Edexcel Chemistry A2 Unit 5 ~ Wednesday 19th June 2013 (Now Closed)

the only thing that becomes part of ring is the group directly attached to it others dont really contribute electron to the pi system. Having said that with ethylbenzene the CH3 group pushes electron cloud to CH group attached to benzene so activates the ring as e- density increases

ahh okay ... thank you - I didnt know that before - *sad times*

I have answer to your question
The thing is zwitterions doesnt exist alone. Remember there is reversible reaction between amino acid and zwitterion so peptide bond forms with amino acids only as they are also present

Yeah, it makes sense now (+rep)
Thanks A LOT ... and good luck with Chem 5

yeah u have round bottom flask with the reactants in another flask u have water or something that boils at a temp lower than boiling point of phenylamine. Now the steam from this flask to the flask where there are reactants which will heat the reactants on that flask coz when the steam condenses it releases heat which will be enough to heat the reactants.
Phenylamine and water will evaporate and is condensed by the condenser since they are immiscible they would form two layers which could be separated using a separating funnel.
Phenylamine does react slightly with water so when separating using separating funnel u have to dissolve it in NaCl to reduce solubility of phenylamine in water so that u dont lose ur product and get high yield.
Hope it helped

Thank you for a very clear explanation all makes sense but when and where is the NaCL added??

Now you do

Can [Cu(NH3)6]2+ form? I've seen in most textbooks and websites that only [Cu(NH3)4]2+ can form but in Jan 2013 for the transition metals question (14, a, C) it says [Cu(NH3)6]2+ as a potential answer?

I certainly do



ATM ... I'm really bad at hydrogen environments

couls someone help me out please --- i did a drawing on paint and i was wondering if anyone could tell me if im right in circling different hydrogen environewmnts in different circles ?

I certainly do



ATM ... I'm really bad at hydrogen environments

couls someone help me out please --- i did a drawing on paint and i was wondering if anyone could tell me if im right in circling different hydrogen environewmnts in different circles ?

I certainly do



ATM ... I'm really bad at hydrogen environments

couls someone help me out please --- i did a drawing on paint and i was wondering if anyone could tell me if im right in circling different hydrogen environewmnts in different circles ?

Looks right to me.

Can [Cu(NH3)6]2+ form? I've seen in most textbooks and websites that only [Cu(NH3)4]2+ can form but in Jan 2013 for the transition metals question (14, a, C) it says [Cu(NH3)6]2+ as a potential answer?

In theory it can but only doesn't because the ammonia Ligands are slightly bigger than water Ligands so they can't fit around the Cu if there's 6.

I think there are only 3 hydrogen environment. One on each of those methyl group one on C next to methyl group on both side and another is all H in those CH2 group after CH3CH2 on both side

Looks right to me.

As far as I remember, the three CH2 environments in the middle are all the same as they are all surrounded by a CH2 on either side so they are only counted as 1 environment

you see in the jan 2013 finAL question ... i tried your approach but i got the answer wrong


thank you all guys for your responses ... i thought the same as you guys ... it seems you all have dfifferent opinions
i am so confused :?

no there are only 3 environments. all those CH2 groups next to CH3CH2 are counted as one and two methyl on opposite end as one and H is CH2 next to methyl group on both side

Nope it does work by this way

Oh okay, are there 5 h environments then ?

but there are 2 sets of 4 sets of ch2 groups down the bottom of the molecule,... i though they were all in one h envionment but it turns out there are 2 ... i dont get why though

becuase the 4 ch2 groups are all attatched to a ch2 group and a ch group so idk