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    (Original post by miniassassin)
    I feel like I've seen completely different electricity questions than everyone here... oh dear
    I am a stalker not assassin. Stalker's do not do any harm. HEHE:zorro:
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    (Original post by Mr.Suhk)
    14)increasing frequency increases max KE of emitted electrons as by equation or by photon energy route, your choice
    The question asked what would happen if the frequency of light was reduced, not increased, which would mean that the electrons would be emitted at the same rate but with less kinetic energy.
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    the total resistance decreases of the circuit which means toal current increses so V across resistor increases
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    (Original post by xxMerlinLoverxx)
    I got Q6 completely wrong :/ I worked out answers using the 6.3 and got 6ohms for the other resistor. I then got 1/6+1/2=2/3 which I flipped and got 3/2 and added onto 3/2 to get 3 ohms. Did anyone else do this or was this just me being stupid? How many marks will I lose for using 6.3 instead of 12-6.3=5.7?
    I used 5.7. I think you will lose some marks. You might get some for the method though.
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    (Original post by GeneralOJB)
    Well that was one piss easy exam! Finished with like 30 minutes to spare. Full marks here I come.

    You sir.. are a ****.


    Stop bragging, for this I hope you don't, selfish ****
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    ya sorry it said decrese ur right- i did write that in the real one
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    (Original post by mr.suhk)
    the total resistance decreases of the circuit which means toal current increses so v across resistor increases
    correct! :d
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    (Original post by alistair_mallard)
    you sir.. Are a ****.


    Stop bragging, for this i hope you don't, selfish ****
    lol hahaaaaa.
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    so was this a hard or easy paper?
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    Did anyone on here get 6ohms for the other resistor for Q6? I know it's wrong but just want to know
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    (Original post by sheepshap)
    so was this a hard or easy paper?
    This paper was a bit easier. So I recon 56/70 is an A.:rolleyes:
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    My god, I've made so many silly mistakes!!
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    For the Y division, would it need to be 16V or could you make it more friendly numbers like 20V per division, it would still ensure it is show on the oscilloscope screen. Apart from that, a fair exam?
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    (Original post by Mr.Suhk)
    1) 20 p, 28 n, 18 e
    2) + 3.2 x 10 ^-19 J
    3) 3.99 x 10 ^ 6 C/kg
    4) feynman stuff ( d quark, W+ Boson, positron, electron neutrino)
    5) weak interaction
    6) B
    7) mass/charge/range etc
    8) I did baryon number and electron lepton number conservation but there are mpre
    9) big 6 marker, pretty easy
    10) particle/ antiparticle: i did electron and positron and said charge was opposite

    11) max and range of KE: photons energy dependant upon freq. as E= hf. Ekmax = hf - phi thereofore max KE exists. Range of ke's because more energy needed to remove deeper electrons etc.
    12) prove 1.8eV (pretty easy)
    13) what is threshold freq. : i got like 4.4 x 10 ^14 Hz
    14)increasing frequency increases max KE of emitted electrons as by equation or by photon energy route, your choice
    15) Double intensity doubles number of photons per second which doubles number of emitted electrons per second

    16) peak to peak = 128V
    17) peak = 64V
    18) Vrms = 45 V
    19) freq. = 100 Hz
    20) horizontal line at 45V
    21) time base: 2ms/div y sensitivity: 16V/div dunno about 3rd mark

    22) 4.2 x 2.5 = 6.3V
    23) 12- 6.3 = 5.7V
    24) 5.7 / 2 = 2.85A
    25) 4.2 - 2.85 = 1.35 A
    26) R = 5.7 / 1.35 = 4.2
    27) I said total R is 1.4 but if it incuded internal resistance then it was 2.9 ohms
    28)think something after but forgot sorry

    29) current = 6/ (50 + 35 + 5 ) x 1000 = 6.7 x 10 ^-5 A
    30) V = 0.33V
    31) increas intensity decreases toatl resistance which increases total current thereofre voltemeter value is greater (alternatives possible)
    32) 30000 ohms
    I think question 14 asked what would happen if the frequency decreased not increased. Am I wrong?
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    I did better than I expected.

    I Will probably have to resit it next year though. :/
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    (Original post by `Jts)
    I did better than I expected.

    I Will probably have to resit it next year though. :/
    In June? Do not take the risk....
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    Does anyone know roughly how many marks Q6&7were for the paper? Think I messed up them both but think the rest went well :/
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    1) 20 p, 28 n, 18 e
    2) + 3.2 x 10 ^-19 J
    3) 3.99 x 10 ^ 6 C/kg
    4) feynman stuff ( d quark, W+ Boson, positron, electron neutrino)
    5) weak interaction
    6) B
    7) mass/charge/range etc
    8) I did baryon number and electron lepton number conservation but there are mpre
    9) big 6 marker, pretty easy
    10) particle/ antiparticle: i did electron and positron and said charge was opposite

    11) max and range of KE: photons energy dependant upon freq. as E= hf. Ekmax = hf - phi thereofore max KE exists. Range of ke's because more energy needed to remove deeper electrons etc.
    12) prove 1.8eV (pretty easy)
    13) what is threshold freq. : i got like 4.4 x 10 ^14 Hz
    14)decreasing frequency decreases max KE of emitted electrons as by equation or by photon energy route, your choice
    15) Double intensity doubles number of photons per second which doubles number of emitted electrons per second

    16) peak to peak = 128V
    17) peak = 64V
    18) Vrms = 45 V
    19) freq. = 100 Hz
    20) horizontal line at 45V
    21) time base: 2ms/div y sensitivity: 16V/div dunno about 3rd mark

    22) 4.2 x 2.5 = 6.3V
    23) 12- 6.3 = 5.7V
    24) 5.7 / 2 = 2.85A
    25) 4.2 - 2.85 = 1.35 A
    26) R = 5.7 / 1.35 = 4.2
    27) I said total R is 1.4 but if it incuded internal resistance then it was 2.9 ohms
    28)power dissipated: comes to total of 50.4V, SAME AS POWER GOING IN FROM BATTERY, none lost altogether therefore conserved

    29) current = 6/ (50 + 35 + 5 ) x 1000 = 6.7 x 10 ^-5 A
    30) V = 0.33V
    31) increas intensity decreases toatl resistance which increases total current thereofre voltemeter value is greater (alternatives possible)
    32) 30000 ohms
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    (Original post by Alistair_Mallard)
    You sir.. are a ****.


    Stop bragging, for this I hope you don't, selfish ****
    Aw, did this exam make your wee brain hurt? Bless..
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    (Original post by x-Sophie-x)
    How was the photon and W+ boson different?I said the photon is the exchange particle in electromagnetic interactions, and W+ was the exchange particle in weak interactions but I had no idea Posted from TSR Mobile
    Which question was this?
 
 
 
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