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# Edexcel S1 - 15th June, 2016 [Exam Discussion] Watch

1. The mean stayed the same, no? I checked it on my calculator

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2. (Original post by iMacJack)
The mean stayed the same, no? I checked it on my calculator

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You checked wrong then. It slightly decreases
3. (Original post by bobbutitii)
all of them
Probably not
4. (Original post by tammymxx)
Can anyonw walk me thru how they got their answer for Rach and Sarahs q
Sure, you use the brain i hope you have
5. Can somebody link me to an unofficial mark scheme please
6. (Original post by cmrol)
Probably not
probably yes
7. (Original post by bobbutitii)
all of them
Thank you very much for your lovely reply(!)

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8. (Original post by bobbutitii)
all of them
Nah sometimes you get dM1 marks, so a method mark
9. (Original post by Pikki1234)
Thank you very much for your lovely reply(!)

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anytime g xxxxxxx
10. (Original post by googleit)
You checked wrong then. It slightly decreases
thats what he is saying
11. (Original post by Piers456)
Nah sometimes you get dM1 marks, so a method mark
Yeah but for a worst case scenario, you assume 0 marks for now
12. (Original post by bobbutitii)
probably yes
I think that you would at least get one mark for correct method for generating a z value maybe one for using the table correctly.
13. Nope, the mean stayed the same. If you add something that is the mean, it's going to stay the same. Checking on the calculator only confirms the assumption.

The standard deviation does, however change. I believe it decreases as you are reducing the spread of data in this circumstance.

(Original post by googleit)
You checked wrong then. It slightly decreases
14. Guys if i got my value of k correct , however i messed up my width , therefore i got incorrect answer for height , even though my method is correct , how many marks will I lose out of 3 ?
15. (Original post by googleit)
The mean DECREASED guys, not stayed the same, we're dealing with classes here. The value of 3.43 will add one to the frequency of the 3-3.5 class. The way we work out the estimate is to multiply the midpoint of the class by the frequency. Hence, since the midpoint of this class is 3.25, which is lower than the mean, the mean decreases.
You could have also done the actual calculation to check, the mean decreased

EDIT: I'll explain this better. The mean before the added values was 3.43. Now there's an added value of 3.43. This adds one to the frequency of 3-3.5 class. In working out the value of the mean, you have to multiply mid point by frequency. Hence, you don't actually deal with 3.43 but rather 3.25, the mid point of the class. Since this value is less than 3.43 the mean decreases.
Try the calculation out for yourself and please amend the unofficial mark schemes.
I think people were just rounding, who knows
16. (Original post by LukeB98)
Nope, the mean stayed the same. If you add something that is the mean, it's going to stay the same. Checking on the calculator only confirms the assumption.

The standard deviation does, however change. I believe it decreases as you are reducing the spread of data in this circumstance.
sorry professor
17. (Original post by Kawaii289)
thats what he is saying
No he's not, the 'no' he said translates to 'isn't it'? He thinks the mean stayed the same
18. (Original post by Pudge666)
Guys if i got my value of k correct , however i messed up my width , therefore i got incorrect answer for height , even though my method is correct , how many marks will I lose out of 3 ?
are you an idiot?
19. (Original post by googleit)
No he's not, the 'no' he said translates to 'isn't it'? He thinks the mean stayed the same
oh sozzy
20. (Original post by googleit)
The mean DECREASED guys, not stayed the same, we're dealing with classes here. The value of 3.43 will add one to the frequency of the 3-3.5 class. The way we work out the estimate is to multiply the midpoint of the class by the frequency. Hence, since the midpoint of this class is 3.25, which is lower than the mean, the mean decreases.
You could have also done the actual calculation to check, the mean decreased

EDIT: I'll explain this better. The mean before the added values was 3.43. Now there's an added value of 3.43. This adds one to the frequency of 3-3.5 class. In working out the value of the mean, you have to multiply mid point by frequency. Hence, you don't actually deal with 3.43 but rather 3.25, the mid point of the class. Since this value is less than 3.43 the mean decreases.
Try the calculation out for yourself and please amend the unofficial mark schemes.
I know what you're saying, but I took it to mean that the 3.43 was factored in exactly as it is, not added to a class in the table. So I'm still going with the mean staying the same.

Either way, it seems a bit ambiguous?

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