x Turn on thread page Beta
 You are Here: Home >< Maths

OCR C2 exam Wed 25th May watch

1. anyone know the exact question for 7 ii 4 marks
2. (Original post by proximity)
anyone know the exact question for 7 ii 4 marks
7ii was 3 marks - Hence find the roots of the equation f(x)=0
3. sorry i meant the actual equation you had to integrate for 4 marks from -1 to 3 or something
5. (Original post by proximity)
sorry i meant the actual equation you had to integrate for 4 marks from -1 to 3 or something
x^4-4x^3-2x^3+12x+9
6. Do people think i will get any marks on q9 for doing 180/a - (what one of the values was)= other value
(right method but used 180/a instead of pi/a the whole way throuhg..)
7. (Original post by bestrevision23)
Do people think i will get any marks on q9 for doing 180/a - (what one of the values was)= other value
(right method but used 180/a instead of pi/a the whole way throuhg..)
Probably like 2 method marks?
8. (Original post by AlfieH)
Probably like 2 method marks?
do u remember what it was out of?
9. (Original post by Saching99)
The trapezium rule.
10. (Original post by bestrevision23)
do u remember what it was out of?
4 marks
11. (Original post by student199919)
i think i got something like 38, i'm probably wrong
Yes boss, I got N=38 and so did all my mates
12. (Original post by AlfieH)
I am gonna start an unofficial mark scheme - I think this is about correct!

1i) 10cm (2m)

1ii) 5.04cm (2m)

2i) 3/10π (2m)

2ii) 20.4cm (3m)

3i) 27+27kx+9k^2x^2+k^3x^3 (4m)

3ii) +/-√3 (2m)

4i) log base 3 x^2/x+4 (2m)

4ii) x=12 (4m)

5a) x^4/2-x^3+2x^2-6x (3m)

5bi) -6/a+2/a^2+4 (4m)

5bii) 4 (1m)

6i) k=91 (3m)

6ii) Sum of terms = 978 (2m)

6iii) N=38 (6m)

7i) R=0, quotient = x^2-4x+3 (3m)

7ii) (x+1), (x-1), (x-3) (3m)

7iii) Prove (2m)

7iv) 512/15 (4m)

8i) Translation 2 units in positive x direction (2m)

8ii) Stretch scale factor 1/9 in y direction (2m)

8iii) Sketch, crosses y at (0,1/9) (2m)

8iv) x=6.73 (3m)

8v) Area =9.60 (3m)

9i) 2π/a (1m)

9ii) a=5/3 and k=√3/2 (3m)

9iii) π/3a and ? (4m)
4ii) I got 12 and other root as well. Are we supposed to leave another root?
9ii) the given values of x were pi/5 and 2pi/5 and hence periodicity is pi/5. Equating this to 2pi/a gives a=10 and k=0. Can anyone explain to me flaw in the argument.
9iii) pi/3a and 4pi/3a

My other answers match with yours as far as I remember.
13. (Original post by tangotangopapa2)
4ii) I got 12 and other root as well. Are we supposed to leave another root?
9ii) the given values of x were pi/5 and 2pi/5 and hence periodicity is pi/5. Equating this to 2pi/a gives a=10 and k=0. Can anyone explain to me flaw in the argument.
9iii) pi/3a and 4pi/3a

My other answers match with yours as far as I remember.
Periodicity was 6pi/5 and equating to 2pi/a= 5/3
14. (Original post by tangotangopapa2)
4ii) I got 12 and other root as well. Are we supposed to leave another root?
9ii) the given values of x were pi/5 and 2pi/5 and hence periodicity is pi/5. Equating this to 2pi/a gives a=10 and k=0. Can anyone explain to me flaw in the argument.
9iii) pi/3a and 4pi/3a

My other answers match with yours as far as I remember.
You can't log a negative number (-3)
15. (Original post by tangotangopapa2)
4ii) I got 12 and other root as well. Are we supposed to leave another root?
9ii) the given values of x were pi/5 and 2pi/5 and hence periodicity is pi/5. Equating this to 2pi/a gives a=10 and k=0. Can anyone explain to me flaw in the argument.
9iii) pi/3a and 4pi/3a

My other answers match with yours as far as I remember.
If you plugged in the negative value you get a syntax error so it was just 12.

16. (Original post by SGHD26716)
You can't log a negative number (-3)
It isn't a negative number if you apply the multiplying 2 as an indice before logging
17. (Original post by tangotangopapa2)
4ii) I got 12 and other root as well. Are we supposed to leave another root?
9ii) the given values of x were pi/5 and 2pi/5 and hence periodicity is pi/5. Equating this to 2pi/a gives a=10 and k=0. Can anyone explain to me flaw in the argument.
9iii) pi/3a and 4pi/3a

My other answers match with yours as far as I remember.
I got 12 and -3
18. (Original post by h3rmit)
It isn't a negative number if you apply the multiplying 2 as an indice before logging
x^ isn't negative, but x is. The original equation was 2logx something.
19. K>0
20. Can someone plsss confirm , for the sum of U > sum of w , did u have to find a new first number and difference for the arithemetic because it was Un+1 it was just Un???

Also wasnt the period PIE/ A?

TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Updated: May 25, 2016
Today on TSR

Four things top students are doing

Over the Easter break

Her parents made her dump me

Poll
Useful resources

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE