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Maths year 11

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Original post by z_o_e
Can you give one more example similar to this just different numbers please.

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I'll post some more, but finish the question first. You've done the hard part. :smile:
Reply 1461
Original post by RDKGames
I'll post some more, but finish the question first. You've done the hard part. :smile:


Is that the percentage one?

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Original post by z_o_e
Is that the percentage one?

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Yeah move onto part b with the percentages.
Reply 1463
Original post by RDKGames
Yeah move onto part b with the percentages.


How would I do that ;/

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Original post by Lucky10
Best advice i could give DO PAST PAPERS its the best way to get better a maths. Any topics you dont get use sites like mathswatch.

I agree with this:smile:.As this is what I did and I went from a C in year 10 to an A* in year 11:h:. Mathswatch is a godsend from heaven and I owe my A* to it:smile:
Original post by z_o_e
How would I do that ;/

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Well look at what part b is asking for. You first need to find the area of the triangle before applying a certain percentage.
Reply 1466
Original post by RDKGames
Well look at what part b is asking for. You first need to find the area of the triangle before applying a certain percentage.




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No calculator please.
Reply 1468
Original post by RDKGames
No calculator please.




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Second line doesn't make sense. Try again. Expand the brackets.
Reply 1470
Original post by RDKGames
Second line doesn't make sense. Try again. Expand the brackets.


As in this way or do you mean

2 root 5 minus 18 root 5?

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Original post by z_o_e
As in this way or do you mean

2 root 5 minus 18 root 5?

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Nope. Don't tell you forgot how to expand brackets with surds...
Reply 1472
Original post by RDKGames
Nope. Don't tell you forgot how to expand brackets with surds...


Nooo I remember I was just unsure!



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Reply 1473
Original post by RDKGames
Nope. Don't tell you forgot how to expand brackets with surds...




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Yep. Collect the terms now.
Reply 1475
Original post by RDKGames
Yep. Collect the terms now.


I know it's a bit dodgy the second ones

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Reply 1476
Original post by RDKGames
Yep. Collect the terms now.


8+ 11-2 root 5?

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The 225 2 - 2 \sqrt5 is not correct, because 2×25=45 2 \times -2\sqrt5 = -4\sqrt5 , not 225 2 - 2\sqrt5

(2+5)(925)=(2×9)+(2×25)+(9×5)+(5×25)=1845+9510 (2 + \sqrt5)(9-2\sqrt5) = (2\times9)+(2\times-2\sqrt5)+(9\times\sqrt5)+(\sqrt5\times-2\sqrt5) = 18 -4\sqrt5 + 9\sqrt5 - 10

Now you need to collect like terms.
Reply 1478
Original post by K-Man_PhysCheM
The 225 2 - 2 \sqrt5 is not correct, because 2×25=45 2 \times -2\sqrt5 = -4\sqrt5 , not 225 2 - 2\sqrt5

(2+5)(925)=(2×9)+(2×25)+(9×5)+(5×25)=1845+9510 (2 + \sqrt5)(9-2\sqrt5) = (2\times9)+(2\times-2\sqrt5)+(9\times\sqrt5)+(\sqrt5\times-2\sqrt5) = 18 -4\sqrt5 + 9\sqrt5 - 10

Now you need to collect like terms.


Do I not multiply them?

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Reply 1479
Original post by K-Man_PhysCheM
The 225 2 - 2 \sqrt5 is not correct, because 2×25=45 2 \times -2\sqrt5 = -4\sqrt5 , not 225 2 - 2\sqrt5

(2+5)(925)=(2×9)+(2×25)+(9×5)+(5×25)=1845+9510 (2 + \sqrt5)(9-2\sqrt5) = (2\times9)+(2\times-2\sqrt5)+(9\times\sqrt5)+(\sqrt5\times-2\sqrt5) = 18 -4\sqrt5 + 9\sqrt5 - 10

Now you need to collect like terms.


What do you mean like terms? Do I add all the surds up from each bracket?

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