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    wake me up inside
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    (Original post by decombatwombat)
    My answers, by no means right, just want to compare with people :

    1)i) 1 - x^2 + x^4

    ii) x - 1/3 x^3 + 1/5 x^5

    iii) pi/6

    iv) Draw the graph, sort of like a loop but starting at pi/4 and ending on the horizontal axis

    As the angles tends to 0 r tends to infinity

    v) a^2 ln(2 root2) or 1/2 a^2 ln 8

    2)i) 1-z

    ii) Show that C + jS thing

    iii) Modulus of the cube roots was root2 the angles were pi/18 13pi/18 25pi/18


    3)i) Eigenvalues were -1/6, 1 eigenvectors were (1 1) and (3 -4) I think, cant quite remember the order

    ii) M^n tended towards (3 4) or something like that order might be different
    ................................ .(3 4)
    cant quite remember

    iii) Not too sure on this, I think it didnt tend to a limit (maybe infinity), as the elements of the matrix were greater than 1 but some were negative so it could have positive or negative infinity

    4)i) Show that arcosh thing

    ii) ln((3+root5)/2) and ln((3-root5)/2)

    iii) The graph sort of looked like x^2 but started at y=2

    The area bound by the curve was 5root5 / 2
    The area bound by the line y = 5 was 5ln((7+3root5)/2)

    Then take one away from the other.


    I think that was all the questions, not sure how many are right, just what I got
    Agree with all in Q1 and I think you have to show that +C = 0 - that counted as 2 marks in a past paper
    Also I put that r tends to +/- infinity - is this ok???

    Agree with Q2
    Agree with Q3 but I got M^n tends to a matrix - can't remember but it had like 3/7 and 4/7 in it
    For part 3 I just put tends to infnity so does not tend to a limit.

    Q4; for the area I got 10ln (3+root5/2) - something ...
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    Confusing and tedious paper
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    decombatwombat I agree with almost everything (which is great ) except I argues that the area bound by y=5 was 5*2ln(\frac{3+\sqrt{5}}{2}) and I can't see how you got your answer.
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    (Original post by Sophieoo1)
    Agree with all in Q1 and I think you have to show that +C = 0 - that counted as 2 marks in a past paper
    Also I put that r tends to +/- infinity - is this ok???

    Agree with Q2
    Agree with Q3 but I got M^n tends to a matrix - can't remember but it had like 3/7 and 4/7 in it
    For part 3 I just put tends to infnity so does not tend to a limit.

    Q4; for the area I got 10ln (3+root5/2) - something ...
    Oh yeah sorry that 4/7 thingy for the matrix is what I got, forgot to put that. I also did the +c thing for the first part. I think you should be alright with the +/- infinity. I think your answer to the last part is just a simplified version of what I put.
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    I got z - 1 for question 2, is that still right? I think it still works for the binomial but I'm not sure. ( I wrote it like (-1+z)^n )


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    (Original post by Aph)
    decombatwombat I agree with almost everything (which is great ) except I argues that the area bound by y=5 was 5*2ln(\frac{3+\sqrt{5}}{2}) and I can't see how you got your answer.
    I think I put the 2 inside, so that it was the thing in the ln squared, which equals the same as yours.
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    What is it likely to be for a B?
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    Any predictions for the A boundary?
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    Did someone manipulate the complex numbers by multiplying by j^4 to get the required result ?
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    (Original post by Connorbwfc)
    Any predictions for the A boundary?
    63/64?
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    (Original post by Connorbwfc)
    Any predictions for the A boundary?
    58 or 59 :/
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    Imo that was one of the hardest papers. Cant recall the last time when they asked you to integrate a hyperbolic function to find the area and all that M^n infinity nonsense. Also cant remember any pp questions like the (1-z). Hopefully it will be 50-55 for an A
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    (Original post by decombatwombat)
    63/64?
    funny
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    Did anyone get 5root5 for the area


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    (Original post by decombatwombat)
    I think I put the 2 inside, so that it was the thing in the ln squared, which equals the same as yours.
    ahhh yes, it does. okay I think that was probably too much work there then you needed but I'm sure its okay.
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    I would personally say around 55 for an A.

    This was the hardest paper for me in recent memory.
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    (Original post by MintyMilk)
    funny
    Yeah that was probably a bit high of an estimate, its just that FP2 boundaries tend to be pretty high. Most likely it will be 59/60
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    (Original post by decombatwombat)
    63/64?
    would make it the easiest paper in the past 6 years!!!
    (Original post by Connorbwfc)
    Any predictions for the A boundary?
    55/56
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    (Original post by decombatwombat)
    Yeah that was probably a bit high of an estimate, its just that FP2 boundaries tend to be pretty high. Most likely it will be 59/60
    Boundary for an A on Jan 13 was 56, and this was significantly harder.

    Expecting somewhere around 53-55
 
 
 
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