The Student Room Group

OCR (non mei) S2 Wednesday 15th June 2016

Scroll to see replies

For the last question I managed to put the type of error, the value of p(X>=20) and p(X>=19) and I claimed the probability of a type 2 would be the probability of p(x>=19) and didn't take it away from 1. How many method marks do youse think would be given? I was assuming 1 each for the boundary probabilities and 1 for the type of error but not entirely sure.
Reply 101
For 8 ii, we didn't have to run a complete test did we and state hypotheses etc? Just find out if it changed the result of the test?


Posted from TSR Mobile
Original post by GM16
For 8 ii, we didn't have to run a complete test did we and state hypotheses etc? Just find out if it changed the result of the test?


Posted from TSR Mobile


The question just says "Determine whether this makes a difference to theconclusion of the test" so you won't need to state the hypotheses again.
Reply 103
Original post by marioman
The question just says "Determine whether this makes a difference to theconclusion of the test" so you won't need to state the hypotheses again.


Phew, thanks


Posted from TSR Mobile
Original post by xsanda
Xsanda's solutions

1) Unbiased mean and variance of summarised data
E(V) = 268
Var(V) = 1912/13 = 147 [4]

2) Normal distribution, given P(M<1.00) = 5%
P(M>1.05) = 13.6% [6]

3) Approximated binomial
n large, np = 26 > 5, nq = 14 > 5
use normal distribution
P(X<=30) = 0.932 [7]

4) Poisson, P(X=4) = P(X=5)
λ = 5, P(X=5) = 0.175 [5]

5) School with 55% girls
i) P(G≥6) = 22% (above significance level), do not reject H₀ [7]
ii) Fixed prob of girl chosen, independent of previous Head Students [1]

6) Cars along a narrow road
i) Constant probability of cars throughout the minute, cars independent [2]
ii) λ = 6.5, P(4≤X<7) = 0.561[3]
iiia) N(30,30)
P(X>35) = 0.158 [6]
b) Not independent (narrow, slow road, so affected by car in front) [1]

7) Probability density function
i) x is a single sample value of X [1]
ii) a=1, b=1.5 [7]
iii) E(X) = 7/4 = 1.75 [3]

8) Animals dying at zoo
i) P(L<12.48) = 4.88% < 5%
reject H₀, substantial evidence zoos limit life expectancy [7]
ii) = 12.5
5.05% > 5%, do not reject H₀, insufficient evidence zoos limit life expectancy [5]
iii) yes, as the distribution of the original data is not given [1]

9) Poisson test, λ=11
i) reject if P(R≥20)
92% chance of Type II error [6]


I concur with all of these.
For 8ii I didn't calculate an unbiased variance. I followed through with just the number given and got the correct conclusion. How many marks will I lose out of 5?
Original post by Mr M (jr)
I concur with all of these.


I keep thinking about my answer to 5ii) . . . . .

that the sample must be random for the significance test to be valid, and then going on to explain what a random sample is in this particular context. Xsanda's answer isn't the same. . . . . and so you don't concur with me. . . . .

To me the question is similar to question 6i) on the June 2014 paper...???????

Quick Reply

Latest

Trending

Trending