Maths year 11

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    (Original post by z_o_e)
    I got this


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    Correct. You can make it even more simpler though.
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    (Original post by RDKGames)
    Correct. You can make it even more simpler though.
    Yeussssss.
    I'll have 2 more questions please

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    (Original post by z_o_e)
    Yeussssss.
    I'll have 2 more questions please

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    Sure, after you finish fully simplifying THAT one.
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    (Original post by RDKGames)
    Sure, after you finish fully simplifying THAT one.
    Simplify that?
    I'm not really sure.

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    (Original post by RDKGames)
    Sure, after you finish fully simplifying THAT one.
    Simplify that?
    I'm not really sure..

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    (Original post by z_o_e)
    Simplify that?
    I'm not really sure..

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    I'll give you an example; how can I simplify something like \displaystyle \frac{2+2a}{2}?
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    (Original post by RDKGames)
    I'll give you an example; how can I simplify something like \displaystyle \frac{2+2a}{2}?
    Cancel the top and bottom 2 and you're left with 2a

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    (Original post by z_o_e)
    Cancel the top and bottom 2 and you're left with 2a

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    Oh dear, you're gonna need to practice your fractions.

    Gonna skip the encouragement:

    \displaystyle \frac{16-48\sqrt{10}}{-356}

    Divide/multiply (doesn't matter which) top and bottom by -1

    \displaystyle \frac{48\sqrt{10} - 16}{356}

    Factorise the numerator as much as you can:

    \displaystyle \frac{16(3\sqrt{10}-1)}{356}

    You can rewrite this as:

    \displaystyle \frac{16}{356}(3\sqrt{10}-1)

    See how far you can simplify the fraction. The simplest it goes is:

    \displaystyle \frac{4}{89}(3\sqrt{10}-1)

    So final answer would be that. Or you can also rewrite it as:

    \displaystyle \frac{4(3\sqrt{10}-1)}{89}

    which leads to

    \displaystyle \frac{12\sqrt{10}-4}{89}
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    (Original post by z_o_e)
    Cancel the top and bottom 2 and you're left with 2a

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    Add these fractions:

     \frac{1}{2}+\frac{1}{2}

    \frac{1}{2}+\frac{1}{3}

    \frac{5}{2}+\frac{1}{5}

    \frac{3}{4}+\frac{7}{2}

    \frac{6}{2}+\frac{2}{6}

    \frac{b}{2}+\frac{a}{a}

    \frac{a}{b}+\frac{c}{d}

    \frac{a+1}{2}+\frac{1}{2}

    \frac{a}{b+1}+\frac{1}{2}

    \frac{2a}{2b+2}+\frac{2}{8}
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    (Original post by RDKGames)
    Add these fractions:

     \frac{1}{2}+\frac{1}{2}

    \frac{1}{2}+\frac{1}{3}

    \frac{5}{2}+\frac{1}{5}

    \frac{3}{4}+\frac{7}{2}

    \frac{6}{2}+\frac{2}{6}

    \frac{b}{2}+\frac{a}{a}

    \frac{a}{b}+\frac{c}{d}

    \frac{a+1}{2}+\frac{1}{2}

    \frac{a}{b+1}+\frac{1}{2}

    \frac{2a}{2b+2}+\frac{2}{8}
    I'm not sure about a and b I think after question 6

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    (Original post by z_o_e)
    I'm not sure about a and b I think after question 6

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    How did you add the previous fractions? You add these ones just the same way.
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    (Original post by RDKGames)
    How did you add the previous fractions? You add these ones just the same way.


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    Good, but for Q1 you can simplify that fraction and for Q5 you added the the denominators.
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    Use a Mathswatch CD , not sure if you're teachers can give you one for free (Worth a shot asking). They do step by step questions and answers and they make it seem easy.
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    (Original post by RDKGames)
    Good, but for Q1 you can simplify that fraction and for Q5 you added the the denominators.
    Oh yea

    How do I do the others ?

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    (Original post by z_o_e)
    Oh yea

    How do I do the others ?

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    In the same way; make the denominators the same before adding them.
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    (Original post by RDKGames)
    In the same way; make the denominators the same before adding them.
    Yep did this


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    (Original post by z_o_e)
    Yep did this


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    Yep, you got the right idea. You can proceed to simplify.
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    ba+2a=2a^2b ??? You're not multiplying them here.
 
 
 
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