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# [Official Thread] OCR MEI AS Mathematics 2016 (C1, C2 & S1) Watch

1. (Original post by ionic285)
last answer was k<-7.5 right? and what about the second to last question was stuck on that for ages, I ended up getting 3-+root21/2 or something for x but couldn't figure out how to get y

I got -7.5 and 3+-root21/2 as well - I just added 3 to each one to get y
2. (Original post by Grindle97)
I got the same as that apart from for 4 where i got y=22/7
Yes i got 22/7 as well
3. For 11ii ) With regards to the coordinates of the intersection points for 2x^2 -5x -3 and x+3
I did the following

2x^2 -6x -6 = 0

Then for the X coordinates i used the formula to give (6 +/- root 84) /4
would that get any marks, i forgot to divide through by 2.

Thanks
4. (Original post by Octavian_190)
I'm just going to list my answers to see if people agree with them.... (They may not be in the exact order and I may have fOr gotten some, but I will try and write down the question bit too)
1. 3^0= 1
9^3/2 =27
(4/5)^-2= 25/16
2. (1-2x)/4>3 = x>-11/2
3. (5c^2d)^3 / (2c^4)/ d^5 = 250c^10d^-2

4. One with intercepts of two lines x=9/7 and y=22/9
5. Root 50 + 2root8= 11root2

ii. Other surds question= 2+root3

6.
Remainder of f(2) is 11 remainder of (x+1) is 11 f(x)= x^3+ax+c
A=-2 and c=7

7. Expand (1-5x)^4
1-20x+150x^2- 500x^3 + 625x^4

8. Find minimum and then Sketch graph of (x-2)^2=9
Minimum at (2,-9)
Crosses x axis at -1 and 5 and y axis at -5
I think 4 should be x = 9/7 and x = 22/7

Also could someone do this for Section B?
5. Does anyone think that the grade boundaries might be slightly lower than usual?
6. Feel free to contribute to the unofficial mark scheme: https://docs.google.com/document/d/1...it?usp=sharing
7. (Original post by xoharrypotter)
2 and -1/2 ?
Yeah I got 2 and -1/2
8. (Original post by Daniel Burridge)
You have got question 1ii wrong it was + or - 27
no it was 27
9. (Original post by The Moo)
Does anyone think that the grade boundaries might be slightly lower than usual?
Yeah I reckon they will be around 57/58 for an A.

I was resitting this and still found certain parts tricky.
10. On the last question i got k > 3/2
6^2 - (4x3(3+k)) < 0
36 - 24 - 8k < 0
12 -8k < 0
k > 12/8 simplified to 3/2?
11. How did everyone do the remainder question? My answers were completely wrong
12. (Original post by juicebox55)
On the last question i got k > 3/2
6^2 - (4x3(3+k)) < 0
36 - 24 - 8k < 0
12 -8k < 0
k > 12/8 simplified to 3/2?
It was 36--24 +8k <0
So k<-60/8
13. (Original post by aaaargggi)
no it was 27
9^(3/2)=9^(1/2))^3 and 9^1/2 can be + or - 3
14. (Original post by Realforce)
Feel free to contribute to the unofficial mark scheme: https://docs.google.com/document/d/1...it?usp=sharing
The collaboration isn't exactly going well
15. http://www.ocr.org.uk/Images/246983-...ludes-gcse.pdf grade boundaries for last year as a guide
A: 64
B: 58
C: 52
D: 47
E: 42
16. I got that but also did an stupid working out error and got k< -60/8 and k>-60/8 will is till get most of the marks for correct workings
(Original post by aaaargggi)
It was 36--24 +8k <0
So k<-60/8
17. Anyone get a copy of the google docs mark scheme before it got raided?
18. who got 4y=3x+22?
19. (Original post by aaaargggi)
It was 36--24 +8k <0
So k<-60/8
The last part of the full equation was -3-k, i took out the minus so i got -(3+k) so c=3+k not -3-k
20. Did anyone get an answer like (x+4 root 3) ?

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