2016 May 25th Edexcel Core 2 Questions and answers. [Unofficial mark scheme] 2016 Watch

bulletman54
Badges: 5
Rep:
?
#121
Report 2 years ago
#121
(Original post by medapplicant2016)
That's what I thought, I did get 16.something though, and did work out f"(x) > 0, which usually gives you 2 marks (you don't need to sub)
If you got 16.6 then i think you may only lose 1 mark then just for not subbing for the minimum value
0
reply
rheajain
Badges: 1
Rep:
?
#122
Report 2 years ago
#122
(Original post by dididid)
the answer was b= (3a+5)/9
I did this

log 3 (3b+1/a-2) = -1
3^-1 = 3b+1/a-2
1/3= 3b+1/a-2
a-2=9b+3
a-5=9b
b=a-5/9
0
reply
UKoE Luna
Badges: 1
Rep:
?
#123
Report 2 years ago
#123
(Original post by tory88)
Is question 6 written out correctly? I get \frac{11\pi}{30}or \frac{31\pi}{30}

EDIT: Seen that there have been amendments since then. Shouldn't 8i) be \frac{a-5}{9}?

I think you're correct, this was my workings.

log_3(3b+1)-log_3(a-2)=-1

log_3(3b+1)+1=log_3(a-2)

log_3(3b+1)+log_33=log_3(a-2)

log_33(3b+1)=log_3(a-2)

3(3b+1)=a-2

9b+3=a-2

9b=a-5

b=\frac{a-5}{9}
1
reply
medapplicant2016
Badges: 7
Rep:
?
#124
Report 2 years ago
#124
(Original post by bulletman54)
If you got 16.6 then i think you may only lose 1 mark then just for not subbing for the minimum value
Cool, thanks so much!
0
reply
X_IDE_sidf
Badges: 2
Rep:
?
#125
Report Thread starter 2 years ago
#125
(Original post by UKoE Luna)
I think you're correct, this was my workings.

log_3(3b+1)-log_3(a-2)=-1

log_3(3b+1)+1=log_3(a-2)

log_3(3b+1)+log_33=log_3(a-2)

log_33(3b+1)=log_3(a-2)

3(3b+1)=a-2

9b+3=a-2

9b=a-5

b=\frac{a-5}{9}
At this point I give up, Yes you are right however the question in the exam may have been \log_3 (3b+1)-\log_3 (2a-2)=-1. It has been too long, I forget. I'll wait till I can see the paper again tomorow
0
reply
tory88
  • Study Helper
Badges: 18
Rep:
?
#126
Report 2 years ago
#126
(Original post by X_IDE_sidf)
we are on to V4 now http://docdro.id/18BTG2C

Thanks
Shouldn't question 9c) be to prove that

P=\frac{1000}{x}+\frac{x}{12}(4\  pi+36-3\sqrt{3})

I forget how to LATEX... Shouldn't the fraction outside the brackets be \frac{x}{12}
0
reply
UKoE Luna
Badges: 1
Rep:
?
#127
Report 2 years ago
#127
(Original post by X_IDE_sidf)
At this point I give up, Yes you are right however the question in the exam may have been \log_3 (3b+1)-\log_3 (2a-2)=-1. It has been too long, I forget. I'll wait till I can see the paper again tomorow
Fair enough, probably the best shout, you can only get so far with memory, but I must thank you for the awesome mark scheme!
0
reply
tory88
  • Study Helper
Badges: 18
Rep:
?
#128
Report 2 years ago
#128
(Original post by X_IDE_sidf)
At this point I give up, Yes you are right however the question in the exam may have been \log_3 (3b+1)-\log_3 (2a-2)=-1. It has been too long, I forget. I'll wait till I can see the paper again tomorow
Please quote me in if you give any corrections to the questions.
0
reply
Zakiiiii
Badges: 4
Rep:
?
#129
Report 2 years ago
#129
how many marks would b 90 UMS
0
reply
dadawdawd
Badges: 0
Rep:
?
#130
Report 2 years ago
#130
for question 6 b, are we supposed tto give answrs to 1 decimal place?
0
reply
HannahC-H
Badges: 1
Rep:
?
#131
Report 2 years ago
#131
(Original post by tory88)
Shouldn't question 9c) be to prove that

