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    (Original post by TheMarshan)
    Are you sure it is z=1, I am almost 100% sure it was just the default equation multiplied through by z.

    My calculator saved the equation, Z^3-7Z^2+11Z+123 Went to Z^4-7Z^3+11Z^2+123Z. Which can be factorized to Z(Z^3-7Z^2+11Z+123), so Z = 0, -3, 5+4j and 5-4j.

    Correct me if I am wrong
    Me and my mate nabeel got z=1 for part iv mate
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    (Original post by adrianblazesit)
    lol james cos i do further maths right? also username checks out so you know it isn't me
    literally no idea what you mean
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    (Original post by Darcy1)
    Me and my mate nabeel got z=1 for part iv mate
    Ritesh you new age battyplex
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    (Original post by jpetersgill)
    Ritesh you new age battyplex
    tee hee hee XD
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    Darcy1 can jump over his back door
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    (Original post by Darcy1)
    Me and my mate nabeel got z=1 for part iv mate
    Yeah also got z=1, as if was z(f)=(f) therefore z(f)-(f)= 0

    (f) (z-1) = 0 so z=1. But I could be wrong
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    (Original post by alistairBruv)
    Darcy1 can jump over his back door
    lowe the beef youre better than this
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    zf(z) = f(z)
    Answer is z = 1, z = -3, z = 5 - 4j and z = 5 + 4j
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    (Original post by Mathbomb)
    zf(z) = f(z)
    Answer is z = 1, z = -3, z = 5 - 4j and z = 5 + 4j
    For the argand diagram question did you represent the argz = 0 and argz = p/4 with dotted lines or does it not matter?
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    (Original post by Darcy1)
    For the argand diagram question did you represent the argz = 0 and argz = p/4 with dotted lines or does it not matter?
    Solid lines, the inequalities weren't strict
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    (Original post by Mathbomb)
    zf(z) = f(z)
    Answer is z = 1, z = -3, z = 5 - 4j and z = 5 + 4j
    +1 confirm
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    (Original post by StrangeBanana)
    Solid lines, the inequalities weren't strict
    Well ****

    Oh well it was only 2 marks will probs get at least 1
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    (Original post by Darcy1)
    Well ****

    Oh well it was only 2 marks will probs get at least 1
    bad luck m8
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    What did people get as the values of p and r? And the roots to the equation?
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    (Original post by MonteVerdi123)
    What did people get as the values of p and r? And the roots to the equation?
    q = -7
    r = 123
    roots 5+/-4j -3 and 1
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    (Original post by MonteVerdi123)
    What did people get as the values of p and r? And the roots to the equation?
    roots were defo 5+/-4j and -3 so yeah :P I think r was 123 but you can check that with the 3 roots that are 100% correct
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    For the roots q of 8, would I get a mark for dividing the equstion by z+3 as z=-3 was a root?
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    How much will be 100UMS?
    If I wrote a non strict inequality for the graph question near the asymptotes will I loose 1 or 2 marks?
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    (Original post by notebook123)
    How much will be 100UMS?
    If I wrote a non strict inequality for the graph question near the asymptotes will I loose 1 or 2 marks?
    Usually just 1 mark unless both of the inequalities required were incorrect. Usually it hovers around 70 for full UMS but either way you should still score extremely highly. Nice job man!
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    SO worried I won't get 95 UMS now :/ ... Can't believe I read it as +j and no -j despite even writing it out at arg(z-(-1-j)). Oh my stupidity worries me sometimes

    What was grade boundaries for 100 UMS , 90 UMS and 80 UMS last few years? Seems to many different ones lool
 
 
 
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