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    (Original post by charlesdarwin)
    somebody remembers the answer for the second part of the trapezium rule question?

    it was 14. something, I think 14.553
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    (Original post by Einsteinj.n.r)
    it was 14. something, I think 14.553
    For the part with the transformations, on the first part did u divide by 2 and the second part used trapezium rule again

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    till what i could remember..not in the same order though!
    1. p=1.5, q=63
    2. a. 14.556, b. 7.278 , cant remember
    3. a. x< or equal to 4.5
    b. x> 1.5 or x< -5 X< -5 and 1.5<X<4.5
    4. arithmetic440066
    5. centre(x-a)^2 + y2= a^2A= 25/8
    6. angle sin 19.5 and -30
    7. geometric0.817539
    8. grapha- (8/5,4/5) b- (20/9, 10/9)
    9. log Y^2 = 32/Xx= 0.5y=8
    10. Q(x)a= -10b= 13
    11. sectorarea = 0.654
    12. some angle question pi/12 and 5pi/12
    13. integration 11/64
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    (Original post by Jjll99)
    don't you think so?
    I found the exam easier so i think the gb may increase
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    (Original post by jamessmith 2202)
    till what i could remember..not in the same order though!
    1. p=1.5, q=63
    2. a. 14.556, b. 7.278 , cant remember
    3. a. x< or equal to 4.5
    b. x> 1.5 or x< -5 X< -5 and 1.5<X<4.5
    4. arithmetic440066
    5. centre(x-a)^2 + y2= a^2A= 25/8
    6. angle sin 19.5 and -30
    7. geometric0.817539
    8. grapha- (8/5,4/5) b- (20/9, 10/9)
    9. log Y^2 = 32/Xx= 0.5y=8
    10. Q(x)a= -10b= 13
    11. sectorarea = 0.654
    12. some angle question pi/12 and 5pi/12
    13. integration 11/64
    For 5, y=0 so it will be
    centre(x-a)^2 + 9= a^2A= 25/8

    For 4, I don't remember that kind of an answer

    The rest seems familiar 😃😃
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    (Original post by jamessmith 2202)
    till what i could remember..not in the same order though!
    1. p=1.5, q=63
    2. a. 14.556, b. 7.278 , cant remember
    3. a. x< or equal to 4.5
    b. x> 1.5 or x< -5 X< -5 and 1.5<X<4.5
    4. arithmetic440066
    5. centre(x-a)^2 + y2= a^2A= 25/8
    6. angle sin 19.5 and -30
    7. geometric0.817539
    8. grapha- (8/5,4/5) b- (20/9, 10/9)
    9. log Y^2 = 32/Xx= 0.5y=8
    10. Q(x)a= -10b= 13
    11. sectorarea = 0.654
    12. some angle question pi/12 and 5pi/12
    13. integration 11/64
    from what i remember... all these seem right
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    (Original post by khassan)
    For the part with the transformations, on the first part did u divide by 2 and the second part used trapezium rule again

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    it was 16+ the answer you got which was 14.553 or something
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    (Original post by Ibrahim Rampuri)
    it was 16+ the answer you got which was 14.553 or something
    Whaaaaat? How?

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    (Original post by Ibrahim Rampuri)
    it was 16+ the answer you got which was 14.553 or something
    Yup got the same!
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    (Original post by jamessmith 2202)
    till what i could remember..not in the same order though!
    1. p=1.5, q=63
    2. a. 14.556, b. 7.278 , cant remember
    3. a. x< or equal to 4.5
    b. x> 1.5 or x< -5 X< -5 and 1.5<X<4.5
    4. arithmetic440066
    5. centre(x-a)^2 + y2= a^2A= 25/8
    6. angle sin 19.5 and -30
    7. geometric0.817539
    8. grapha- (8/5,4/5) b- (20/9, 10/9)
    9. log Y^2 = 32/Xx= 0.5y=8
    10. Q(x)a= -10b= 13
    11. sectorarea = 0.654
    12. some angle question pi/12 and 5pi/12
    13. integration 11/64
    almost all seem familiar apart from 4 :/
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    (Original post by khassan)
    Whaaaaat? How?

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    it was integration of 2 + the original equation.. so when integrate 2 you get 2x and subtitute x with number of x values between 6 and -2 so 8 values so it is 2*8 + your original answer
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    (Original post by pondsteps)
    Yup got the same!
    For the first or second transformation?
    For the first I just divided the previous by 2....for the second I used the trapezium rule again

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    (Original post by khassan)
    For the first or second transformation?
    For the first I just divided the previous by 2....for the second I used the trapezium rule again

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    no the 16+ thing is for the sec transformation.. and no u dont use the trapezium rule again
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    (Original post by pondsteps)
    no the 16+ thing is for the sec transformation.. and no u dont use the trapezium rule again
    Y 16?

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    (Original post by jamessmith 2202)
    i think it is 11/64 cz..the area of the triangle was 0.5x(3/8)x(2-0.5)..=9/32
    integrated region= x(x-1)(x-2) from 1 to 0.5= 7/64
    9/32 -7/64 = 11/64
    yea i think that's what i got
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    I don't know how some of you thought the paper was easy but I found it quite tough tbh 😟 Hope grade boundaries are lower.
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    (Original post by Saad69)
    I got 30 and -19.5 I think

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    me too
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    (Original post by Arzam45)
    Yea that's what I got.
    i got a=10
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    (Original post by Riri18)
    I don't know how some of you thought the paper was easy but I found it quite tough tbh 😟 Hope grade boundaries are lower.
    It was definitely not easy, but it wasn't too hard either. I know many people at my school found it difficult so I'm sure the grade boundaries will be similar to the January 2016 grade boundaries, if not, lower. I guess the difficulty of the paper depends on how many past papers you've done, some people who found the exam very easy have done literally all the papers since 2007 lol
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    (Original post by Raynedrops)
    Nothing, I have no idea how to work out the answer!
    the centre was (a,0)
    so circles eq will be (x-a)^2+(y-0)^2=a^2 because a is the radius
    and in the second part substitute x with 4 and y with -3 to get a
    i got it like 3.125
 
 
 
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