P=\frac{1000}{x}+\frac{x}{12}(4\  pi+36-3\sqrt{3})

I forget how to LATEX... Shouldn't the fraction outside the brackets be \frac{x}{12}
yes, you're right
0
reply
UKoE Luna
Badges: 1
Rep:
?
#132
Report 2 years ago
#132
(Original post by dadawdawd)
for question 6 b, are we supposed tto give answrs to 1 decimal place?
Pretty sure it said to give answers to 1dp yes.
0
reply
Dieselblue
Badges: 7
Rep:
?
#133
Report 2 years ago
#133
(Original post by X_IDE_sidf)
The question didn't have limits at that point, part (a) was simply \int (3x-x^{\frac{3}{2}})dx
Well then it's just +c
0
reply
Brydon hurst
Badges: 0
Rep:
?
#134
Report 2 years ago
#134
Can somebody type out the actual question 7b? I cant remember what it was and may help me to remember if i got 24.3
0
reply
Dieselblue
Badges: 7
Rep:
?
#135
Report 2 years ago
#135
(Original post by X_IDE_sidf)
u_n=ar^{n-1}
\therefore |u_9-u_{10}| = |(64)(\frac{3}{4})^{9-1}-(64)(\frac{3}{4})^{10-1}| = 1.602 (3 d.p.)
Hey guys I did exactly this in my exam, I remember writing it identically however I got the wrong answer (calculator error maybe?) Would I get the method marks but not the answer mark?
0
reply
Brydon hurst
Badges: 0
Rep:
?
#136
Report 2 years ago
#136
(Original post by Dieselblue)
Hey guys I did exactly this in my exam, I remember writing it identically however I got the wrong answer (calculator error maybe?) Would I get the method marks but not the answer mark?
I did u10 - u9 or is that wrong? You should get the method mark if it was only a calculating error.
0
reply
Dieselblue
Badges: 7
Rep:
?
#137
Report 2 years ago
#137
(Original post by Brydon hurst)
I did u10 - u9 or is that wrong? You should get the method mark if it was only a calculating error.
I did ar^(9-1)-ar^(10-1) I got -0.025 though
0
reply
Brydon hurst
Badges: 0
Rep:
?
#138
Report 2 years ago
#138
(Original post by Dieselblue)
I did ar^(9-1)-ar^(10-1) I got -0.025 though
Yeah you will definitely get method marks.
0
reply
Dieselblue
Badges: 7
Rep:
?
#139
Report 2 years ago
#139
(Original post by Brydon hurst)
Yeah you will definitely get method marks.
Ok thanks thats good to know
0
reply
obeyyy
Badges: 1
Rep:
?
#140
Report 2 years ago
#140
any ideas for grade boundaries? roughly how many marks for an a?
0
reply
X

Quick Reply

Attached files
Write a reply...
Reply
new posts
Latest
My Feed

See more of what you like on
The Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

Personalise

University open days

  • Arts University Bournemouth
    Art and Design Foundation Diploma Further education
    Sat, 25 May '19
  • SOAS University of London
    Postgraduate Open Day Postgraduate
    Wed, 29 May '19
  • University of Exeter
    Undergraduate Open Day - Penryn Campus Undergraduate
    Thu, 30 May '19

How did your AQA A-level Business Paper 1 go?

Loved the paper - Feeling positive (104)
19.01%
The paper was reasonable (275)
50.27%
Not feeling great about that exam... (109)
19.93%
It was TERRIBLE (59)
10.79%

Watched Threads

View All