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    So like a prat I forgot I could do De Moivres... I did it with some double angle stuff instead :facepalm:

    I didn't teach the last integral.

    Left the eq Of circle in the form r^2 not r...

    Had the answer to the roots of unity but didn't simplify

    I guess doing an all-nighter was a double edged sword for me.
    Depending on the boundaries, it could go either way.

    A*'s gone to shambles. With luck an A is still reachable
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    (Original post by lizard54142)
    Saw from your profile that you're an MEI Further Maths tutor. By any chance do you have a list of past 100UMS boundaries for this exam? And for other MEI modules as well?

    Thank you!
    Here you go (It also includes Physics).
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  1. File Type: pdf Minimum Raw Marks for Full UMS.pdf (53.6 KB, 230 views)
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    For Question 2, to find v^5 instead of raising 2 to the power 5 I accidentally raised root2 to the power 5, how many marks would I lose?
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    Well, that exam was rather nice. Annoyed at myself for putting v5=-32 and not 32j and for forgetting the +c in the integration (is that always worth a mark???). Other than that, everything went really well! 70/72 hopefully, and possibly 100UMS.
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    (Original post by SH0405)
    Here you go (It also includes Physics).
    I love you.

    PRSOM PRSOM PRSOM
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    (Original post by lizard54142)
    I love you.
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    I had no idea what it meant by the equation thing for v at the last part of question 2... But apart from that I reckon everything else was great!
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    (Original post by joey4live)
    For Question 2, to find v^5 instead of raising 2 to the power 5 I accidentally raised root2 to the power 5, how many marks would I lose?
    Possibly 2, not too sure! You would get follow through marks.
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    Kinda worried, what did people put for the show that question where u had to integrate 1/(1-x^2)?
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    (Original post by qwepoizxcmnb)
    Kinda worried, what did people put for the show that question where u had to integrate 1/(1-x^2)?
    Partial Fractions were required. From there, it was relatively simple to acquire the given result.
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    If I used double angle formula to find the cos5x identity instead of de moivres theorem how many marks would I lose? It was out of 5, got the correct answer using double angle formula but now in hindsight I think it said using de moivres theorem?
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    How would you compare the difficulty of this paper to others?
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    I've done an unofficial mark scheme on page7 btw guys
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    (Original post by SH0405)
    Partial Fractions were required. From there, it was relatively simple to acquire the given result.
    Yeah lol I just used the standard integral off the data sheet, but justified c =0, any ideas how many marks that would be? Just 1?
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    (Original post by SH0405)
    How would you compare the difficulty of this paper to others?
    I'd say similar to the easier years. Annoying cause that means grade boundaries will be high :/
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    (Original post by qwepoizxcmnb)
    Yeah lol I just used the standard integral off the data sheet, but justified c =0, any ideas how many marks that would be? Just 1?
    Not sure to be honest.
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    (Original post by qwepoizxcmnb)
    I'd say similar to the easier years. Annoying cause that means grade boundaries will be high :/
    I would say it was about average.
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    (Original post by chizz1889)
    If I used double angle formula to find the cos5x identity instead of de moivres theorem how many marks would I lose? It was out of 5, got the correct answer using double angle formula but now in hindsight I think it said using de moivres theorem?
    It did say "Using de Moivre's Theorem"

    You will either get full marks or no marks.
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    (Original post by chizz1889)
    If I used double angle formula to find the cos5x identity instead of de moivres theorem how many marks would I lose? It was out of 5, got the correct answer using double angle formula but now in hindsight I think it said using de moivres theorem?
    I think you'll lose either 4 or 5
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    (Original post by qwepoizxcmnb)
    Yeah lol I just used the standard integral off the data sheet, but justified c =0, any ideas how many marks that would be? Just 1?
    Probably 1/2, like SH0405 said you had to use partial fractions, and they almost certainly wanted you to "derive" the result rather than copy it off the sheet.
 
 
 

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