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# OCR MEI - FP1 - 14th May 2015 watch

1. (Original post by TheMarshan)
Are you sure it is z=1, I am almost 100% sure it was just the default equation multiplied through by z.

My calculator saved the equation, Z^3-7Z^2+11Z+123 Went to Z^4-7Z^3+11Z^2+123Z. Which can be factorized to Z(Z^3-7Z^2+11Z+123), so Z = 0, -3, 5+4j and 5-4j.

Correct me if I am wrong
Me and my mate nabeel got z=1 for part iv mate
lol james cos i do further maths right? also username checks out so you know it isn't me
literally no idea what you mean
3. (Original post by Darcy1)
Me and my mate nabeel got z=1 for part iv mate
Ritesh you new age battyplex
4. (Original post by jpetersgill)
Ritesh you new age battyplex
tee hee hee XD
5. Darcy1 can jump over his back door
6. (Original post by Darcy1)
Me and my mate nabeel got z=1 for part iv mate
Yeah also got z=1, as if was z(f)=(f) therefore z(f)-(f)= 0

(f) (z-1) = 0 so z=1. But I could be wrong
7. (Original post by alistairBruv)
Darcy1 can jump over his back door
lowe the beef youre better than this
8. zf(z) = f(z)
Answer is z = 1, z = -3, z = 5 - 4j and z = 5 + 4j
9. (Original post by Mathbomb)
zf(z) = f(z)
Answer is z = 1, z = -3, z = 5 - 4j and z = 5 + 4j
For the argand diagram question did you represent the argz = 0 and argz = p/4 with dotted lines or does it not matter?
10. (Original post by Darcy1)
For the argand diagram question did you represent the argz = 0 and argz = p/4 with dotted lines or does it not matter?
Solid lines, the inequalities weren't strict
11. (Original post by Mathbomb)
zf(z) = f(z)
Answer is z = 1, z = -3, z = 5 - 4j and z = 5 + 4j
+1 confirm
12. (Original post by StrangeBanana)
Solid lines, the inequalities weren't strict
Well ****

Oh well it was only 2 marks will probs get at least 1
13. (Original post by Darcy1)
Well ****

Oh well it was only 2 marks will probs get at least 1
14. What did people get as the values of p and r? And the roots to the equation?
15. (Original post by MonteVerdi123)
What did people get as the values of p and r? And the roots to the equation?
q = -7
r = 123
roots 5+/-4j -3 and 1
16. (Original post by MonteVerdi123)
What did people get as the values of p and r? And the roots to the equation?
roots were defo 5+/-4j and -3 so yeah :P I think r was 123 but you can check that with the 3 roots that are 100% correct
17. For the roots q of 8, would I get a mark for dividing the equstion by z+3 as z=-3 was a root?
18. How much will be 100UMS?
If I wrote a non strict inequality for the graph question near the asymptotes will I loose 1 or 2 marks?
19. (Original post by notebook123)
How much will be 100UMS?
If I wrote a non strict inequality for the graph question near the asymptotes will I loose 1 or 2 marks?
Usually just 1 mark unless both of the inequalities required were incorrect. Usually it hovers around 70 for full UMS but either way you should still score extremely highly. Nice job man!
20. SO worried I won't get 95 UMS now :/ ... Can't believe I read it as +j and no -j despite even writing it out at arg(z-(-1-j)). Oh my stupidity worries me sometimes

What was grade boundaries for 100 UMS , 90 UMS and 80 UMS last few years? Seems to many different ones lool

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