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# Official OCR A G481 mechanics 20th May 2013 Watch

1. (Original post by OllieGCSEs)
This answer is more appropriate for seatbelts and airbags i think - crumple zones are designe to absorb some of the energy from a collision

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I don't know, I made these notes around the mark scheme as this question came up in 2010 sometime
2. (Original post by yodawg321)
I don't know, I made these notes around the mark scheme as this question came up in 2010 sometime
A seatbelt question came up in May 2010, maybe you've confused the two - i'm not saying what you mentioned is wrong, however it's a perfect answer for an airbag or seatbelt question, so you might want to throw in 'absorbs energy' just to set it aside from the airbag/seatbelt answers

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3. How do you define the joule and watt?
4. Any videos for this module? Anything similar what examsolutions.net does for maths but for physics mechanics?
5. (Original post by rfka)
How do you define the joule and watt?
The joule is the unit of energy and is the work done when a force of one newton moves its point of application by one metre. i.e. 1J = 1N *1m

A watt is a measure of power (work done per unit time) and so 1W = 1J/1s or in words 1 Watt is when 1 joule is expended per second.

Added stuff for Ogley
Attached Files
6. C3 Revision.docx (38.3 KB, 189 views)
7. S1 Rev.docx (332.0 KB, 91 views)
8. Does anyone have any model answers for car safety chapter?
Such as crumple zone, seat belts, what effects braking distance etc. ?
9. (Original post by OllieGCSEs)
This answer is more appropriate for seatbelts and airbags i think - crumple zones are designed to absorb some of the energy from a collision

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that's pretty much what the answer says.... seatbelts are mostly about keeping you in the car so that you don't hit the windshield airbags are designed to slow you down gradually
10. (Original post by yodawg321)
Where does it say about series and parrallel in the spec? Can't find anything about it

http://www.ocr.org.uk/Images/81024-specification.pdf
I'm not sure. I remember seeing a few past questions on it and we always did an experiment on it in class. I think it is on the specification somewhere, where though is a mystery. Just make sure you know it..
11. (Original post by ChloeB43)
I'm not sure. I remember seeing a few past questions on it and we always did an experiment on it in class. I think it is on the specification somewhere, where though is a mystery. Just make sure you know it..
Under 1.3.4 it says:

Students can carry out experiments to find the relationship between force and extension for a single spring, springs in series or parallel, rubber, polythene strip, etc.

It doesn't say we need to understand to, but it is included.
12. (Original post by dakenSoren)
Hmmm from some gentle stalking I think we have a quite a bit in common: programming, computers, chemistry, maths, further maths, gym
You hoping to do CompSci or something at Uni?
haha yeah or electronics engineering.
it could be done though, i dont have the knowledge to do it
13. (Original post by dakenSoren)
Here is those long word question answers
i ****ing love you dude
14. (Original post by P!=NP)
Any videos for this module? Anything similar what examsolutions.net does for maths but for physics mechanics?
check the first page/post of the thread -.-
15. here you go *****ess
Attached Images
16. Mechanics Definitions.pdf (313.8 KB, 169 views)
17. I've been revising almost daily for this exam. Why can't I revise today?!?!?!!?!?!?!?!? Help someone
18. So what do you need to know for the springs in parallel and in series?
19. What formulas are not given in the exam?
20. (Original post by Vorsah)
What formulas are not given in the exam?
look up the ocr A physics data sheet, you'll see what you're given

does anyone know how to answer question 3)d)i)2) on june 2012?
21. (Original post by Kreayshawn)
look up the ocr A physics data sheet, you'll see what you're given

does anyone know how to answer question 3)d)i)2) on june 2012?
mgsintheta=ma so a=mgsintheta/m ----- a=gsintheta -- sintheta=a/g you just worked out a in the previous part and its just plug and chug from there
22. (Original post by blackstarz)
mgsintheta=ma so a=mgsintheta/m ----- a=gsintheta -- sintheta=a/g you just worked out a in the previous part and its just plug and chug from there
thanks that makes sense - mark scheme skipped putting "m" in either side of the equation so i was confused as to how they got there
23. Just read the examiners report, nobody got 60 in this exam in January!

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