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    (Original post by physicsmaths)
    Diagram=sorted.


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    Hardest edexcel paper?
    GOt any?
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    (Original post by TeeEm)
    there are some at this link .
    http://madasmaths.com/archive/maths_...revolution.pdf
    ..
    sorry I cannot give you question number because I am teaching at the moment
    Cheers!!! If I finish all the papers would I have done these or are these separate


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    (Original post by Zenarthra)
    Hardest edexcel paper?
    GOt any?
    Ive only done june 14 and jube 13R so not sure.


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    (Original post by physicsmaths)
    Ive only done june 14 and jube 13R so not sure.


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    DId you check the ms for C3?
    75/75, im quite pleased
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    (Original post by Zenarthra)
    DId you check the ms for C3?
    75/75, im quite pleased
    Yh, same 75/75.


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    (Original post by physicsmaths)
    Yh, same 75/75.


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    WHat practice are you doing for C4?
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    (Original post by Zenarthra)
    WHat practice are you doing for C4?
    Nothing, same as C3.
    Well technically I have been doing very hard maths for months so i dont need to prepare for C3/4 at all.


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    Why are the limits of this integral the other way around? (Part b)

    I got the right answer in absolute terms, 20pi, but it came out negative.
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    (Original post by Zenarthra)
    DId you check the ms for C3?
    75/75, im quite pleased
    Very well done
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    (Original post by SeanFM)
    Very well done
    thanks
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    (Original post by physicsmaths)
    Nothing, same as C3.
    Well technically I have been doing very hard maths for months so i dont need to prepare for C3/4 at all.


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    That's not very wise.
    Even people scoring S's on STEP dont get full UMS in FP modules.
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    (Original post by Zenarthra)
    That's not very wise.
    Even people scoring S's on STEP dont get full UMS in FP modules.
    I dont need full UMS lol. I need an 80 in C4 and 80 in FP3.


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    Can anyone help me get this into the form N = 5000 - Ate^{-kt} (where A is a positive constant)?

    The mark scheme says my first step in the image attached is correct but I don't get how the e ends up moving from the denominator? Thanks
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    (Original post by grn)
    Can anyone help me get this into the form N = 5000 - Ate^{-kt} (where A is a positive constant)?

    The mark scheme says my first step in the image attached is correct but I don't get how the e ends up moving from the denominator? Thanks
    Bring e part to the top. Let 1/e^c=A


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    (Original post by grn)
    Can anyone help me get this into the form N = 5000 - Ate^{-kt} (where A is a positive constant)?

    The mark scheme says my first step in the image attached is correct but I don't get how the e ends up moving from the denominator? Thanks
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    (Original post by physicsmaths)
    Bring e part to the top. Let 1/e^c=A


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    Cool, I just got mixed up thinking you aren't able to bring the e up, but since it has an exponent it's fine? Anyway thank you
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    (Original post by IWantSomeMushu)
    Why are the limits of this integral the other way around? (Part b)

    I got the right answer in absolute terms, 20pi, but it came out negative.
    I have also tried this question and got a negative answer using the method Area=4*(area of first quadrant)

    Tbh I have no idea what's happening here :/
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    C4 Grade Boundaries
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  1. File Type: pdf C4 GRADE BOUNDARIES.pdf (134.5 KB, 172 views)
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    (Original post by Gome44)
    I have also tried this question and got a negative answer using the method Area=4*(area of first quadrant)

    Tbh I have no idea what's happening here :/
    I did the four quadrant method as well!

    I really want to know what's going on here...
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    (Original post by IWantSomeMushu)
    Why are the limits of this integral the other way around? (Part b)

    I got the right answer in absolute terms, 20pi, but it came out negative.
    (Original post by Gome44)
    I have also tried this question and got a negative answer using the method Area=4*(area of first quadrant)

    Tbh I have no idea what's happening here :/
    Haven't done C4 in awhile so I hope I'm not talking garbage here. I believe the limits are the other way around to what you'd intuitively believe because at t=0 you are at (5,0) and at t=pi/2 you are at (0,4). As you know from normal integration to find the area under a curve you need to have the upper limit being the large x-coordinate, otherwise you get a negative value

    trivial e.g. if you want to find the area under y=1 between x=1 and 2 you have 2 as the upper limit and 1 as the lower limit, the other way around gives you -1 rather than +1 for the area. So similarly in your question t=0 gives you the larger x-coordinate rather than t=pi/2, so t=0 is your upper limit.

    Hope I made sense! (and hope that I am remembering C4 correctly also :P )
 
 
 
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