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AQA Unit 3 Mathematics 13 June 2012 - Unofficial Mark Scheme [43603H] [GCSE] Watch

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    (Original post by PrinceUpsb)
    For UMS:

    90% = A*
    80% = A
    70% = B

    and so on... always.
    I'm aware but the actual UMS score changes depending on different grade boundaries & raw marks.
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    (Original post by JDee)
    I'm aware but the actual UMS score changes depending on different grade boundaries & raw marks.
    To get a B overall = 210 UMS
    He already has 127 UMS.
    210-127= 83 UMS required on this paper for him to get a B overall.

    84/120 =70% therefore this is a B grade. Regardless of raw marks.
    I am speaking just of UMS.
    He asked 'if I get a C on this paper will I get a B overall'- the answer is yes as he could get 83/120 (69.1%) which would be a C grade, on this paper, and still get a B overall.

    See below for original quotes:
    (Original post by charliehavana)
    I really want to get a B in maths overall, but if I get a C on this paper, will I still manage to scrape a B, do you think? I have 127 "points" overall, a B for Unit 1 and a B for Unit 2.

    (Original post by PrinceUpsb)
    To get a B overall you need 83/120 marks on this paper. 84/120 marks is the lowest B you can get, so if you were to get a C on this paper it is unlikely you would get a B overall. If you get a B or higher on this paper you will definitely get a B overall
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    (Original post by PrinceUpsb)
    To get a B overall = 210 UMS
    He already has 127 UMS.
    210-127= 83 UMS required on this paper for him to get a B overall.

    84/120 =70% therefore this is a B grade. Regardless of raw marks.
    I am speaking just of UMS.
    He asked 'if I get a C on this paper will I get a B overall'- the answer is yes as he could get 83/120 (69.1%) which would be a C grade, on this paper, and still get a B overall.

    See below for original quotes:
    So, if I get a (really) high C, I could still get a B overall? (Sorry, I don't quite understand the UMS points part!)

    I'm pretty sure I could get a B on this...the more I think about the exam, the more it worries me hahah :') I presume it would need to be only a couple of marks off of a B to still get the overall B?

    Sorry for all the questions! Also, I'm a "she" :P
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    (Original post by charliehavana)
    So, if I get a (really) high C, I could still get a B overall? (Sorry, I don't quite understand the UMS points part!)

    I'm pretty sure I could get a B on this...the more I think about the exam, the more it worries me hahah :') I presume it would need to be only a couple of marks off of a B to still get the overall B?

    Sorry for all the questions! Also, I'm a "she" :P
    Sorry for the gender mixup!

    Basically, yes, it is possible for you to get a C on this and end up with a B overall. I can't tell you how many marks as I don't know how the raw marks/ UMS correlates, but I would probably guess you can only be either 1 or 2 marks below a B. If you get a B or higher on this then you will guaranteed get a B overall
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    (Original post by PrinceUpsb)
    Sorry for the gender mixup!

    Basically, yes, it is possible for you to get a C on this and end up with a B overall. I can't tell you how many marks as I don't know how the raw marks/ UMS correlates, but I would probably guess you can only be either 1 or 2 marks below a B. If you get a B or higher on this then you will guaranteed get a B overall
    Ah, got it. Thanks ever so much! Fingers crossed
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    (Original post by charliehavana)
    Ah, got it. Thanks ever so much! Fingers crossed

    To make things fair regardless of the difficulty of the paper, exam boards convert your raw marks into a 'UMS' mark. This means that someone taking a really hard test may only get 50/80 marks, whereas someone the following year may take an easy test and end up with 60/80 marks. If everyone sitting it finds it 'generally' easy, the raw marks to UMS conversion will be lowered. This means that both people would receive 100/120 UMS, for example.

    The actual paper is out of 80 total raw marks.
    This test has a total maximum possible UMS of 120.
    Depending on how hard the paper was found by students, raw marks will be converted to UMS.
    These grade boundaries are not released until day before results day, but on TSR there have been a few suggestions of possible grade boundaries...

    66/80 - 108/120 (A*)
    52/80 - 96/120 (A)
    41/80 - 84/120 (B)
    33/80 - 72/120 (C)

    As I said before, you need 83/120 (or more) on this paper to get a B overall.
    84/120 UMS marks is a B grade, meaning that 83/120 is the highest mark for a C grade. So, if you get a very high C grade it is possible for a B overall.
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    (Original post by PrinceUpsb)
    As I said before, you need 83/120 (or more) on this paper to get a B overall.
    84/120 UMS marks is a B grade, meaning that 83/120 is the highest mark for a C grade. So, if you get a very high C grade it is possible for a B overall.
    Oh, I see! Teachers talk about grade boundaries being higher or lower

    I did count through my paper once I'd finished what I could, and marked myself on what I could get (I know it's not accurate, of course!), or taking away marks/partial marks for questions I didn't answer or understand, and I remember giving myself 40-43/80. Of course it will probably be different when marked by the board, it's just a habit of mine.

    Hopefully it'll be enough. Thankyou for your help!
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    hello all i am a teacher so if u have any questions on ums i may be able to help.

    someone put up mark scheme but left out feq questionsName:  1.jpg
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    Hello, can anyone upload the actual paper, please? Thanks.
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    (Original post by naz2you)
    hello all i am a teacher so if u have any questions on ums i may be able to help.

    someone put up mark scheme but left out feq questionsName:  1.jpg
Views: 256
Size:  80.6 KBName:  2.jpg
Views: 224
Size:  85.1 KBName:  3.jpg
Views: 214
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    Hello, i would like to you to see if these could be correct.
    Question 1: (x and y perimeter)
    2x=5y

    2:2x+2y = perimeter

    3:total perimeter as x and y =14x because of subsitution. i multiplied all sides by 5, subsituted in 2x for 5y and added them together 5x+5x+2x+2x=14x
    if you can check this i would be grateful
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    (Original post by naz2you)
    hello all i am a teacher so if u have any questions on ums i may be able to help.

    someone put up mark scheme but left out feq questionsName:  1.jpg
Views: 256
Size:  80.6 KBName:  2.jpg
Views: 224
Size:  85.1 KBName:  3.jpg
Views: 214
Size:  86.7 KBName:  4.jpg
Views: 203
Size:  90.3 KB
    Pm
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    2026.doc2600.pdf

    i have attached the paper in pdf and ums guidlines.
    hope this help
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    (Original post by naz2you)
    2026.doc2600.pdf

    i have attached the paper in pdf and ums guidlines.
    hope this help
    Thanks so much for this! Great!

    Do you know what the answer is to (4)? I got 24 but someone said it's 48.

    Cheers!
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    (Original post by JDee)
    Thanks so much for this! Great!

    Do you know what the answer is to (4)? I got 24 but someone said it's 48.

    Cheers!
    48
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    Do you know what the answer is to Q5 ? ((:

    Thanks
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    You absolute STAR! Have you got the foundation paper too by any chance?

    (Original post by naz2you)
    2026.doc2600.pdf

    i have attached the paper in pdf and ums guidlines.
    hope this help
 
 
 
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