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    I really hope the grade boundaries aren't high as heck


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    (Original post by Bliss_)
    It was good.
    What was the answer for the very last question about Shane gas?


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    i wrote that amount of polymers may increase but to a little extent as percentages are low
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    It wasn't bad but some mcq's were weird.
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    (Original post by ToxicPhantom007)
    i wrote that amount of polymers may increase but to a little extent as percentages are low
    I AM SURE THIS IS MOST PROBABLY WRONG BUT THIS IS WHAT I DID.
    The question asked about the polymers and I remember it said "Poly(ethene) relative to Poly(propene)" So since it said relative I guess we have to compare the two as its obvious it will increase.. The question data was something like this:
    Methane-90% Ethane-0.6% Propane-0.4% Butane-0.4%

    Since poly(ethene) can be formed only from ethane, propane and butane and not methane because it has only 1 carbon and cannot be cracked into a ethene molecule, the percentage of shale that could be used to make poly(ethene) would be 0.6%+ 0.4%+ 0.4% = 1% . So 1% of shale can be used to make poly(ethene).

    Since poly(propene) can only be formed from propane and butane and not ethane and not methane, the percentage of shale that could be used to make poly(propene) will be 0.4% + 0.4% =0.8% .

    Hence increased amounts of both polymers can be formed but more poly(ethene) is formed as 1% of shale can be used while 0.8% of shale can be used to make poly(propene)

    Idk about this ans tho
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    What was the helium question?
    what was the answer to the question where u had to state an assumption to the enthalpy change for the hess law?
    what was the answer to the shell question?
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    (Original post by wenogk)
    I AM SURE THIS IS MOST PROBABLY WRONG BUT THIS IS WHAT I DID.
    The question asked about the polymers and I remember it said "Poly(ethene) relative to Poly(propene)" So since it said relative I guess we have to compare the two as its obvious it will increase.. The question data was something like this:
    Methane-90% Ethane-0.6% Propane-0.4% Butane-0.4%

    Since poly(ethene) can be formed only from ethane, propane and butane and not methane because it has only 1 carbon and cannot be cracked into a ethene molecule, the percentage of shale that could be used to make poly(ethene) would be 0.6%+ 0.4%+ 0.4% = 1% . So 1% of shale can be used to make poly(ethene).

    Since poly(propene) can only be formed from propane and butane and not ethane and not methane, the percentage of shale that could be used to make poly(propene) will be 0.4% + 0.4% =0.8% .

    Hence increased amounts of both polymers can be formed but more poly(ethene) is formed as 1% of shale can be used while 0.8% of shale can be used to make poly(propene)

    Idk about this ans tho
    lol it was of 2 marks and wtf there's no need for such detail
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    and what did you choose for the mcq where gases were remaining at the end ?
    i chose 100 cm3
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    (Original post by ToxicPhantom007)
    and what did you choose for the mcq where gases were remaining at the end ?
    i chose 100 cm3
    it was 75
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    (Original post by ToxicPhantom007)
    lol it was of 2 marks and wtf there's no need for such detail
    I wrote it in short form in 4 lines..
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    (Original post by ToxicPhantom007)
    lol it was of 2 marks and wtf there's no need for such detail
    Lol yea


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    What about that deflection question was the line above or below?


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    (Original post by hasi.99)
    What about that deflection question was the line above or below?


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    i think it was below because it was deflected more
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    (Original post by tejsanghavi)
    it was 75
    Also found 75
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    was the answer to the shell question 3p 3s 3s
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    What did u find for the enthalpy change for the combustion? And the one below where u were given the grams ?
    (Sorry for the vague explanation)
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    (Original post by Bliss_)
    It was good.
    What was the answer for the very last question about Shane gas?


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    Ethane and propane are used to make ethene and propene by dehydrogenation reaction. This ethene and propene is used to make poly ethene and poly propene. But since, Ethane and Propane are required for the manufacture of Shane gas, the production of poly ethene and poly propene decreases.
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    (Original post by Sandy_Vega30)
    Ethane and propane are used to make ethene and propene by dehydrogenation reaction. This ethene and propene is used to make poly ethene and poly propene. But since, Ethane and Propane are required for the manufacture of Shane gas, the production of poly ethene and poly propene decreases.
    I wrote that to. About dehydration and stuff like that
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    (Original post by hasi.99)
    What about that deflection question was the line above or below?


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    Below. Lighter molecules are deflected more.
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    (Original post by tejsanghavi)
    What was the helium question?
    what was the answer to the question where u had to state an assumption to the enthalpy change for the hess law?
    what was the answer to the shell question?
    I wrote that Helium has very low atomic mass (its very light) and hence can be deflected more easily by the magnetic field.

    Shells : 3p 3s 3s 2p

    I don't really recall an assumption for the Hess's law.
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    (Original post by Sandy_Vega30)
    I wrote that Helium has very low atomic mass (its very light) and hence can be deflected more easily by the magnetic field.

    Shells : 3p 3s 3s 2p

    I don't really recall an assumption for the Hess's law.
    I wrote that is light and also very small so can pass through the smallest of gaps.
    For shells I included the spins as it asked for orbital.The assumption was for the RAM which was that Carbon has an RAM of 12
 
 
 
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