Maths year 11

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    (Original post by RDKGames)
    The acute angle at B.


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    Correct.
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    (Original post by RDKGames)
    Correct.
    Argh. The question says 3sf.
    So the final answer is 6.40?

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    (Original post by z_o_e)
    Argh. The question says 3sf.
    So the final answer is 6.40?

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    Yep.
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    (Original post by RDKGames)
    Yep.
    Here how's the 3sf part


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    (Original post by z_o_e)
    Here how's the 3sf part


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    Yep
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    Can someone help me on this please


    How do I work it out? Thank you

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    (Original post by z_o_e)
    Can someone help me on this please


    How do I work it out? Thank you

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    The labourer charges £12.00 per hour of work. So how much would he charge for half an hour of work? And hence, how much would he charge for one and a half hours of work?

    Then the grand total is the sum of all the final prices.
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    (Original post by K-Man_PhysCheM)
    The labourer charges £12.00 per hour of work. So how much would he charge for half an hour of work? And hence, how much would he charge for one and a half hours of work?

    Then the grand total is the sum of all the final prices.
    18

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    That's right! Now calculate the total price to be paid.
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    (Original post by RDKGames)
    Yep
    Heya can you explain this part please

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    (Original post by z_o_e)
    Heya can you explain this part please

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    You need to find how much more rice India exported than Thailand. So basically, find the difference between the two.

    9.9 \times1 0^7 - 2.05 \times 10^7

    This is the same as  (9.9-2.05) \times 10^7 = 7.85 \times 10^7
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    (Original post by K-Man_PhysCheM)
    You need to find how much more rice India exported than Thailand. So basically, find the difference between the two.

    9.9 \times1 0^7 - 2.05 \times 10^7

    This is the same as  (9.9-2.05) \times 10^7 = 7.85 \times 10^7
    What about this?


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    I need to see the first part of the question.

    You need to find the multiplier for a 10% percentage decrease, and then find how many times that multiplier must have been applied to give a value of less than £35 000.

    For a slightly different question, let's say that in January a dress cost $150, and the price decreased by 5% each month.
    The multiplier for a 5% decrease is 1 - \frac{5}{100} = 1-0.05 = 0.95

    After one month in this case, the new price of the dress is:
    £150 \times 0.95 = £142.50 (February price)

    After a second month, the new price would be:
    £142.50 \times 0.95 = £135.38 (March price)

    Say I need to find what month the price will be under $120

    £135.38 \times 0.95 = £128.61 (April)
    £128.61 \times 0.95 = £122.18 (May)
    £122.18 \times 0.95 = £116.07 (June)

    So the price of the dress is under $120 from June.


    You can apply the same to your question, but remember, first work out the correct multiplier for the 10% decrease in your question.
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    (Original post by K-Man_PhysCheM)
    I need to see the first part of the question.

    You need to find the multiplier for a 10% percentage decrease, and then find how many times that multiplier must have been applied to give a value of less than £35 000.

    For a slightly different question, let's say that in January a dress cost $150, and the price decreased by 5% each month.
    The multiplier for a 5% decrease is 1 - \frac{5}{100} = 1-0.05 = 0.95

    After one month in this case, the new price of the dress is:
    £150 \times 0.95 = £142.50 (February price)

    After a second month, the new price would be:
    £142.50 \times 0.95 = £135.38 (March price)

    Say I need to find what month the price will be under $120

    £135.38 \times 0.95 = £128.61 (April)
    £128.61 \times 0.95 = £122.18 (May)
    £122.18 \times 0.95 = £116.07 (June)

    So the price of the dress is under $120 from June.


    You can apply the same to your question, but remember, first work out the correct multiplier for the 10% decrease in your question.
    This is the first part :/ i dont get percentages.


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    (Original post by z_o_e)
    This is the first part :/ i dont get percentages.


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    If the goods are worth £50 000 in January, but they decrease by 10% in February, it means that the new price is its old price minus 10% of its old price.

    Or in other words, its new price is (100% - 10% =) 90% of its old price.

    90 percent means 90 per 100, or 90/100ths of the old price, or 0.9 times the old price.

    Hence the new price is:
     50000 \times \dfrac{90}{100} = 50000 \times 0.9 =

    You need to calculate the numerical value of that.

    We call the '0.9' the multiplier, because it is the decimal by which you multiply the original price to get the new price.


    For part (b), find how many times you need to multiply by the multiplier to get a price below £35000. (You can also solve part (b) by using algebra).
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    (Original post by K-Man_PhysCheM)
    If the goods are worth £50 000 in January, but they decrease by 10% in February, it means that the new price is its old price minus 10% of its old price.

    Or in other words, its new price is (100% - 10% =) 90% of its old price.

    90 percent means 90 per 100, or 90/100ths of the old price, or 0.9 times the old price.

    Hence the new price is:
     50000 \times \dfrac{90}{100} = 50000 \times 0.9 =

    You need to calculate the numerical value of that.

    We call the '0.9' the multiplier, because it is the decimal by which you multiply the original price to get the new price.


    For part (b), find how many times you need to multiply by the multiplier to get a price below £35000. (You can also solve part (b) by using algebra).
    Got this


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    Part (a) is correct.

    You haven't answered the question in part (b). It asks you to show that May is the month where the price of the goods is under £35000, from the initial price of £50000 in January.

    You multiply the starting price by the multiplier, then multiply that result by the multiplier again, then repeat until you get a number below £35000. Find how many times you had to do that, and hence deduce the month.
    Remember, you are already told that the answer is May, you just have to "show that" the price goes below £35000 in May.
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    (Original post by K-Man_PhysCheM)
    Part (a) is correct.

    You haven't answered the question in part (b). It asks you to show that May is the month where the price of the goods is under £35000, from the initial price of £50000 in January.

    You multiply the starting price by the multiplier, then multiply that result by the multiplier again, then repeat until you get a number below £35000. Find how many times you had to do that, and hence deduce the month.
    Remember, you are already told that the answer is May, you just have to "show that" the price goes below £35000 in May.


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