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WJEC AS Physics PH1 May 19th 2015 watch

1. (Original post by Jonooo123)
Haha well I bet it will catch a few people out!
They'll probably put an upwards arrow. It's likely though that a lot of people thought there would be no air resistance but thankfully for them there was no 'no arrow'.
2. (Original post by Jonooo123)
Did anyone else get a resistivity along the lines of 8x10^-8 for the wire? and a drift velocity of something like 5x10^-5?
I remember getting 10^-5 for drift velocity
3. With the graff with the train. I did a tangent and I got a weird acceleration. what was the acceleration? or in other words, what was the gradient?
4. (Original post by rhungwilym)
With the graff with the train. I did a tangent and I got a weird acceleration. what was the acceleration? or in other words, what was the gradient?
0.133333333333333333333333333333 333333333333333333333333333333.. . ms^-2
5. (Original post by PrimeLime)
0.133333333333333333333333333333 333333333333333333333333333333.. . ms^-2
I think I got something smaller than that but I don't remember. I just remember making the triangle massive on the paper
6. (Original post by rhungwilym)
I think I got something smaller than that but I don't remember. I just remember making the triangle massive on the paper
yeah mine was about 0.1375 I think, I'm sure there will be loads of tolerance in the mark scheme for that bit like ±0.05, doesn't sound like a lot but in the context it is!
7. Where did 48km/h come from? I put 50 because I am a tool. Also what was the velocity of it? I think I did 50,000/60x60? Something like that?
8. (Original post by DirtyExamTables)
Where did 48km/h come from? I put 50 because I am a tool. Also what was the velocity of it? I think I did 50,000/60x60? Something like that?
Can't remember the exact values, but you divide distance travelled (300m) by their respective speeds, this gives you the time taken. Do this for both AB and BA. Then to calculate mean velocity, you divide the total distance travelled (300+300=600) by the total time taken for AB and BA, which should give you 48km
9. (Original post by thegayman)
Can't remember the exact values, but you divide distance travelled (300m) by their respective speeds, this gives you the time taken. Do this for both AB and BA. Then to calculate mean velocity, you divide the total distance travelled (300+300=600) by the total time taken for AB and BA, which should give you 48km
48km/h sorry
10. (Original post by DirtyExamTables)
Where did 48km/h come from? I put 50 because I am a tool. Also what was the velocity of it? I think I did 50,000/60x60? Something like that?
It went at 40kmh for 7.5 hours and 60 for 5 hours. (40x7.5)+(60x5) = 600
600/12.5 = 48. For the next bit velocity = 0 because the resultant displacement is zero, it ends where it started!
11. (Original post by thegayman)
Can't remember the exact values, but you divide distance travelled (300m) by their respective speeds, this gives you the time taken. Do this for both AB and BA. Then to calculate mean velocity, you divide the total distance travelled (300+300=600) by the total time taken for AB and BA, which should give you 48km
ugh. I knew 50 was too good to be true I didn't do very well. Will have to do better next year amongst all the a2 exams, otherwise I'll be working in McDonald's for the rest of my life
12. (Original post by Jonooo123)
It went at 40kmh for 7.5 hours and 60 for 5 hours. (40x7.5)+(60x5) = 600
600/12.5 = 48. For the next bit velocity = 0 because the resultant displacement is zero, it ends where it started!
oh great. I've done even worse than my already low expectations
13. (Original post by DirtyExamTables)
oh great. I've done even worse than my already low expectations
Have faith, the grade boundaries are likely to be low (I hope!!) as the paper was significantly harder than previous years
14. (Original post by thegayman)
Have faith, the grade boundaries are likely to be low (I hope!!) as the paper was significantly harder than previous years
It would be good to compile a list of all the quotes on answers people agree on. Because, so far, 4500 ohms is the only number I can recognise...
15. (Original post by DirtyExamTables)
It would be good to compile a list of all the quotes on answers people agree on. Because, so far, 4500 ohms is the only number I can recognise...
Hmm I would try but I can't remember question numbers only answers aha
16. (Original post by Jonooo123)
Hmm I would try but I can't remember question numbers only answers aha
and 4500 ohms is right
17. (Original post by Jonooo123)
and 4500 ohms is right
Yay, so far I'm on 5 marks out of 80. At one point I remember doing mgh - 0.5mv^2, that seem familiar? I know I got the next part wrong though, I forgot to use the horizontal distance given in the question
18. (Original post by DirtyExamTables)
Where did 48km/h come from? I put 50 because I am a tool. Also what was the velocity of it? I think I did 50,000/60x60? Something like that?
I did the same as you because I don't think it said the time in that particular question. it said later if I remember. in the graph.
19. (Original post by rhungwilym)
I did the same as you because I don't think it said the time in that particular question. it said later if I remember.
You have to work out the time, using time=distance travelled/speed
20. I think I did okay on the experiment question, the grasshopper one is either all right or all completely wrong, and deriving the equation I did steps of vt x a, vta x n, vtan x e, then dividing by t and cancelling the t's to get nave. Didn't remember to mention how it equalled I though.

Edit: oh and I also forgot to put ohm meters as the unit for resistivity, guaranteed that will be the question with a mark for unit

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