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    (Original post by thesmallman)
    Guys question!! For proton NMR, can the H in the aldehyde group be split?? Cos I've heard from certain sources that it always remains as a singlet, but the last question on the June 2014 paper seems to suggest otherwise??

    Thank you!
    Sorry had to ask this again, but would really appreciate an answer!
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    (Original post by itsConnor_)
    I appreciate that, sorry, it's only because the exam's tomorrow I'm stressing myself out over your more complex method sry
    what wven is this about?


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    (Original post by thesmallman)
    Sorry had to ask this again, but would really appreciate an answer!
    An aldehyde H can be split

    Eg in ethanal CH3CHO, the aldehyde H would be a quartet due to the adjacent CH3 group
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    (Original post by lai812matthew)
    i hope they will at least give a formula before asking us questions about it because i cannot remember !
    Yeah, hopefully they won't be that mean! In a few past papers they actually name the monomers and you just have to draw the polymer it form
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    (Original post by thesmallman)
    Sorry had to ask this again, but would really appreciate an answer!
    I'm pretty sure it can be split. So if the aldehyde group was attached to a ch2 group then it would be a triplet.
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    (Original post by Chem1stry101)
    An aldehyde H can be split
    THANKS A LOT!!! I was lit panicking so much
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    When asked to identify what feature causes stereoisomerism, is it just any double bound in the molecule?
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    (Original post by Chem1stry101)
    An aldehyde H can be split

    Eg in ethanal CH3CHO, the aldehyde H would be a quartet due to the adjacent CH3 group
    in the data sheet, the ones with * would not be splitting in the diagram shown in exam. http://www.ocr.org.uk/Images/74947-datasheet.pdf , and aldehyde is not one of them.
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    (Original post by fannehh)
    When asked to identify what feature causes stereoisomerism, is it just any double bound in the molecule?
    and chiral carbon
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    june 2015 markscheme and paper unit 4
    Attached Images
  1. File Type: pdf F324_MS_June15.pdf (608.2 KB, 58 views)
  2. File Type: pdf F324-01 QP Jun15.pdf (531.5 KB, 51 views)
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    (Original post by lai812matthew)
    and chiral carbon
    Thanks!
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    (Original post by fannehh)
    When asked to identify what feature causes stereoisomerism, is it just any double bound in the molecule?
    Non rotation around a c=c bond as well as different substituent groups
    And optical isomerism where a carbon has 4 different substituent groups so it is chiral so forms a non superimposable mirror image
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    (Original post by Chem1stry101)
    If you have symmetry and one environment is mirrored elsewhere in the molecule, just look at one side for the splitting pattern.

    Eg if you had CH3-CH2-O-CH2-CH3 it is symmetrical. So only 2 H environments. The CH3 peak would be a triplet due to the neighbouring CH2, and the CH2 would be a quartet due the neighbouring CH3
    But just to check if you had CH3CH2CH2CH3 the CH3 would be split into a triplet but the CH2 would not be split as its symmetrical?
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    Really wish the exam was in the morning, gonna be stressing over it until 13:45
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    (Original post by yoda123)
    Really wish the exam was in the morning, gonna be stressing over it until 13:45
    I agree especially as I have two exams the next day and one on Thursday so I'm not really going to be able to revise much for the ones on wednesday
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    (Original post by yoda123)
    Really wish the exam was in the morning, gonna be stressing over it until 13:45
    same, just cba!


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    (Original post by Jehaan)
    But just to check if you had CH3CH2CH2CH3 the CH3 would be split into a triplet but the CH2 would not be split as its symmetrical?
    ch2 would split into quartet right?


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    Do u use pencil for displayed formula, skeletal, etc and do you have to use pencil
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    what do I write for bonding and structure for benzene??


    good luck guys btw
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    Can carboxylic acids be reduced by NABH4 aswell?
 
 
 
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