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    (Original post by ionic285)
    last answer was k<-7.5 right? and what about the second to last question was stuck on that for ages, I ended up getting 3-+root21/2 or something for x but couldn't figure out how to get y

    I got -7.5 and 3+-root21/2 as well - I just added 3 to each one to get y
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    (Original post by Grindle97)
    I got the same as that apart from for 4 where i got y=22/7
    Yes i got 22/7 as well
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    For 11ii ) With regards to the coordinates of the intersection points for 2x^2 -5x -3 and x+3
    I did the following

    2x^2 -6x -6 = 0

    Then for the X coordinates i used the formula to give (6 +/- root 84) /4
    would that get any marks, i forgot to divide through by 2.

    Thanks
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    (Original post by Octavian_190)
    I'm just going to list my answers to see if people agree with them.... (They may not be in the exact order and I may have fOr gotten some, but I will try and write down the question bit too)
    1. 3^0= 1
    9^3/2 =27
    (4/5)^-2= 25/16
    2. (1-2x)/4>3 = x>-11/2
    3. (5c^2d)^3 / (2c^4)/ d^5 = 250c^10d^-2


    4. One with intercepts of two lines x=9/7 and y=22/9
    5. Root 50 + 2root8= 11root2


    ii. Other surds question= 2+root3

    6.
    Remainder of f(2) is 11 remainder of (x+1) is 11 f(x)= x^3+ax+c
    A=-2 and c=7

    7. Expand (1-5x)^4
    1-20x+150x^2- 500x^3 + 625x^4

    8. Find minimum and then Sketch graph of (x-2)^2=9
    Minimum at (2,-9)
    Crosses x axis at -1 and 5 and y axis at -5
    I think 4 should be x = 9/7 and x = 22/7

    Also could someone do this for Section B?
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    Does anyone think that the grade boundaries might be slightly lower than usual?
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    Feel free to contribute to the unofficial mark scheme: https://docs.google.com/document/d/1...it?usp=sharing
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    (Original post by xoharrypotter)
    2 and -1/2 ?
    Yeah I got 2 and -1/2
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    (Original post by Daniel Burridge)
    You have got question 1ii wrong it was + or - 27
    no it was 27
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    (Original post by The Moo)
    Does anyone think that the grade boundaries might be slightly lower than usual?
    Yeah I reckon they will be around 57/58 for an A.

    I was resitting this and still found certain parts tricky.
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    On the last question i got k > 3/2
    6^2 - (4x3(3+k)) < 0
    36 - 24 - 8k < 0
    12 -8k < 0
    k > 12/8 simplified to 3/2?
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    How did everyone do the remainder question? My answers were completely wrong
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    (Original post by juicebox55)
    On the last question i got k > 3/2
    6^2 - (4x3(3+k)) < 0
    36 - 24 - 8k < 0
    12 -8k < 0
    k > 12/8 simplified to 3/2?
    It was 36--24 +8k <0
    So k<-60/8
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    (Original post by aaaargggi)
    no it was 27
    9^(3/2)=9^(1/2))^3 and 9^1/2 can be + or - 3
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    (Original post by Realforce)
    Feel free to contribute to the unofficial mark scheme: https://docs.google.com/document/d/1...it?usp=sharing
    The collaboration isn't exactly going well
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    http://www.ocr.org.uk/Images/246983-...ludes-gcse.pdf grade boundaries for last year as a guide
    A: 64
    B: 58
    C: 52
    D: 47
    E: 42
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    I got that but also did an stupid working out error and got k< -60/8 and k>-60/8 will is till get most of the marks for correct workings
    (Original post by aaaargggi)
    It was 36--24 +8k <0
    So k<-60/8
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    Anyone get a copy of the google docs mark scheme before it got raided?
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    who got 4y=3x+22?
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    (Original post by aaaargggi)
    It was 36--24 +8k <0
    So k<-60/8
    The last part of the full equation was -3-k, i took out the minus so i got -(3+k) so c=3+k not -3-k
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    Did anyone get an answer like (x+4 root 3) ?
 
 
 
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