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    (Original post by money-for-all)
    i got y=8 and my skecth was an upside down quadratic graph like an upside down 'U' is that right ? or nah
    Yeah, sounds right.

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    (Original post by AccountingHelp)
    If I'm thinking about the same question as you, you didn't have to work out the max point did you? It just said state clearly the y intercept
    Oh, sorry. Yep, I meant intecept. So is it at y=15?
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    (Original post by df97)
    Shouldn't it be 75-32rt5?
    Yep, thanks! What a big change one button press can be! I've edited the original post. Sorry to anyone I confused!
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    hey i messed up some how on the last step of finding equation of P ( used the right method) meaning i got point Q wrong and so forth couldnt work out the area! but i got the correct integral and the correct method throughout and so how many marks will i loose for this whole section??
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    (Original post by 28657)
    Oh, sorry. Yep, I meant intecept. So is it at y=15?
    No, y=8
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    (Original post by timtjtim)
    Yeah, sounds right.

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    ****, here goes -1 mark
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    (Original post by BlackthornRose)
    Exactly what i was thinking.



    So the translation was [1/2, 41/4] as opposed to [1/2, -41/4]? Please explain, i sort of understand and sort of don't as i can't completely remember which one it said is supposed to map onto the other.
    The question was y=(x-7/2)-41/4 to y=(x-4)
    So we need to get rid of the -41/4, to do that we need to add -41/4 to LHS.
    Vector [a,b] translates y=x to y-b=x-a therefore [1/2, 41/4] must give y-41/4=(x-7/2-1/2)-41/4 clearing it up gives y=(x-4)
    Hope that helps
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    what was the question in number 3, 4, 6, 7a 7b, 8a
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    ..
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    Who else got root 34 ? Please say aye aye captain !
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    (Original post by money-for-all)
    Who else got root 34 ? Please say aye aye captain !
    sorry thats wrong lol the radius is root 65
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    (Original post by money-for-all)
    Who else got root 34 ? Please say aye aye captain !
    nope

    root 65
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    (Original post by timtjtim)
    Yeah, sounds right.

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    What a g, you drew what I did, I knew AQA were trying to be sneaky so I completed the square on the quadratic and found out that it turns above 8 and drops down to pass through the 8 (y-intercept), rate you for it aha
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    (Original post by BearackObama)
    How did people get root 65 for the radius of the circle when the centre co-ordinates were (5,-3). On expanding this came out as root 34 surely?
    i got rooooooooooot 34
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    (Original post by df97)
    The question was y=(x-7/2)-41/4 to y=(x-4)
    So we need to get rid of the -41/4, to do that we need to add -41/4 to LHS.
    Vector [a,b] translates y=x to y-b=x-a therefore [1/2, 41/4] must give y-41/4=(x-7/2-1/2)-41/4 clearing it up gives y=(x-4)
    Hope that helps
    Yes it did, thank you very much. I also just reworked it out for myself and you are correct. That's another mark gone for me.
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    I recently made a new thread with an updated mark scheme if you lot could add to it, it will be finished soon

    http://www.thestudentroom.co.uk/show....php?t=4095491
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    (Original post by timtjtim)
    No, y=8
    did you have to mention the x cordinates ?!?!?!?!?
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    (Original post by money-for-all)
    i got rooooooooooot 34
    Mate you had to use the distance formula or place the number in the eq to find k (=r^2)
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    (Original post by rndmtngr99)
    I got k=30
    Are u sure k wasn't -30
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    (Original post by beanigger)
    sorry thats wrong lol the radius is root 65
    I got sqrt65 as well. Did you find it by using pytharogas or substituting point A into the equation?
 
 
 
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