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Edexcel International A level (IAL): Physics Unit 6 (WPH06) - 19th May, 2016 - PM Watch

1. (Original post by Zacken)
I think all of that is wrong.
Is there ecf on any of that? And why cant we multiple length by gradient
2. (Original post by amohsen982)
Is there ecf on any of that? And why cant we multiple length by gradient
Yep, definitely.

Not sure what you mean. It's not necessarily a graph that goes through the origin.
3. (Original post by Zacken)
Yep, definitely.

Not sure what you mean. It's not necessarily a graph that goes through the origin.
hey the V2 against V2-V1 graph for which I drew a sketch, I passed thorugh he orgin cause c=0.
What did you write for the last to points in that question? for accuracy and precaution?
4. (Original post by AvWOW)
hey the V2 against V2-V1 graph for which I drew a sketch, I passed thorugh he orgin cause c=0.
Yes, that's correct (but not necessary).

What did you write for the last to points in that question? for accuracy and precaution?
Accuracy: letting the capacitor charge up fully

Precaution: checking the orientation of the capacitor in order to avoid overheating.
5. Imma cry someone please link me when theres an unofficial mark scheme
6. (Original post by Zacken)
Yes, that's correct (but not necessary).

Accuracy: letting the capacitor charge up fully

Precaution: checking the orientation of the capacitor in order to avoid overheating.
I wrote the same precaution (connecting the capacitor to the correct terminals) but I wrote repeat and find mean for accuracy... It might be wrong cause you don't repeat for circuits normally as it could heatup right? smh
7. Guys was the gradient suppose to be positive or negative? I got -ve which cancelled as grad= -p?
8. (Original post by Ha97)
Guys was the gradient suppose to be positive or negative? I got -ve which cancelled as grad= -p?
9. (Original post by Zacken)
Yes, that's correct (but not necessary).

Accuracy: letting the capacitor charge up fully

Precaution: checking the orientation of the capacitor in order to avoid overheating.
Zacken do you think my graph would get any marks? (Look a few posts above)
10. (Original post by Zacken)
Oh cool..
Btw what was your value of e?
11. (Original post by The_Big_E)
Zacken do you think my graph would get any marks? (Look a few posts above)
Yes, it's fine.

(Original post by Ha97)
Oh cool..
Btw what was your value of e?
1.55.
12. (Original post by Zacken)
Yes, it's fine.

1.55.
got 1.51 that looks wring though, anyways the unit for the gradient was K or K^-1
13. (Original post by Ha97)
got 1.51 that looks wring though, anyways the unit for the gradient was K or K^-1
K^(-1).
14. (Original post by Zacken)
K^(-1).
Reading to be taken for the capacitor question and the arrangement of the voltmeter?
15. (Original post by Zacken)
K^(-1).
ohh... I said it was K.... wasn't it lnA against K^-1
16. (Original post by Zacken)
K^(-1).
Shouldn't it be K ??, because then when multiplied by the boltzmann constant it would remove the K^-1 in it thus the final unit would be C instead of Ck^-2
17. (Original post by Ha97)
got 1.51 that looks wring though, anyways the unit for the gradient was K or K^-1
(Original post by AvWOW)
ohh... I said it was K.... wasn't it lnA against K^-1
(Original post by Omar2365)
Shouldn't it be K, because then when multiplied by the boltzmann constant it would remove the K^-1 in it thus the final unit would be C instead of Ck^-2
Sorry - yes, I thought you were asking about the unit for the axes. The unit for the gradient is K (although that doesn't matter) as long as you say the unit of p is also K.
18. Expected boundaries? This paper was filled with 1 markers and made silly mistakes in them :¡ i think it will be lower maybe 28 for an A? What do u guys think?

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19. I got 1.95x10^-19 for the charge.... everyone seems to have gotten something along the line of 1.55x10^-19
O_O pooping bricks here
20. What did you guys write for the readings to be taken for the capacitor and the arrangement if the voltmeter? 2 and 1 mark respectively

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