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    (Original post by Kira Yagami)
    Did people put there was an upper outlier for the box plot thing or ? 1.5 X 0.3 = 0.45 and add that to Q3 and subrtact it to Q1
    Yeah there was no lower outliers but some upper outliers
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    was the cherry question the probability that he has to pick two before he gets a cherry?
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    (Original post by alicec11)
    For the football team question the first one was 25C15 right?

    And then 13C5 * 12C7 or roughly those figures? I just want to know whether the method was right
    Yes, and then divide the second answer by first for the third part ~

    25C15 13C8 and 12C7 are the numbers iirc.
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    (Original post by Duskstar)
    That's the same I did for the first two questions - the second part was (7*6*5 + 6*5*4 + 4*3*2 + 3*2*1) / (20*19*18)
    What's this question you just referred to? I am talking about the 6 marker on A and B probabilities. Are you talking about the (A/B) and (B/A)
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    (Original post by Bobhopkins05)
    was the cherry question the probability that he has to pick two before he gets a cherry?
    The last part was the probability that he has to pick more than 2 before getting (not cherry).
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    Did people get something like 0.0406 is something for the probablity of X>= to 19 for the hypsothesis test?
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    (Original post by joshgofe)
    1/19!!! Yes!! It's just the same as one answer before(cherry 3times in a row) right?? I got that for the last question! Tell me it's right plz
    Yes, I'm pretty sure the cherry one was 1/19 (I seem to remember).
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    (Original post by Slenderman)
    What's this question you just referred to? I am talking about the 6 marker on A and B probabilities. Are you talking about the (A/B) and (B/A)
    Nope - that's the method I used for P(B), which gives what you said I think.
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    conditional probability, one was just 1?
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    (Original post by liverpool2044)
    conditional probability, one was just 1?
    Yes.
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    (Original post by Duskstar)
    The last part was the probability that he has to pick more than 2 before getting (not cherry).
    I did 1 minus (6/20 plus (6/20 x 14/20))

    would I get any marks for that
    I cant remember if I did the 1 minus or not
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    Yep, that's what I got
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    (Original post by liverpool2044)
    conditional probability, one was just 1?
    One of them was yes, because they'd have to be the same chocolates given that three are orange.
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    (Original post by Bobhopkins05)
    what was the actual question for that? How many marks was it?
    For the last question, I'll write down what I remember of it:

    20 chocolates, 7 O, 6 C, 4 X, 3 Y

    First part - 3 people pick a chocolate at random, probability:
    A: all pick O
    B: all pick the same

    Second part - P(A|B) and P(B|A)

    Third part - P(A) on two seperate occasions, same situation

    Fourth part - probability 1 person gets (not C) in more than 2 picks (with removal)

    My method is at the top of page 6 along with the question ^
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    Can someone amazing pls put up an unofficial mark scheme for this exam?? 😊👌
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    (Original post by Duskstar)
    Nope - that's the method I used for P(B), which gives what you said I think.
    Yeah it does. And for the hypothesis I did like

    Ho: p=0.78
    H1: p>0.78

    where p = is blah blah

    and this is the stupid bit. I did the binomial distribution of 19 and I did 1- that answer and got like 99.19% and said it was above 99% as it was a 1% sig test and did the next one to show the next below would be wrong. I got no critical region for the first one and I said that do not reject ho.

    On the second one I said do not reject again as my critical region was 20... obviously I know that was wrong. **** -_-
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    (Original post by ¡Muy bien!)
    Not sure about the order of questions:
    1. Electricity.
    2. Sports watched
    3. Choosing a 15 people team out of 25 for something?
    4.cards
    5. 3 dice, highest score
    7. Drug hyphothesis
    8. Chocolates
    Does anyone remember the other questions?
    I think 5 was the stem and leaf (about tourists?) and 6 was the dice PDF. The others I think are right (as well as order).
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    The Hypothesis Level value was 0.0461.

    1st Q: 0.0461 > 0.01 Accept H0 Reject H1.
    2nd Q: 0.0461 < 0.05 Accept H1 Reject H0
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    For the very last question I interpreted it as him having to pick 2 cherries, which would mean that on the third one he could either pick one that he liked or continue picking cherries (hence the more than 2)

    So I did (6/20)*(5/19) which gives 3/38, which is the answer quite a few people at my school got.

    I also have the question paper with all of my (rounded) answers on in case anyone wants to confer
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    (Original post by Bobhopkins05)
    I did 1 minus (6/20 plus (6/20 x 14/20))

    would I get any marks for that
    I cant remember if I did the 1 minus or not
    What I did was 1 - (14/20) - (6/20) * (14/19) - (6/20) * (5/19) * (14/18)

    You would get 1 or 2 marks I think (I think it was a 3-marker), depending what exactly you put down.

    I'm not 100% sure in what I did - I hope it's correct, but it's possible the third probability wasn't needed, and I haven't had time to think it through properly since the exam lol.
 
 
 
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