
The original shape had an area of 4...
co-ordinates were (0,0), (0,2), (4,1) that's a isosceles triangle base 2 hight 4
8. (Original post by Aph)
The original shape had an area of 4...
co-ordinates were (0,0), (0,2), (4,1) that's a isosceles triangle base 2 hight 4
I could've sworn the coordinates were (0,0) (2,0) and (4,1)
9. (Original post by frackingmusic)
I could've sworn the coordinates were (0,0) (2,0) and (4,1)
No Aph is right it was an area of 4 !
10. (Original post by frackingmusic)
I could've sworn the coordinates were (0,0) (2,0) and (4,1)
I got the same answer as you as well. I think we got the 2,0 and 0,2 co-ordinates other way round.
11. (Original post by frackingmusic)
I could've sworn the coordinates were (0,0) (2,0) and (4,1)
I did the same for a while but no they were definately what I stated.
12. I'm hoping around 70/72 for 100UMS. I definitely think it was a harder paper than last year!
13. (Original post by Aph)
I did the same for a while but no they were definately what I stated.
you're right those are the co-ordinates and the right answer
14. I was allowed to take this bad boy in. Did everything
15. Guys what do you think about grade boundaries? I would've got 100% but misread the (z-(-1-j))=pi/4 and instead did (z-(-1+j))=pi/4 whyyyyyyyy? ((((((((((((( So screwed ffs lol

Easy paper as well, I expect 63 as A again :/
16. I cannot remember if I actually put p= r= in one of the questions, but I did right the equation. Will they still imply that I got the right answeR?
17. (Original post by MintyMilk)
Attachment 398155

Our unofficial mark scheme, (2 of us).

Pinch of salt.

Edit: X and Y on Q1 are the other way around (we both got them the right way in the actual exam)

Edit 2: Q4 is meant to be from -1-j, and the area below it isn't meant to be shaded, I wasn't the one who actually wrote all the stuff out and we went through it all pretty quickly, sorry about the discrepancies
18. (Original post by MintyMilk)
Was just about to say something :P

Quick question, for question 4, for some stupid reason I did everything correct but with arg(z-(-1+j)) for some reason :/ Throughout the whole question, how many marks do you reckon I lost? Max would be 4 but probs 2/3 :/
19. (Original post by joe12345marc)
Was just about to say something :P

Quick question, for question 4, for some stupid reason I did everything correct but with arg(z-(-1+j)) for some reason :/ Throughout the whole question, how many marks do you reckon I lost? Max would be 4 but probs 2/3 :/
Well, the part that required you to plot that particular inequality was two marks, then part 3 was another 2 marks.

Not quite sure, but it could be anywhere from 1 to 4
1 mark lost if they allow full follow-through marks on part 3 and the actual plotting of the point in part 2 was only worth 1 mark (assuming you got the inequality correct).

4 marks lost if it's 0 for anything that isn't fully correct in part 2, then if that carries over to part 3. I think 2 to 3 is the most likely range, sorry I can't give an exact figure though, maybe someone more experienced can.
20. (Original post by MintyMilk)
Well, the part that required you to plot that particular inequality was two marks, then part 3 was another 2 marks.

Not quite sure, but it could be anywhere from 1 to 4
1 mark lost if they allow full follow-through marks on part 3 and the actual plotting of the point in part 2 was only worth 1 mark (assuming you got the inequality correct).

4 marks lost if it's 0 for anything that isn't fully correct in part 2, then if that carries over to part 3. I think 2 to 3 is the most likely range, sorry I can't give an exact figure though, maybe someone more experienced can.
Nah it's cool I just was checking and making sure I'm being realistic with my score! Was expecting 100 UMS today but a stupid mistake like that can cost me like 10 UMS :/

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