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Maths year 11 Watch

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    (Original post by RDKGames)
    Correct number but wrong sign Notice that you are multiplying negative by a negative there so the answer must be a positive. Other than that, you have now expanded both brackets. Refer back to the Pythagorean theorem and see what you need to do with the two answers you just got.


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    (Original post by z_o_e)
    How's this?


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    -18\sqrt5 - 18\sqrt5 is not \sqrt5. The 101 is correct.
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    (Original post by RDKGames)
    -18\sqrt5 - 18\sqrt5 is not \sqrt5. The 101 is correct.
    So is that it,

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    (Original post by z_o_e)
    So is that it,

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    Well no, I just said one of your calculations is wrong.
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    (Original post by RDKGames)
    Well no, I just said one of your calculations is wrong.
    I got 36root5

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    (Original post by z_o_e)
    I got 36root5

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    Well, technically MINUS 36root5. But yeah you got there. Now continue on with the first part, nearly done.
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    (Original post by RDKGames)
    Well, technically MINUS 36root5. But yeah you got there. Now continue on with the first part, nearly done.
    I got this



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    (Original post by RDKGames)
    Well, technically MINUS 36root5. But yeah you got there. Now continue on with the first part, nearly done.


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    Nope nope nope. You are getting confused.

    You had a^2+b^2=c^2 written out.

    You worked out what a^2 and b^2 are because you expanded the required brackets for the side lengths, so just add them together. What you've done right there is (a^2)^2+(b^2)^2=c^2 which doesn't make sense. Also, don't use the calculator because it will only gives out decimals which are not asked for.
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    (Original post by RDKGames)
    Nope nope nope. You are getting confused.

    You had a^2+b^2=c^2 written out.

    You worked out what a^2 and b^2 are because you expanded the required brackets for the side lengths, so just add them together. What you've done right there is (a^2)^2+(b^2)^2=c^2 which doesn't make sense. Also, don't use the calculator because it will only gives out decimals which are not asked for.


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    Nope. (9+4\sqrt5)+(101-36\sqrt5)=(9+101)+(4\sqrt5-36\sqrt5) Simplify it down,
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    (Original post by RDKGames)
    Nope. (9+4\sqrt5)+(101-36\sqrt5)=(9+101)+(4\sqrt5-36\sqrt5) Simplify it down,


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    Yep! So since the length of the hypotenuse, c, is followed by c^2=110-32\sqrt5, you can now find its length, and you will have it in the required form that part a asks for. State the values of a and b once you have done this.
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    (Original post by RDKGames)
    Yep! So since the length of the hypotenuse, c, is followed by c^2=110-32\sqrt5, you can now find its length, and you will have it in the required form that part a asks for. State the values of a and b once you have done this.
    I didn't quiet get that

    State the values of a and b?

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    (Original post by z_o_e)
    I didn't quiet get that

    State the values of a and b?

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    You know that c^2=110-32\sqrt5 so how can we go about finding c itself? What do we do to both sides? Once you have done this, you can tell what the values of a and b are.
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    (Original post by RDKGames)
    You know that c^2=110-32\sqrt5 so how can we go about finding c itself? What do we do to both sides? Once you have done this, you can tell what the values of a and b are.
    Divide both sides :/ not sure

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    (Original post by z_o_e)
    Divide both sides :/ not sure

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    Square root both sides.
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    (Original post by RDKGames)
    Square root both sides.


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    So since it is now in the form c=\sqrt{a-b\sqrt5} you can state what the values of a and b are.
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    (Original post by RDKGames)
    So since it is now in the form c=\sqrt{a-b\sqrt5} you can state what the values of a and b are.
    Can you give one more example similar to this just different numbers please.

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