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jonny5263
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#121
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#121
W h a t w a s t h e 1st p a r t o f l o g question........................ ...........................
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................
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AstarAstarA
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#122
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#122
(Original post by Chrisj725)
What was that on the log question about just solving mathematically or graphically?
Graphically means using a graphing calculator to read off the value of the exponential.

Numerically means by finding it using trial and error (some students do this if they have no clue)
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AstarAstarA
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#123
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#123
(Original post by civ1)
yeah a really silly miststake. hiw many marks was the question. and how many will i lose do you think??
I think it was 4
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swiftietay99
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#124
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#124
(Original post by FakeDumbledore)
Unlucky mate I've seen the official mark scheme and a few of these are wrong :/
Better luck next year in your resit...
what "official" mark scheme then? kindly enlighten us all.
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NotNotBatman
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#125
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#125
(Original post by 10moxoma)
how do you rearrange in to find b in terms of a?
 log_3{(3b+1)} -log_3{(a-2)} = -1

 log_3{(\frac{3b+1}{a-2})} =-1

 3^{-1} =\frac{3b+1}{a-2}

 \frac{a-2}{3} =3b+1

 a-2 =9b+3

 b = \frac{a-5}{9}
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civ1
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#126
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#126
(Original post by AstarAstarA)
I think it was 4
so how many will i lose??
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edis1122
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#127
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#127
guys the equation of the tangent to the circle wasn't that 3y+5x-89=0
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Chrisj725
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#128
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#128
(Original post by AstarAstarA)
Graphically means using a graphing calculator to read off the value of the exponential.

Numerically means by finding it using trial and error (some students do this if they have no clue)
Brilliant thank you, I answered it easily but thought I was missing something!
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Benevo
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#129
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#129
Put it on here then
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N^3
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#130
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#130
(Original post by NotNotBatman)
 log_3{(3b+1)} -log_3{(a-2)} = -1

 log_3{(\frac{3b+1}{a-2})} =-1

 3^{-1} =\frac{3b+1}{a-2}

 \frac{a-2}{3} =3b+1

 a-2 =9b+3

 b = \frac{a-5}{9}
Where have you got this mark scheme from mate?
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AstarAstarA
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#131
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#131
(Original post by civ1)
so how many will i lose??
It depends on whether they will allow follow through marks. They decide on the mark scheme after they get the results back to see where most students slipped up. If a lot of students make a particular mistake, then they will adjust the mark scheme to allow some non dependent marks and error carried forward answer marks. However, people found this paper quite easy so it's unlikely that they'll be generous.
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AstarAstarA
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#132
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#132
(Original post by edis1122)
guys the equation of the tangent to the circle wasn't that 3y+5x-89=0
Sorry. I hope you did fine on the rest of the questions though.
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edis1122
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#133
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#133
(Original post by AstarAstarA)
Sorry. I hope you did fine on the rest of the questions though.
have you got the actual question so i could work it out again?
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civ1
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#134
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#134
what do u guys think the grade broundaries are?
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AstarAstarA
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#135
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#135
(Original post by swiftietay99)
what "official" mark scheme then? kindly enlighten us all.
It's a troll. Leave them be otherwise they come back for more
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HaveFa1th
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#136
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#136
(Original post by samgoulden99)
It was B in terms of A
Scared the crap outta me!
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TeeEm
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#137
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#137
Was there an optimization question?
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NotNotBatman
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#138
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#138
(Original post by N^3)
Where have you got this mark scheme from mate?
I haven't got a mark scheme.
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AstarAstarA
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#139
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#139
(Original post by edis1122)
have you got the actual question so i could work it out again?
A circle with centre (7, 8) and tangent that meats the circle at (10,13). Find equation of the tangent
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joe35678
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#140
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#140
how many marks was question 8b, anyone remember ????
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