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    (Original post by RedDevil1997)
    Will I get the mark for saying the direction of the force on the pully is Southwest??
    i think you'll defo get the mark if you drew a diagram
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    how many marks was questions 8?
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    Can someone give me their opinions here...
    How many marks will I lose on question 8.. i put the answer as 1.2N but forgot to times by g right at the end. i used this answer for 8b as well so will i get method marks? I got the angle right
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    (Original post by Singh_sidhana)
    how many marks was questions 8?
    8a 7 marks
    8b 4 marks
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    (Original post by Singh_sidhana)
    how many marks was questions 8?
    12. 8 for a and 4 for b
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    (Original post by txnilxnur)
    Can someone give me their opinions here...
    How many marks will I lose on question 8.. i put the answer as 1.2N but forgot to times by g right at the end. i used this answer for 8b as well so will i get method marks? I got the angle right
    Quite a few, I imagine you lose a 3+ for the part A but for part B i only see 2 marks max
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    (Original post by txnilxnur)
    8a 7 marks
    8b 4 marks
    you sure i remember 8a being 10 marks , because i got 8 completely wrong.
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    (Original post by Hasib98)
    This was a resit for me, anyone else?
    Which do you prefer M1 or M2
    resitted this, and obs m1 becuase m2 hurts me in many ways
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    (Original post by EpicTree)
    Quite a few, I imagine you lose a 3+ for the part A but for part B i only see 2 marks max
    yeah cause all my working out was right.. and 1.2g = 11.76. hopefully I won't lose more than 3!!
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    How many marks was the moments question?
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    (Original post by Singh_sidhana)
    you sure i remember 8a being 10 marks , because i got 8 completely wrong.
    **** na I'm sure it wasn't that many... the only 10 marker was the coefficient of friction
    8b was deffo 4 marks i remember that
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    Quick question hoping someone can clear this out1) for the first question I got got 14 soemthjng degrees and I mentioned this is from the positive X AXIS or to the right People seem to have done 90+ this to get from y axis but they didn't mention so I just used X axis 2) for the coefficient of friction I got the right answer but it came out negative because I took the friction pointing UP the slope and someone said it was down the slope How much would I lose out I think it was 10 marks ?
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    If I got 66 kg and the length to go with it would I loose many marks? Correct method
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    (Original post by Georgia.C123)
    If I got 66 kg and the length to go with it would I loose many marks? Correct method
    yes
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    (Original post by NatoHeadshot)
    Quick question hoping someone can clear this out1) for the first question I got got 14 soemthjng degrees and I mentioned this is from the positive X AXIS or to the right People seem to have done 90+ this to get from y axis but they didn't mention so I just used X axis 2) for the coefficient of friction I got the right answer but it came out negative because I took the friction pointing UP the slope and someone said it was down the slope How much would I lose out I think it was 10 marks ?
    With the first question it asked for the answer as a bearing which is why you needed to add 90.
    As for the second question.. I'm not sure how many marks you'll lose maybe half?
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    how many marks do you reckon ill get?

    1. a. 104 degree
    b. p = (400+15t)i + (20t)jq = (20t)i + (800-5t)j
    c. q = 640i + 640j

    2. a. T = 20.6N
    b. I put R=15.5N but put force on scale pan by brink = 14.7N - how many marks will i get?

    3. Got everything write until the last line, so had I=mv-mu, and u=3.5, ended up doing a calc error, will that be costly?

    4. a. Correct graph
    b. T = 8.75 s

    5. μ = 0.73

    6. Found 2 equations using moments but couldn't go any further with it - how many method marks?

    7. a. -1+k=z and 1+k=3z and sub z=-1+k into 1+k=3z so 1+k=3(-1+k) which gives k=0.5 so F2 = 0.5i + 0.5j - if this is wrong then how many marks?
    b. V = 12i +5j, thus speed = 13 ms-1

    8. a. Tension = 11.76 = 12N (2sf)
    b. RF = √(11.76)^2 + (11.76)^2 = 16.6 = 17N (2sf) with a bearing of 045
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    (Original post by EpicTree)
    yes
    How many about?
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    (Original post by Georgia.C123)
    How many about?
    atleast 3
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    Grade boundary for this exam paper?

    Is there another thread with a poll or something I can compare/contrast to last year?


    100% = ?, A* = ?, A = ?, B = ?, C = ?
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    (Original post by Georgia.C123)
    How many about?
    I did the same thing.. do you remember how many it was out of ? I think it was 7, I'm saying probably 4 marks we'd lose which is annoying cause its such a silly mistake
 
 
 
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