Turn on thread page Beta
    Offline

    2
    ReputationRep:
    (Original post by Sh4hid96)
    N2O5
    Thankyouuuuuu. Correct
    Offline

    2
    ReputationRep:
    (Original post by Ben_14)
    Thankyouuuuuu. Correct
    Also, whats was the enthalpy change for the one but last page? i think mine was around -36.6KJmol?
    Offline

    2
    ReputationRep:
    (Original post by Ser_)
    I had -417!
    I had the same.
    Offline

    2
    ReputationRep:
    (Original post by Ben_14)
    Also, whats was the enthalpy change for the one but last page? i think mine was around -36.6KJmol?
    56.something
    Offline

    2
    ReputationRep:
    (Original post by Ben_14)
    Also, whats was the enthalpy change for the one but last page? i think mine was around -36.6KJmol?
    Mine was -1.3KJmol-1 but I've just realised I put the concentration as 'n' instead of the moles!!!! Sugarrrrrr
    Offline

    16
    ReputationRep:
    (Original post by Sh4hid96)
    I got 18.9.
    I got this aswell, but rounded to 19%
    Offline

    16
    ReputationRep:
    (Original post by Ben_14)
    Also, whats was the enthalpy change for the one but last page? i think mine was around -36.6KJmol?
    I got this aswell
    Offline

    2
    ReputationRep:
    What did everyone put for the volume? I had like 0.228 something? And what was the catalyst?
    Offline

    16
    ReputationRep:
    (Original post by ZeroShun)
    I also put delta H as equal to Ef -Eb.
    I should be Eb - Ef
    Offline

    2
    ReputationRep:
    (Original post by Ser_)
    Mine was -1.3KJmol-1 but I've just realised I put the concentration as 'n' instead of the moles!!!! Sugarrrrrr
    should've been something along the lines of

    -50x4.12x6.2/0.025 (pretty sure that was the moles value)
    then divide by a 1000 to convert joules to KJ
    Offline

    2
    ReputationRep:
    (Original post by Formless)
    I should be Eb - Ef
    No it shouldnt
    Offline

    2
    ReputationRep:
    (Original post by Ben_14)
    should've been something along the lines of

    -50x4.12x6.2/0.025 (pretty sure that was the moles value)
    then divide by a 1000 to convert joules to KJ
    Don't you only use the number of moles of one of the reactants
    Offline

    2
    ReputationRep:
    What did people put as the definition for molar mass?
    Offline

    2
    ReputationRep:
    (Original post by Ser_)
    What did people put as the definition for molar mass?
    Mass of one mole of a compound
    Offline

    2
    ReputationRep:
    (Original post by Questioner1234)
    Don't you only use the number of moles of one of the reactants
    well the entire equation had a 1:1:1:1 molar ratio so the moles would remain the same. I think it you had to work out the moles for NAOH which was 0.025. Make sense?
    Offline

    16
    ReputationRep:
    (Original post by Questioner1234)
    No it shouldnt
    Actually yeah my bad that is correct i forgot that deltaH is negative in exothermic, so Eb being larger. I guess i lost a mark then, however i know i did the graph right, just forgot about darn signs
    Offline

    16
    ReputationRep:
    (Original post by Questioner1234)
    0.3something
    Yes i got the same, Thought it was a bit too small, but i knew it had to be less than 2.4dm^3 as it was <0.1moles
    Offline

    2
    ReputationRep:
    (Original post by Formless)
    Yes i got the same, Thought it was a bit too small, but i knew it had to be less than 2.4dm^3 as it was <0.1moles
    What was the compound again? 2Ca(N03)2?
    Offline

    2
    ReputationRep:
    (Original post by Ben_14)
    well the entire equation had a 1:1:1:1 molar ratio so the moles would remain the same. I think it you had to work out the moles for NAOH which was 0.025. Make sense?
    Yeah I did the exact same method and got 56 with a temp change of 6.5 and volume of 25? What did you get as your answer.
    Offline

    2
    ReputationRep:
    (Original post by Ben_14)
    What was the compound again? 2Ca(N03)2?
    Yeah
 
 
 
Reply
Submit reply
Turn on thread page Beta
Updated: August 14, 2015

3,324

students online now

800,000+

Exam discussions

Find your exam discussion here

Poll
Should predicted grades be removed from the uni application process

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reply
Hide
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.