You are Here: Home >< Maths

# MAT Prep Thread - 2nd November 2016 watch

1. I got e for number 10 MC--I believe the answer was if PI(n) = 2, you can get every last digit, which I thought was false because you can't get 4, because 2 is the only even prime. I believe the question was asking which answer choice was false.
2. (Original post by pressurize)
I got e for number 10 MC--I believe the answer was if PI(n) = 2, you can get every last digit, which I thought was false because you can't get 4, because 2 is the only even prime. I believe the question was asking which answer choice was false.
isn't P(14) = 2 (since 14 = 2 * 7)
and x(14) = 4

?

or did i misread what P(x) was
3. (Original post by pressurize)
I got e for number 10 MC--I believe the answer was if PI(n) = 2, you can get every last digit, which I thought was false because you can't get 4, because 2 is the only even prime. I believe the question was asking which answer choice was false.
if you try 11*4 you get 2 distinct factors
4. You're right...oops
5. (Original post by m0.4444)
if you try 11*4 you get 2 distinct factors
The answer to j was b
6. (Original post by Amitbalter)
The answer to j was b
I think i put b, not 100% sure.
7. (Original post by pressurize)
You're right...oops
Ive made tons of silly mistakes too. There more annoying when you understand the question but mess it up anyways.
8. Is it possible to get partial credit on a specific part in a long problem? slash is 80 a decent score (im american)
9. (Original post by Amitbalter)
The answer to j was b
Yes i got b
10. (Original post by pressurize)
Is it possible to get partial credit on a specific part in a long problem? slash is 80 a decent score (im american)
80 will be a fantastic score, and yes.
11. Well, after looking at this I think I got around 60, hopefully it's good enough
12. (Original post by Quido)
Well, after looking at this I think I got around 60, hopefully it's good enough
I think I got around 65 to 70. I hope it doesn't go down any further as this forum gets longer.
13. (Original post by m0.4444)
I think I got around 65 to 70. I hope it doesn't go down any further as this forum gets longer.
I'm just gonna have to avoid this thread for a while haha
14. Is anyone gonna upload an unofficial mark scheme?
15. (Original post by Quido)
I'm just gonna have to avoid this thread for a while haha
I am pretty much non-productive unless i see this thread. But I wish I would just stay away from it.
16. (Original post by RuairiMorrissey)
I got 10 combinations but 107 and 117 for c? I couldn't explain why they were the values though.
If you calculate them all carefully, they all come to 107. This rhymes with the fact that the function A^n(B^m(x))= (2^n)(3^n)x+(2^n*3^n - 1) which is used in the last question. Note that 107 = 108-1

The latter also shows that it is impossible to reach 214x+96 (or whatever it was) since for each compound function added, the constant is > 1/2 the x coefficient. Hence, since 96 < 1/2 of 214, it is impossible with any sum.
17. (Original post by DavidBick)
If you calculate them all carefully, they all come to 107. This rhymes with the fact that the function A^n(B^m(x))= (2^n)(3^n)x+(2^n*3^n - 1) which is used in the last question. Note that 107 = 108-1

The latter also shows that it is impossible to reach 214x+96 (or whatever it was) since for each compound function added, the constant is > 1/2 the x coefficient. Hence, since 96 < 1/2 of 214, it is impossible with any sum.
How many marks do you think those two parts were?
18. (Original post by DavidBick)
If you calculate them all carefully, they all come to 107. This rhymes with the fact that the function A^n(B^m(x))= (2^n)(3^n)x+(2^n*3^n - 1) which is used in the last question. Note that 107 = 108-1

The latter also shows that it is impossible to reach 214x+96 (or whatever it was) since for each compound function added, the constant is > 1/2 the x coefficient. Hence, since 96 < 1/2 of 214, it is impossible with any sum.
They didn't all come to 107.
19. (Original post by DavidBick)
If you calculate them all carefully, they all come to 107. This rhymes with the fact that the function A^n(B^m(x))= (2^n)(3^n)x+(2^n*3^n - 1) which is used in the last question. Note that 107 = 108-1

The latter also shows that it is impossible to reach 214x+96 (or whatever it was) since for each compound function added, the constant is > 1/2 the x coefficient. Hence, since 96 < 1/2 of 214, it is impossible with any sum.
I got the same result but said 1/6 instead of 1/2 since m and n both are positive ints.
20. I feel like I've not done well enough to get an interview : (

### Related university courses

TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Updated: October 30, 2017
Today on TSR

### Exam Jam 2018

All day biology and life sciences revision thread

### Solo - A Star Wars Story

Poll
Useful resources

Can you help? Study help unanswered threadsStudy Help rules and posting guidelinesLaTex guide for writing equations on TSR

## Groups associated with this forum:

View associated groups

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE