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2016 May 25th Edexcel Core 2 Questions and answers. [Unofficial mark scheme] 2016 Watch

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    Grade boundary ideas?
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    (Original post by X_IDE_sidf)
    http://www.thestudentroom.co.uk/atta...1&d=1464204940 <-- NEW PDF. This is V2 and has been layed out in a more stylish manner and has Q 9c corrected

    Edit: to satisfy my ocd, the real scanned paper will be hitting shelves soon.
    Link doesn't work :-(
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    (Original post by HannahC-H)
    Link doesn't work :-(
    http://docdro.id/xPyA5Yl

    edit: DERP, forgot to change Q 8. =0 not -1
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    For question 7 would you lose a mark for not putting +c on the integral?
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    TY
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    (Original post by bulletman54)
    For question 7 would you lose a mark for not putting +c on the integral?
    I think so, the question didn't specify limits in (a) so without + c you are technically incorrect.
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    (Original post by X_IDE_sidf)
    I think so, the question didn't specify limits in (a) so without + c you are technically incorrect.
    What was the exact wording of the question ?
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    (Original post by bulletman54)
    What was the exact wording of the question ?
    find \int (3x-x^{\frac{3}{2}})dx
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    If I got x = ~17 and didn't sub back into P, how many marks do you reckon I'll lose?
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    (Original post by bulletman54)
    What was the exact wording of the question ?
    Usually the mark scheme says (+c) in brackets as in previous years, so I don't think you'd lose a mark
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    (Original post by bulletman54)
    For question 7 would you lose a mark for not putting +c on the integral?
    In previous years its in brackets and not required
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    (Original post by medapplicant2016)
    If I got x = ~17 and didn't sub back into P, how many marks do you reckon I'll lose?
    2 i think cause u made a rounding error and never subbed for the min value
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    (Original post by medapplicant2016)
    In previous years its in brackets and not required
    Could you link me the markscheme for a question like this from a previous year?
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    (Original post by medapplicant2016)
    In previous years its in brackets and not required
    source
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    (Original post by X_IDE_sidf)
    http://docdro.id/xPyA5Yl

    edit: DERP, forgot to change Q 8. =0 not -1
    Wasn't 6i

    1-2cos(\theta -\frac{\pi}{5})

    and not

    1-2sin(\theta -\frac{\pi}{5})
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    For the perimeter question, if I substituted x=17, how many marks can I expect to lose ?
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    (Original post by UKoE Luna)
    Wasn't 6i

    1-2cos(\theta -\frac{\pi}{5})

    and not

    1-2sin(\theta -\frac{\pi}{5})
    we are on to V4 now http://docdro.id/18BTG2C

    Thanks
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    (Original post by X_IDE_sidf)
    6 1-2\sin(\theta - \frac{\pi}{5})=0 solve for \theta and 4\cos^2 x + 7\sin x - 2 = 0

    6 i) (3 marks) \frac{8\pi}{15}or \frac{-2\pi}{15}
    ii) (6 marks) 345.5$^{\circ}$ or 194.5$^{\circ}$
    Is question 6 written out correctly? I get \frac{11\pi}{30}or \frac{31\pi}{30}

    EDIT: Seen that there have been amendments since then. Shouldn't 8i) be \frac{a-5}{9}?
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    (Original post by X_IDE_sidf)
    source
    (Original post by bulletman54)
    Could you link me the markscheme for a question like this from a previous year?
    http://qualifications.pearson.com/co...c_20150812.pdf

    See question 6
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    (Original post by bulletman54)
    2 i think cause u made a rounding error and never subbed for the min value
    That's what I thought, I did get 16.something though, and did work out f"(x) > 0, which usually gives you 2 marks (you don't need to sub)
 
 
 
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