How do you find the range for ---> x+1 / x-2 With a domain of x>3 ????
Basically the way I do these is by subbing in x=3, which gives (3+1)/(3-2) = 4/1 = 4, and then I sub in a really big number for example 500, which gives (500+1)/(500-2) = 1.006... From this you can see that as x tends towards infinity, f(x) tends towards 1. So the range is 1 < f(x) < 4
Np, it seems the only Q that could really throw a full marks paper is a nasty trig Q which is probably a no go area after June 2013 despite the fact that the trig on the paper, imo, was not the hardest Q.