Maths year 11

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    Well done.

    Have a go at the other question's I've posted.
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    (Original post by z_o_e)
    How did this go?

    Shall I added 5 root 4 & root 6?



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    Is it POSSIBLE to make 5\sqrt{5} + \sqrt{6} any simpler by any means of addition? If not, then no you don't add them.
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    (Original post by RDKGames)
    Is it POSSIBLE to make
    Unparseable or potentially dangerous latex formula. Error 4: no dvi output from LaTeX. It is likely that your formula contains syntax errors or worse.
    5\root{5} + \sqrt{6}
    any simpler by any means of addition? If not, then no you don't add them.
    So this is the final answer ?


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    (Original post by z_o_e)
    How did this go?

    Shall I added 5 root 4 & root 6?



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    Also, show me how you got 3\sqrt2 + 2\sqrt3 to equal 5\sqrt5?
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    (Original post by z_o_e)
    So this is the final answer ?


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    No. That's just simply a wrong answer. Refer to my post above ^
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    (Original post by RDKGames)
    Also, show me how you got 3\sqrt2 + 2\sqrt3 to equal 5\sqrt5?
    I added 3 + 2 inside and outside the root which got me 5 r 5

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    (Original post by z_o_e)
    I added 3 + 2 inside and outside the root which got me 5 r 5

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    What surd rule did you use for that?
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    (Original post by RDKGames)
    What surd rule did you use for that?
    I didn't use a rule

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    (Original post by z_o_e)
    I didn't use a rule

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    Precisely why your answer is wrong. You just guessed that's how it works.

    3\sqrt2 + 2\sqrt3 cannot be simplified any further.
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    (Original post by RDKGames)
    Precisely why your answer is wrong. You just guessed that's how it works.

    3\sqrt2 + 2\sqrt3 cannot be simplified any further.
    So what do I do to find the final answer?

    There's nothing else really left I think that's the final answer.

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    (Original post by z_o_e)
    So what do I do to find the final answer?

    There's nothing else really left I think that's the final answer.

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    Exactly. The final answer is indeed \sqrt6 + 2\sqrt3 + 3\sqrt 2 + 6
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    (Original post by RDKGames)
    Exactly. The final answer is indeed \sqrt6 + 2\sqrt3 + 3\sqrt 2 + 6
    So surds like that cannot be added?

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    (Original post by z_o_e)
    So surds like that cannot be added?

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    No. Square root of a number is the same as raising that number to the power of 1/2. This means that you would essentially be adding something like a^{\frac{1}{2}}+b^{\frac{1}{2}} into (a+b)^{\frac{1}{2}} which doesn't make sense because a and b are different bases and laws of indices do not work that like that.
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    (Original post by RDKGames)
    No. Square root of a number is the same as raising that number to the power of 1/2. This means that you would essentially be adding something like a^{\frac{1}{2}}+b^{\frac{1}{2}} into (a+b)^{\frac{1}{2}} which doesn't make sense because a and b are different bases and laws of indices do not work that like that.
    Oh thanks


    And how's this



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    (Original post by z_o_e)
    Oh thanks


    And how's this



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    Okay hang on. The method overall is correct. Check the numerator multiplication on the first line, and then check if the denominator on the second line is truly the same as (2+6\sqrt{10})(2-6\sqrt{10})
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    (Original post by RDKGames)
    Okay hang on. The method overall is correct. Check the numerator multiplication on the first line, and then check if the denominator on the second line is truly the same as (2+6\sqrt{10})(2-6\sqrt{10})
    I don't see anything wrong?

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    (Original post by z_o_e)
    I don't see anything wrong?

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    Okay. For the numerator, you have 8 on the first fraction and the (2 take 6 root 10) on the second, when you multiply the two fractions, you multiply the two numerators. So 8 times (2 take 6 root 10).

    For denominator, expand the brackets and see what you get. Compare this to what you've written.
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    (Original post by RDKGames)
    Okay. For the numerator, you have 8 on the first fraction and the (2 take 6 root 10) on the second, when you multiply the two fractions, you multiply the two numerators. So 8 times (2 take 6 root 10).

    For denominator, expand the brackets and see what you get. Compare this to what you've written.
    This?


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    Yeah you fixed the numerator. Now fix the denominator. Expand it and see what you get.
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    (Original post by RDKGames)
    Yeah you fixed the numerator. Now fix the denominator. Expand it and see what you get.
    I got this


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