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# AQA C1 Unofficial Markscheme Watch

1. (Original post by money-for-all)
i got y=8 and my skecth was an upside down quadratic graph like an upside down 'U' is that right ? or nah
Yeah, sounds right.

2. (Original post by AccountingHelp)
If I'm thinking about the same question as you, you didn't have to work out the max point did you? It just said state clearly the y intercept
Oh, sorry. Yep, I meant intecept. So is it at y=15?
3. (Original post by df97)
Shouldn't it be 75-32rt5?
Yep, thanks! What a big change one button press can be! I've edited the original post. Sorry to anyone I confused!
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4. hey i messed up some how on the last step of finding equation of P ( used the right method) meaning i got point Q wrong and so forth couldnt work out the area! but i got the correct integral and the correct method throughout and so how many marks will i loose for this whole section??
5. (Original post by 28657)
Oh, sorry. Yep, I meant intecept. So is it at y=15?
No, y=8
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6. (Original post by timtjtim)
Yeah, sounds right.

****, here goes -1 mark
7. (Original post by BlackthornRose)
Exactly what i was thinking.

So the translation was [1/2, 41/4] as opposed to [1/2, -41/4]? Please explain, i sort of understand and sort of don't as i can't completely remember which one it said is supposed to map onto the other.
The question was y=(x-7/2)-41/4 to y=(x-4)
So we need to get rid of the -41/4, to do that we need to add -41/4 to LHS.
Vector [a,b] translates y=x to y-b=x-a therefore [1/2, 41/4] must give y-41/4=(x-7/2-1/2)-41/4 clearing it up gives y=(x-4)
Hope that helps
8. what was the question in number 3, 4, 6, 7a 7b, 8a
9. ..
10. Who else got root 34 ? Please say aye aye captain !
11. (Original post by money-for-all)
Who else got root 34 ? Please say aye aye captain !
sorry thats wrong lol the radius is root 65
12. (Original post by money-for-all)
Who else got root 34 ? Please say aye aye captain !
nope

root 65
13. (Original post by timtjtim)
Yeah, sounds right.

What a g, you drew what I did, I knew AQA were trying to be sneaky so I completed the square on the quadratic and found out that it turns above 8 and drops down to pass through the 8 (y-intercept), rate you for it aha
14. (Original post by BearackObama)
How did people get root 65 for the radius of the circle when the centre co-ordinates were (5,-3). On expanding this came out as root 34 surely?
i got rooooooooooot 34
15. (Original post by df97)
The question was y=(x-7/2)-41/4 to y=(x-4)
So we need to get rid of the -41/4, to do that we need to add -41/4 to LHS.
Vector [a,b] translates y=x to y-b=x-a therefore [1/2, 41/4] must give y-41/4=(x-7/2-1/2)-41/4 clearing it up gives y=(x-4)
Hope that helps
Yes it did, thank you very much. I also just reworked it out for myself and you are correct. That's another mark gone for me.
16. I recently made a new thread with an updated mark scheme if you lot could add to it, it will be finished soon

http://www.thestudentroom.co.uk/show....php?t=4095491
17. (Original post by timtjtim)
No, y=8
did you have to mention the x cordinates ?!?!?!?!?
18. (Original post by money-for-all)
i got rooooooooooot 34
Mate you had to use the distance formula or place the number in the eq to find k (=r^2)
19. (Original post by rndmtngr99)
I got k=30
Are u sure k wasn't -30
20. (Original post by beanigger)
sorry thats wrong lol the radius is root 65
I got sqrt65 as well. Did you find it by using pytharogas or substituting point A into the equation?

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